Problem 30
Question
Simplify the expression. $$ \log _{6} 6^{9} $$
Step-by-Step Solution
Verified Answer
The simplified expression is 9.
1Step 1: Understand the Logarithmic Identity
Recall the logarithmic identity \( \log_b(b^x) = x \). This identity tells us that when you have a logarithm of a number that is raised to a power, and the base of the logarithm is the same as the base of the exponent, the result is simply the exponent.
2Step 2: Apply the Identity to the Expression
Notice that the expression \( \log_{6}(6^9) \) matches the identity from Step 1: the base of the logarithm (6) is the same as the base of the exponent (also 6). Therefore, according to the identity, the expression simplifies directly to the exponent.
3Step 3: Simplified Result
Applying the identity from Step 1 to the given expression \( \log_{6}(6^9) \), we find that the expression simplifies to the exponent, which is 9.
Key Concepts
Logarithmic IdentityExponentiationSimplifying Expressions
Logarithmic Identity
In the world of logarithms, simplifying expressions can often be achieved through understanding and applying key identities. One of the most important is the logarithmic identity: \( \log_b(b^x) = x \). This identity is useful whenever you have a logarithm where the base matches that of a number raised to an exponent.Let's break this down:
- The expression \( \log_b(b^x) \) means you're finding the power, \( x \), to which the base \( b \) is raised to get \( b^x \).
- If the base of the logarithm and the base of the power match, then the logarithm essentially cancels out, leaving you with the exponent \( x \).
Exponentiation
Exponentiation is a mathematical operation involving numbers called the base and the exponent. It's expressed in the form \( b^x \), where \( b \) is the base and \( x \) is the exponent.Understanding basic properties:
- When you raise a base to an exponent, you're multiplying the base by itself as many times as the exponent indicates.
- For example, \( 6^9 \) means multiplying 6 by itself 9 times.
Simplifying Expressions
The process of simplifying mathematical expressions is about making the equation easier to work with by reducing it to its most basic form. When it comes to logarithmic expressions, simplification often involves applying identities like the one we've discussed.Why simplify?:
- It makes equations easier to understand and solve.
- It reduces computational complexity, saving time and effort.
Other exercises in this chapter
Problem 29
Determine if \(f\) is one-to-one. You may want to graph \(y=f(x)\) and apply the horizontal line test. $$ f(x)=|x-1| $$
View solution Problem 29
Exercises \(11-30:\) Use \(f(x)\) and \(g(x)\) to find a formula for each expression. Identify its domain. (a) \((f+g)(x)\) (b) \((f-g)(x)\) (c) \((f g)(x)\) (d
View solution Problem 30
Find \(C\) and a so that \(f(x)=C a^{x}\) satisfies the given conditions. $$ f(0)=7 \text { and } f(-1)=1 $$
View solution Problem 30
Use a calculator to approximate each pair of expressions. Then state which property of logarithms this calculation illustrates. $$ \log \frac{\sqrt{x^{2}+4}}{\s
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