Problem 30
Question
Predict the chemical formula \(\mathrm{Na}_{\mathrm{}} \mathrm{O}_{y}\) of the compound that results from the reaction between the elements \(\mathrm{Na}\) and \(\mathrm{O}\). Answer: Na is a group IA metal and thus loses one electron to become \(\mathrm{Na}^{+} . \mathrm{O}\) is a group VIA nonmetal and so gains two electrons to become \(\mathrm{O}^{2-} .\) In order for the compound formed to be electrically neutral, the formula must be \(\mathrm{Na}_{2} \mathrm{O}\).
Step-by-Step Solution
Verified Answer
The chemical formula of the compound formed by the reaction between sodium and oxygen is \(Na_2O\).
1Step 1: 1. Identify the charge of each element and its electronic basis
Sodium (Na) is an alkali metal in Group IA and has one valence electron. Metals in Group IA tend to lose one electron to have a stable electron configuration, thus forming cations with a charge of +1 (Na⁺).
Oxygen (O) is a non-metal in Group VIA and has six valence electrons. Elements in Group VIA need two more electrons to achieve a stable configuration, forming anions with a charge of -2 (O²⁻).
2Step 2: 2. Determine the ratio necessary for the compound to be electrically neutral
In order to form an electrically neutral compound, the total positive charge and the total negative charge must balance each other out. In this case, we need two Na⁺ ions (each with a +1 charge) to balance out a single O²⁻ ion (with a -2 charge).
3Step 3: 3. Write the chemical formula
To reflect the balance of charges, the chemical formula for the compound formed by Na and O should be Na₂O. This means that two sodium atoms react with one oxygen atom to create an electrically neutral compound.
Answer: The chemical formula of the compound formed by the reaction between sodium and oxygen is Na₂O.
Key Concepts
Ionic CompoundsAlkali MetalsElectron ConfigurationChemical Reactions
Ionic Compounds
Ionic compounds are formed through the transfer of electrons from one atom to another, creating ions. This typically occurs between metals and non-metals. The metal, which loses electrons, forms a positively charged ion known as a cation. The non-metal, which gains electrons, becomes a negatively charged ion called an anion. When these oppositely charged ions come together, they form an ionic bond. This bond is the result of electrostatic attraction, which holds the ions together in a stable structure.
- An example is sodium oxide (\(\mathrm{Na}_2\mathrm{O}\)), where sodium cations (\(\mathrm{Na}^{+}\)) bond with an oxygen anion (\(\mathrm{O}^{2-}\)).
Alkali Metals
Alkali metals belong to Group IA of the periodic table and include elements like lithium, sodium, and potassium. These metals are known for their high reactivity, especially with non-metals such as oxygen and halogens. The high reactivity of alkali metals stems from their single valence electron.
- This lone electron is relatively weakly bound to the atom and is easily lost in chemical reactions.
Electron Configuration
Electron configuration is a way to denote the arrangement of electrons in an atom's electron shells. The configuration follows the order of the periodic table and the principle of minimizing energy levels. Electrons fill orbitals starting with the lowest energy levels. For example, sodium's electron configuration is \[1s^2 2s^2 2p^6 3s^1\]. This shows that sodium has a single electron in its outermost shell, which it can lose to become stable, forming a \(\mathrm{Na}^{+}\) ion. Oxygen, on the other hand, has the electron configuration \[1s^2 2s^2 2p^4\] and needs two more electrons to fill its outer shell. By gaining these electrons, oxygen becomes \(\mathrm{O}^{2-}\), completing the octet in the \(\mathrm{2p}\) orbital. This completion represents a stable electron configuration, explaining why oxygen acts as an anion in reactions.
Chemical Reactions
Chemical reactions involve the rearrangement of atoms or ions to form new substances. A common form of chemical reaction is the interaction between alkali metals and non-metals, resulting in the formation of ionic compounds. In the case of sodium and oxygen, sodium loses its outermost electron to oxygen in a direct transfer.
- This reaction results in sodium oxidizing, which means it loses electrons.
- Oxygen, on the other hand, gets reduced by gaining electrons.
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