Problem 30
Question
Sketch the graph of a function \(g\) that has the following properties: (a) \(g\) is everywhere smooth (continuous with a continuous first derivative); (b) \(g(0)=0\) (c) \(g^{\prime}(x)<0\) for all \(x\); (d) \(g^{\prime \prime}(x)<0\) for \(x<0\) and \(g^{\prime \prime}(x)>0\) for \(x>0\).
Step-by-Step Solution
Verified Answer
The function is a smooth, continuously decreasing curve passing through the origin, concave down for \(x<0\) and concave up for \(x>0\).
1Step 1: Analyze property (a)
The function \(g\) is described as smooth everywhere, which means that it is continuous and has a continuous first derivative, \(g^{\prime}(x)\). Therefore, the function does not have any breaks, corners, or cusp points.
2Step 2: Understand property (b)
We know that \(g(0)=0\). This tells us that the graph of the function passes through the origin, that is the point \((0,0)\).
3Step 3: Interpret property (c)
The property \(g^{\prime}(x)<0\) indicates that \(g(x)\) is a decreasing function for all \(x\). Since the first derivative \(g^{\prime}(x)\) is negative at every point, the graph should always slope downwards as \(x\) increases.
4Step 4: Apply property (d) to the left of origin
For \(x<0\), the second derivative \(g^{\prime\prime}(x)<0\). This implies that the graph is concave down on the left side of the origin. The slope of the decreasing function becomes steeper as \(x\) approaches 0 from the left.
5Step 5: Apply property (d) to the right of origin
For \(x>0\), the second derivative \(g^{\prime\prime}(x)>0\). This means the graph is concave up on the right side. The slope of the decreasing function becomes less steep as \(x\) moves away from the origin to the right.
6Step 6: Sketch the graph
Drawing the graph, it starts at the origin \((0, 0)\). To the left of the origin, the graph arcs downward becoming steeper, indicating negative slope and negative curvature (concave down). To the right of the origin, the graph remains decreasing but curves upward, indicating negative slope and positive curvature (concave up).
Key Concepts
Continuous FunctionsDerivativesConcavityGraphing Functions
Continuous Functions
When we talk about continuous functions in calculus, we are referring to functions that do not have any interruptions in their graph. Essentially, this means the graph can be drawn without lifting your pencil from the paper.
Continuous functions are important because they allow predictions and calculations without any sudden changes or jumps. If the function is continuous, it means that:
Continuous functions are important because they allow predictions and calculations without any sudden changes or jumps. If the function is continuous, it means that:
- For every point within the domain, the function has a value.
- As you approach any value from either side, the function approaches a specific output value, known as the limit.
- This makes continuous functions smooth and predictable.
Derivatives
Derivatives in calculus measure how a function changes as its input changes. They are essentially the slope of a function at a given point.
When discussing the first derivative, which is often noted as \(g'(x)\), you are looking at how much and in what direction the function is changing. If \(g'(x) < 0\), it means the function is decreasing - the graph slopes downwards as you move to the right. This is a crucial insight when trying to understand the behavior of the graph.
When discussing the first derivative, which is often noted as \(g'(x)\), you are looking at how much and in what direction the function is changing. If \(g'(x) < 0\), it means the function is decreasing - the graph slopes downwards as you move to the right. This is a crucial insight when trying to understand the behavior of the graph.
- If \(g'(x) > 0\), the function is increasing.
- If \(g'(x) = 0\), it suggests a potential extremum or turning point.
Concavity
Concavity refers to the "curvature" of the function's graph. It's like determining if the function's graph is "smiling" or "frowning." This is defined by the second derivative, \(g''(x)\).
If \(g''(x) > 0\), the function's graph is concave up ("smiling"). This suggests that as you move from left to right, the graph becomes less steep if it is decreasing, or steeper if it is increasing. For our exercise, on the right side of the origin where \(x > 0\), the function does exactly this.
If \(g''(x) > 0\), the function's graph is concave up ("smiling"). This suggests that as you move from left to right, the graph becomes less steep if it is decreasing, or steeper if it is increasing. For our exercise, on the right side of the origin where \(x > 0\), the function does exactly this.
- If \(g''(x) < 0\), it's concave down ("frowning"), meaning the graph steepens if decreasing or lessens if increasing. The left side of our graph exhibits this behavior under \(x < 0\).
Graphing Functions
Graphing functions allow us to visualize mathematical relationships concretely. Knowing how to graph based on derivatives and concavity insights is key to understanding and predicting behavior.
For sketching a graph based on the given function properties:
For sketching a graph based on the given function properties:
- Start by plotting known points like \(g(0) = 0\), ensuring the graph passes through the origin.
- With \(g'(x) < 0\), maintain a downward slope across all \(x\).
- Incorporate concavity: to the left of the origin, the graph falls steeper (concave down), and to the right, the graph, though declining, curves upwards (concave up).
Other exercises in this chapter
Problem 29
Prove that if \(F^{\prime}(x)=0\) for all \(x\) in \((a, b)\) then there is a constant \(C\) such that \(F(x)=C\) for all \(x\) in \((a, b)\). Hint: Let \(G(x)=
View solution Problem 29
What constant acceleration will cause a car to increase its velocity from 45 to 60 miles per hour in 10 seconds?
View solution Problem 30
$$ \int\left(\pi x^{3}+1\right)^{4} 3 \pi x^{2} d x $$
View solution Problem 30
If Methuselah's parents had put \( 100\) in the bank for him at birth and he left it there, what would Methuselah have had at his death ( 969 years later) if in
View solution