Problem 30
Question
Solve and check each equation with rational exponents. $$ x^{3 / 2}=27 $$
Step-by-Step Solution
Verified Answer
The solution of the equation \( x^{3 / 2} = 27 \) is \( x = 9 \).
1Step 1: Isolate the exponential term
The first step is to isolate the term with the exponential, which in this case is already done, as the equation is \( x^{3 / 2} = 27 \).
2Step 2: Apply the square to both sides
In order to remove the exponent of \( \frac{3}{2} \), square both sides of the equation. Squaring the left side gives us \( (x^{3 / 2})^{2/3} = x \), and squaring the right side gives us \( 27^{2/3} \). This results in the new equation: \( x = 27^{2/3} \).
3Step 3: Evaluate the right side
Calculate the value of \( 27^{2/3} \). The value of \( 27^{2/3} \) is 9. Therefore, the solution for x is 9.
4Step 4: Substitute and verify
The last step is to substitute the value of x into the initial equation and verify that both sides are equal. Substituting x = 9 in the equation \( x^{3 / 2} = 27 \) gives \( 9^{3 / 2} = 27 \). After calculating, we see that indeed \( 27 = 27 \), so our solution is correct.
Key Concepts
Solving EquationsExponentsVerification of Solution
Solving Equations
Solving equations involving rational exponents can initially seem daunting, but understanding the steps makes the process straightforward. Let's begin with a clear equation: \(x^{3/2} = 27\). The key to solving this equation is to "undo" the operation that is acting on \(x\). In this instance, the exponent \(3/2\) is our focus. To isolate \(x\), use the method of exponents. Specifically, you want to apply the inverse operation associated with a rational exponent. Since \(3/2\) is our exponent, take the reciprocal of it, which is \(2/3\). When you apply \((3/2) * (2/3)\) to \(x^{3/2}\), you simplify it to \(x\). Therefore, by raising both sides of the equation to \(2/3\), we clear the exponent on \(x\):
- Result on the left: \((x^{3/2})^{2/3} = x\)
- Apply the operation on the right: \(27^{2/3}\)
Exponents
Exponents, particularly rational exponents, are crucial tools in algebra. A rational exponent, such as \(3/2\), can be expressed as a combination of roots and powers. This means \(x^{3/2}\) represents the square root followed by cubing or vice versa.Let's dissect \(x^{3/2}\). This notation implies two operations:
- First, \(x^{1/2}\) means "take the square root of \(x\)".
- Then, you apply another operation: raising the result of the root to the power of \(3\)".
Verification of Solution
Verification is a vital step after solving any equation. Checking ensures the obtained solution satisfies the original equation, affirming correctness. After solving \(x^{3/2} =27\) to find \(x = 9\), it's crucial to verify by substituting back into the initial equation: \(9^{3/2} = 27\).Breaking this down, execute:
- Calculate \(9^{1/2} \), which is the square root of 9, resulting in 3.
- Next, compute \(3^3\), which equals 27.
Other exercises in this chapter
Problem 30
In Exercises \(29-44,\) perform the indicated operations and write the result in standard form. $$\sqrt{-81}-\sqrt{-144}$$
View solution Problem 30
Solve each rational inequality in Exercises \(29-48,\) and graph the solution set on a real number line. Express each solution set in interval notation. $$ \fra
View solution Problem 30
Solve each linear inequality in Exercises 27-48 and graph the solution set on a number line. Express the solution set using interval notation. $$8 x-2 \geq 14$$
View solution Problem 30
Exercises \(17-30\) contain equations with constants in denominators. Solve each equation. $$ \frac{3 x}{5}-\frac{x-3}{2}=\frac{x+2}{3} $$
View solution