Problem 30
Question
Sketch the graph of the given equation. Label the intercepts. $$y=4 x+12$$
Step-by-Step Solution
Verified Answer
Intersects at (0,12) on y-axis and (-3,0) on x-axis.
1Step 1: Identify the equation type
The given equation, \(y = 4x + 12\), is a linear equation in slope-intercept form where \(y = mx + b\). Here, the slope \(m\) is 4 and the y-intercept \(b\) is 12.
2Step 2: Find the y-intercept
The y-intercept is the point where the line crosses the y-axis. For \(y = 4x + 12\), the y-intercept (where \(x = 0\)) is \(y = 12\). So, the coordinate of the y-intercept is (0, 12).
3Step 3: Find the x-intercept
The x-intercept is the point where the line crosses the x-axis. This happens when \(y = 0\). Setting \(y = 0\) in the equation \(0 = 4x + 12\) and solving for \(x\), we get: \[ 0 = 4x + 12 \] \[ 4x = -12 \] \[ x = -3 \]So, the coordinate of the x-intercept is (-3, 0).
4Step 4: Plot the intercepts
On a graph, plot the points (0, 12) for the y-intercept and (-3, 0) for the x-intercept.
5Step 5: Draw the line
Draw a straight line through the points (0, 12) and (-3, 0) to represent the equation \(y = 4x + 12\). This line is the graph of the given equation.
6Step 6: Label the intercepts
Clearly label the intercepts on the graph: (0, 12) is the y-intercept and (-3, 0) is the x-intercept.
Key Concepts
plotting points
plotting points
Plotting points is a straightforward yet crucial step in graphing linear equations. Start by plotting the y-intercept, as it gives a clear starting point on the graph. In our example, the y-intercept is \((0, 12)\). Next, plot the x-intercept which we found to be \((-3, 0)\). Plotting these points gives you two fixed points through which the line must pass. Draw a straight line through these points to represent the equation. Make sure to label the intercepts clearly so you can easily identify these key points on your graph. This method ensures that anyone looking at your graph can immediately understand the relationship between the variables.
Other exercises in this chapter
Problem 30
Write an equation of the line satisfying the given conditions. Line has \(y\) -intercept 3 and \(x\) -intercept 7
View solution Problem 30
Find the slope of the line passing through the given points. Round to the nearest hundredth where necessary. \((-8.65,2.8)\) and \((12.5,-3.72)\)
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In Exercises \(21-32,\) indicate which quadrant contains the given point. If a point lies on one of the coordinate axes, indicate which one. $$(8,47)$$
View solution Problem 31
Write an equation of the line satisfying the given conditions. Line has \(x\) -intercept \(-3\) and \(y\) -intercept 4
View solution