Problem 30
Question
Solve each equation analytically for all complex solutions, giving exact forms in your solution set. Then, graph the left side of the equation as \(y_{1}\) in the suggested viewing window and, using the capabilities of your calculator, support the real solutions. $$\begin{aligned} &-4 x^{3}-x^{2}+4 x=0\\\ &[-4,4] \text { by }[-10,10] \end{aligned}$$
Step-by-Step Solution
Verified Answer
Solutions: \(x = 0, \frac{1+\sqrt{65}}{-8}, \frac{1-\sqrt{65}}{-8}\). Graph confirms real solutions.
1Step 1: Factor the Equation
The given equation is \(-4x^3 - x^2 + 4x = 0\). First, factor out the common factor from all terms:\(x(-4x^2 - x + 4) = 0\). This gives us the first solution: \(x = 0\).
2Step 2: Solve the Quadratic
The quadratic part of the equation is \(-4x^2 - x + 4 = 0\). We solve this using the quadratic formula: \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\), where \(a = -4\), \(b = -1\), \(c = 4\).
3Step 3: Calculate the Discriminant
Compute the discriminant \(\Delta = b^2 - 4ac\):\(\Delta = (-1)^2 - 4(-4)(4) = 1 + 64 = 65\). Since the discriminant is positive, there are two real solutions.
4Step 4: Apply the Quadratic Formula
Now plug the values into the quadratic formula:\(x = \frac{-(-1) \pm \sqrt{65}}{2(-4)}\). Simplify this to get:\(x = \frac{1 \pm \sqrt{65}}{-8}\). This results in two solutions:\(x = \frac{1 + \sqrt{65}}{-8}\) and \(x = \frac{1 - \sqrt{65}}{-8}\).
5Step 5: Write the Solution Set
Combine all solutions into a solution set:\[ x = 0, \frac{1 + \sqrt{65}}{-8}, \frac{1 - \sqrt{65}}{-8} \]. These represent all the complex numbers (real in this case) that satisfy the equation.
6Step 6: Graph the Left Side of the Equation
Graph \(y_1 = -4x^3 - x^2 + 4x\) using a graphing calculator or software in the window \([-4,4]\) by \([-10,10]\). Check intersections with the x-axis, which should occur at the real solutions derived.
7Step 7: Verify Real Solutions with Calculator
Using the calculator's graphing capabilities, confirm that all x-intercepts (real solutions) lie within the derived solutions. Ensure the parabola correctly intersects the x-axis at \(x = 0\) and the approximate decimals of \(x = \frac{1 + \sqrt{65}}{-8}\) and \(x = \frac{1 - \sqrt{65}}{-8}\).
Key Concepts
Factoring PolynomialsQuadratic FormulaGraphing Polynomials
Factoring Polynomials
Factoring is a process used to simplify polynomials by expressing them as a product of simpler polynomials. To factor the equation \[-4x^3 - x^2 + 4x = 0\], we begin by identifying any common factors in each term. In this case, each term includes the variable \(x\), which can be factored out to produce:
The polynomial \(-4x^2 - x + 4\) now remains, and to fully solve the equation, we must solve this quadratic component separately. Factoring not only simplifies polynomials but also helps in finding solutions, whether they are real or complex numbers, by breaking down complex expressions into manageable pieces.
- \(x(-4x^2 - x + 4) = 0\)
The polynomial \(-4x^2 - x + 4\) now remains, and to fully solve the equation, we must solve this quadratic component separately. Factoring not only simplifies polynomials but also helps in finding solutions, whether they are real or complex numbers, by breaking down complex expressions into manageable pieces.
Quadratic Formula
The quadratic formula is a universal method to find solutions to any quadratic equation of the form \(ax^2 + bx + c = 0\). For our equation, the quadratic formula helps to solve the quadratic polynomial \(-4x^2 - x + 4 = 0\). The formula is given by:\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]where \(a = -4\), \(b = -1\), and \(c = 4\).
The quadratic formula provides us a reliable way to find the roots of any quadratic equation, and is especially useful when simple factoring isn't possible.
- First, calculate the discriminant \(\Delta = b^2 - 4ac\):\(\Delta = 1 + 64 = 65\).
- Since \(\Delta > 0\), it indicates two distinct real solutions.
The quadratic formula provides us a reliable way to find the roots of any quadratic equation, and is especially useful when simple factoring isn't possible.
Graphing Polynomials
Graphing polynomials gives a visual representation of the solutions and behavior of polynomial equations. For the equation \(y_1 = -4x^3 - x^2 + 4x\), graphing it helps us understand where the polynomial intersects the x-axis, which corresponds to the solutions of the equation.
Here’s how you can approach graphing this polynomial:
A graph provides an intuitive understanding of behavior such as turning points and symmetry, facilitating a deeper comprehension beyond just numeric solutions.
Here’s how you can approach graphing this polynomial:
- Use graphing software or a calculator to input the equation and set the viewing window from \([-4,4]\) across the x-axis and \([-10,10]\) on the y-axis.
- Look for the x-intercepts, which indicate the places where \(y = 0\) and correlate with our solutions: \(x = 0\), \(x = \frac{1 + \sqrt{65}}{-8}\), and \(x = \frac{1 - \sqrt{65}}{-8}\).
A graph provides an intuitive understanding of behavior such as turning points and symmetry, facilitating a deeper comprehension beyond just numeric solutions.
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