Problem 30
Question
Multiply and simplify. All variables represent positive real numbers. $$ -\sqrt{3}(\sqrt{7}-\sqrt{15}) $$
Step-by-Step Solution
Verified Answer
The simplified expression is \\(-\sqrt{21} + 3\sqrt{5}\\).
1Step 1: Distribute the Radical Term
To multiply, distribute the term \(-\sqrt{3}\) through the expression inside the parentheses, which is \(\sqrt{7} - \sqrt{15}\). This results in \(-\sqrt{3} imes \sqrt{7}\) and \(-\sqrt{3} imes (-\sqrt{15})\).
2Step 2: Multiply the Radicals
Multiply the radicals by using the property \(\sqrt{a} \times \sqrt{b} = \sqrt{ab}\). For \(-\sqrt{3} \times \sqrt{7}\), calculate \(-\sqrt{21}\). For \(-\sqrt{3} \times (-\sqrt{15})\), which is positive because the negatives cancel, calculate \(+\sqrt{45}\).
3Step 3: Simplify the Radicals
Check if the radical expressions can be simplified. \(\sqrt{21}\) cannot be simplified further. \(\sqrt{45}\) can be simplified: as \(45 = 3^2 \times 5\), \(\sqrt{45} = \sqrt{9 \times 5} = 3\sqrt{5}\).
4Step 4: Combine the Terms
Combine the terms from Step 2 and Step 3: \(-\sqrt{21} + 3\sqrt{5}\). The expression is now simplified and does not combine further because the radicals are different.
Key Concepts
Simplifying RadicalsDistributive PropertyMultiplying Radicals
Simplifying Radicals
Simplifying radicals means reducing a radical expression to its simplest form by removing any possible square factors that are perfect squares. In radical expressions, this means breaking down the number or the variable under the square root sign into its prime factors, allowing us to simplify when possible.
For instance, in the exercise problem, we find the expression \(\sqrt{45}\). This number can be broken down into prime factors: \(45 = 3^2 \times 5\), which allows us to simplify \(\sqrt{45}\) to \(3\sqrt{5}\). This happens because \(\sqrt{9}\) simplifies to 3, which is a perfect square.
This technique not only simplifies making subsequent calculations easier but also frequently allows for situations where radicals can be added or subtracted if like radicals are present. Understanding this concept well aids in solving a wide range of algebraic problems involving roots.
For instance, in the exercise problem, we find the expression \(\sqrt{45}\). This number can be broken down into prime factors: \(45 = 3^2 \times 5\), which allows us to simplify \(\sqrt{45}\) to \(3\sqrt{5}\). This happens because \(\sqrt{9}\) simplifies to 3, which is a perfect square.
This technique not only simplifies making subsequent calculations easier but also frequently allows for situations where radicals can be added or subtracted if like radicals are present. Understanding this concept well aids in solving a wide range of algebraic problems involving roots.
Distributive Property
The distributive property is an essential algebraic rule used when you need to multiply a single term by two or more terms inside a set of parentheses. This property allows you to "distribute" the multiplication over addition or subtraction, ensuring that every term inside the brackets is multiplied by the factor outside. Use this property to expand expressions and simplify equations.
In our original exercise, we deal with the expression \(-\sqrt{3}(\sqrt{7} - \sqrt{15})\). The distributive property tells us that we must multiply \(-\sqrt{3}\) by both \(\sqrt{7}\) and \(-\sqrt{15}\). Each resulting product is calculated separately, yielding \(-\sqrt{3} \times \sqrt{7}\) and \(-\sqrt{3} \times (-\sqrt{15})\), before combining them back together.
This method is invaluable for simplifying complex expressions and equations, allowing algebraic manipulation even with the involvement of radicals.
In our original exercise, we deal with the expression \(-\sqrt{3}(\sqrt{7} - \sqrt{15})\). The distributive property tells us that we must multiply \(-\sqrt{3}\) by both \(\sqrt{7}\) and \(-\sqrt{15}\). Each resulting product is calculated separately, yielding \(-\sqrt{3} \times \sqrt{7}\) and \(-\sqrt{3} \times (-\sqrt{15})\), before combining them back together.
This method is invaluable for simplifying complex expressions and equations, allowing algebraic manipulation even with the involvement of radicals.
Multiplying Radicals
Multiplying radicals follows a simple rule: when you multiply two radical expressions, you multiply the numbers or variables inside the radicals, provided they have the same root degree. When multiplying square roots, use the property \(\sqrt{a} \times \sqrt{b} = \sqrt{ab}\).
This step was used to simplify the given expression. Taking \(-\sqrt{3} \times \sqrt{7}\), we calculated \(\sqrt{21}\). Similarly, for \(-\sqrt{3} \times (-\sqrt{15})\), the expression becomes \(\sqrt{45}\).
Keep in mind, the negatives cancel out in the second product, which maintains the product as positive. Multiplying radicals effectively reduces complex expressions, allowing simplified results whenever possible and is an essential skill in algebraic manipulation.
This step was used to simplify the given expression. Taking \(-\sqrt{3} \times \sqrt{7}\), we calculated \(\sqrt{21}\). Similarly, for \(-\sqrt{3} \times (-\sqrt{15})\), the expression becomes \(\sqrt{45}\).
Keep in mind, the negatives cancel out in the second product, which maintains the product as positive. Multiplying radicals effectively reduces complex expressions, allowing simplified results whenever possible and is an essential skill in algebraic manipulation.
Other exercises in this chapter
Problem 29
Simplify each radical expression. All variables represent positive real numbers. $$ \sqrt{242} $$
View solution Problem 29
Solve each equation. Write all proposed solutions. Cross out those that are extraneous. $$ \sqrt{9-a}-a=3 $$
View solution Problem 30
Write each number in the form a + bi. See Example 2. a. \(-43\) b. \(\sqrt{-169}\)
View solution Problem 30
The diagonal of a square parking lot is approximately \(1,414\) feet long. a. Find the length of one side of the parking lot. Round to the nearest foot. b. Find
View solution