Problem 30
Question
Solve each equation. Check your solutions. \(|6 c-1|=0\)
Step-by-Step Solution
Verified Answer
The solution is \(c = \frac{1}{6}\).
1Step 1: Understand the Absolute Value Expression
We have the equation \(|6c - 1| = 0\). Recall that the absolute value of a number is zero only if the number itself is zero. Therefore, we need to solve the equation inside the absolute value for zero: \(6c - 1 = 0\).
2Step 2: Solve the Equation
Now solve the equation \(6c - 1 = 0\). Add 1 to both sides to isolate the term with \(c\): \[6c - 1 + 1 = 0 + 1\]This simplifies to \(6c = 1\).
3Step 3: Isolate the Variable
Divide both sides by 6 to solve for \(c\): \[c = \frac{1}{6}\]So, \(c\) is equal to \(\frac{1}{6}\).
4Step 4: Check the Solution
Substitute \(c = \frac{1}{6}\) back into the original equation to verify: \[|6 \left(\frac{1}{6}\right) - 1| = |1 - 1| = |0| = 0\]Since the left side equals the right side, \(c = \frac{1}{6}\) is indeed a solution.
Key Concepts
Equation SolvingVariable IsolationChecking Solutions
Equation Solving
When we encounter an equation, like \(\left|6c - 1\right| = 0\), we need to find the value of the variable \(c\) that makes the equation true. Absolute value equations require special attention: they express that the number inside the absolute value brackets \(\left|x\right|\) is equal to zero, so the expression itself must also be zero.
- Recognize that an absolute value can only be zero if the number inside it is zero.
- Identify the expression inside the absolute value brackets.
- In this case, solve \(6c - 1 = 0\).
Variable Isolation
Isolation of a variable is crucial in solving equations effectively. Our goal is to get \(c\) by itself on one side of the equation, untouched by other numbers or variables. For the equation \(6c - 1 = 0\), do the following:
- Add 1 to both sides to simplify:
- \[6c - 1 + 1 = 0 + 1\]
- This clarifies to \(6c = 1\).
- Next, divide both sides by 6 to isolate \(c\): \[c = \frac{1}{6}\]
Checking Solutions
After calculating a potential solution, we must verify our work. Checking solutions confirms whether our calculated value satisfies the original equation. Follow these steps:
- Substitute \(c = \frac{1}{6}\) back into the original expression: \(|6(\frac{1}{6}) - 1|\).
- Calculate the inside: \(|1 - 1|\ = |0|\ = 0\).
Other exercises in this chapter
Problem 30
Identify the additive inverse and multiplicative inverse for each number. $$ -0.125 $$
View solution Problem 30
Name the property illustrated by each statement. If \(y-2=-8,\) then \(3(y-2)=3(8)\)
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Evaluate each expression if \(a=\frac{2}{5}, b=-3, c=0.5,\) and \(d=6\). \(\frac{1}{c}+\frac{1}{d}\)
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Solve each inequality. Graph the solution set on a number line. $$ \frac{|n-3|}{2}
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