Problem 30
Question
In Problems , let $$ \mathbf{u}=\left[\begin{array}{l} 3 \\ 4 \end{array}\right], \quad \mathbf{v}=\left[\begin{array}{l} -1 \\ -2 \end{array}\right], \quad \text { and } \quad \mathbf{w}=\left[\begin{array}{r} 1 \\ -2 \end{array}\right] $$ $$ \text { Compute } \mathbf{u}-\mathbf{v} \text { and illustrate the result graphically. } $$
Step-by-Step Solution
Verified Answer
The vector \( \mathbf{u} - \mathbf{v} \) is \( \begin{bmatrix} 4 \\ 6 \end{bmatrix} \).
1Step 1: Identify the Vectors
We are given three vectors: \( \mathbf{u} = \begin{bmatrix} 3 \ 4 \end{bmatrix} \), \( \mathbf{v} = \begin{bmatrix} -1 \ -2 \end{bmatrix} \), and \( \mathbf{w} = \begin{bmatrix} 1 \ -2 \end{bmatrix} \). Our task is to compute \( \mathbf{u} - \mathbf{v} \).
2Step 2: Compute the Difference of the Vectors
To find \( \mathbf{u} - \mathbf{v} \), subtract corresponding components of vector \( \mathbf{v} \) from vector \( \mathbf{u} \):\[\mathbf{u} - \mathbf{v} = \begin{bmatrix} 3 \ 4 \end{bmatrix} - \begin{bmatrix} -1 \ -2 \end{bmatrix} = \begin{bmatrix} 3 - (-1) \ 4 - (-2) \end{bmatrix} = \begin{bmatrix} 4 \ 6 \end{bmatrix}\]
3Step 3: Illustrate the Result Graphically
To graphically illustrate \( \mathbf{u} - \mathbf{v} \), plot the vector \( \begin{bmatrix} 4 \ 6 \end{bmatrix} \) starting from the origin on a grid. The vector ends at the point (4, 6), and its components represent its movement from the origin: 4 units in the x-direction and 6 units in the y-direction.
Key Concepts
Vector OperationsGraphical RepresentationMathematics Education
Vector Operations
Vectors are fundamental in mathematics, especially in physics and engineering, because they represent both magnitude and direction. One of the core operations involving vectors is subtraction. Vector subtraction is similar to regular subtraction but specific to vector components. For instance, if you have two vectors, \( \mathbf{u} \) and \( \mathbf{v} \), the subtraction \( \mathbf{u} - \mathbf{v} \) involves taking each component of \( \mathbf{v} \) and subtracting it from the corresponding component of \( \mathbf{u} \).
In our exercise, we are given \( \mathbf{u} = \begin{bmatrix} 3 \ 4 \end{bmatrix} \) and \( \mathbf{v} = \begin{bmatrix} -1 \ -2 \end{bmatrix} \). The subtraction \( \mathbf{u} - \mathbf{v} \) is calculated as follows:
In our exercise, we are given \( \mathbf{u} = \begin{bmatrix} 3 \ 4 \end{bmatrix} \) and \( \mathbf{v} = \begin{bmatrix} -1 \ -2 \end{bmatrix} \). The subtraction \( \mathbf{u} - \mathbf{v} \) is calculated as follows:
- Subtract the x-components: \( 3 - (-1) = 4 \)
- Subtract the y-components: \( 4 - (-2) = 6 \)
Graphical Representation
Graphical representation of vectors is a powerful way to understand vector operations visually. When subtracting vectors, like \( \mathbf{u} - \mathbf{v} \), the result can be plotted on the Cartesian coordinate system to better visualize the change.
To represent \( \begin{bmatrix} 4 \ 6 \end{bmatrix} \) graphically, start at the origin (0,0) since vector operations typically begin from this point. Move 4 units right along the x-axis, then 6 units upwards along the y-axis. Mark the endpoint at coordinates (4, 6).
The entire vector can be seen as an arrow starting from the origin and ending at this point, clearly showing the direction and the magnitude of the resultant vector. The horizontal movement signifies change along the x-axis, and the vertical represents change along the y-axis.
By graphing vector results, students can intuitively grasp how vector operations affect both direction and position. It is like painting a path of where the vector takes you.
To represent \( \begin{bmatrix} 4 \ 6 \end{bmatrix} \) graphically, start at the origin (0,0) since vector operations typically begin from this point. Move 4 units right along the x-axis, then 6 units upwards along the y-axis. Mark the endpoint at coordinates (4, 6).
The entire vector can be seen as an arrow starting from the origin and ending at this point, clearly showing the direction and the magnitude of the resultant vector. The horizontal movement signifies change along the x-axis, and the vertical represents change along the y-axis.
By graphing vector results, students can intuitively grasp how vector operations affect both direction and position. It is like painting a path of where the vector takes you.
Mathematics Education
Understanding vectors is a substantial part of mathematics education, serving as a bridge between algebra and geometry. It plays a crucial role in developing spatial reasoning and problem-solving skills.
Learners are often introduced to vectors through graphical means first, which allows them to see the practical applications and benefits of using vectors. By visualizing operations like vector subtraction, students can better comprehend concepts like force, velocity, and other vector quantities in physics.
Clear teaching methods are essential. These include breaking down the operations:
Vector mathematics is a versatile and valuable tool, equipping students with the ability to tackle a range of real-world problems.
Learners are often introduced to vectors through graphical means first, which allows them to see the practical applications and benefits of using vectors. By visualizing operations like vector subtraction, students can better comprehend concepts like force, velocity, and other vector quantities in physics.
Clear teaching methods are essential. These include breaking down the operations:
- Identifying vector components
- Performing algebraic operations on each component
- Visualizing the final vector on a coordinate plane
Vector mathematics is a versatile and valuable tool, equipping students with the ability to tackle a range of real-world problems.
Other exercises in this chapter
Problem 29
In Problems 29-34, let $$ \mathbf{u}=\left[\begin{array}{l} 3 \\ 4 \end{array}\right], \quad \mathbf{v}=\left[\begin{array}{l} -1 \\ -2 \end{array}\right], \qua
View solution Problem 30
Let \(\mathbf{x}=[2,0,-1]^{\prime}\). Find \(\mathbf{y}\) so that \(\mathbf{x}\) and \(\mathbf{y}\) are perpendicular.
View solution Problem 31
Let $$ A=\left[\begin{array}{rr} 1 & 3 \\ 0 & -2 \end{array}\right] \quad \text { and } \quad B=\left[\begin{array}{lllr} 1 & 2 & 0 & -1 \\ 2 & 1 & 3 & 0 \end{a
View solution Problem 31
Determine whether each system is overdetermined or underdetermined; then solve each system. $$ \begin{array}{r} 2 x-y=3 \\ x-y=4 \\ 3 x-y=1 \end{array} $$
View solution