Problem 30
Question
In Problems 1-30, plot the graph of each equation. Begin by checking for symmetries and be sure to find all \(x\) - and \(y\)-intercepts. $$ |x|+|y|=4 $$
Step-by-Step Solution
Verified Answer
The graph is a diamond centered at the origin with vertices at (4, 0), (-4, 0), (0, 4), and (0, -4).
1Step 1: Identify the Equation Type
The given equation is \(|x| + |y| = 4\), which involves absolute values. This type of equation represents a boundary where the total distance from the origin, in terms of both x and y axes, equals 4.
2Step 2: Check for Symmetries
The equation \(|x| + |y| = 4\) is symmetric about both the x-axis and the y-axis. This means that if you flip the graph over the x-axis or y-axis, it remains unchanged. This is confirmed because the equation is unaffected by replacing x with -x or y with -y.
3Step 3: Finding x- and y-Intercepts
To find the x-intercept, set \(y = 0\), which gives \(|x| = 4\). Solving for x, we have two solutions: \(x = 4\) and \(x = -4\). Similarly, to find the y-intercept, set \(x = 0\), which gives \(|y| = 4\). Solving for y, we also have two solutions: \(y = 4\) and \(y = -4\).
4Step 4: Identifying Lines and Region
The absolute value equation \(|x| + |y| = 4\) represents a diamond shape in the coordinate plane. We can rewrite it as a combination of lines: 1. For \(x, y \geq 0\), the line is \(x + y = 4\).2. For \(x \geq 0, y \leq 0\), the line is \(x - y = 4\).3. For \(x \leq 0, y \geq 0\), the line is \(-x + y = 4\).4. For \(x, y \leq 0\), the line is \(-x - y = 4\).
5Step 5: Plot the Points and Connect
You can now plot the intercepts: (4, 0), (-4, 0), (0, 4), and (0, -4) on a graph. Then, draw lines connecting these points. This will form a diamond shape on the coordinate plane, with the center at the origin (0, 0).
Key Concepts
Symmetry in GraphsIntercepts of EquationsPlotting Points in Coordinate Plane
Symmetry in Graphs
The concept of symmetry in graphs is a fundamental aspect when analyzing absolute value equations, like \(\|x\| + \|y\| = 4\). Symmetry simplifies understanding and graphing the equation by revealing that certain transformations—such as reflections across axes—do not alter the graph's appearance. Here, the equation is symmetric with respect to both axes. This means:
- If you reflect the graph across the x-axis, the equation remains unchanged.
- The same is true for a reflection across the y-axis.
Intercepts of Equations
Finding the intercepts of an equation is crucial in determining where the graph will cross the axes. For the equation \(\|x\| + \|y\| = 4\), we analyze the x-intercepts and y-intercepts separately.
**Finding x-intercepts** involves setting \(y = 0\). Plugging this into the equation, we get \[\|x\| + \|0\| = 4 \] which simplifies to \[\|x\| = 4. \] Solving it, we find two solutions: \(x = 4\) and \(x = -4\). These tell us that the points (4, 0) and (-4, 0) lie on the x-axis.
**Finding y-intercepts** requires setting \(x = 0\). Substituting, we get \[\|0\| + \|y\| = 4, \] or \[\|y\| = 4. \] Solving this gives us \(y = 4\) and \(y = -4\), indicating the points (0, 4) and (0, -4) lie on the y-axis.
These intercepts are essential because they provide specific points that help shape the boundary of the diamond on the graph.
**Finding x-intercepts** involves setting \(y = 0\). Plugging this into the equation, we get \[\|x\| + \|0\| = 4 \] which simplifies to \[\|x\| = 4. \] Solving it, we find two solutions: \(x = 4\) and \(x = -4\). These tell us that the points (4, 0) and (-4, 0) lie on the x-axis.
**Finding y-intercepts** requires setting \(x = 0\). Substituting, we get \[\|0\| + \|y\| = 4, \] or \[\|y\| = 4. \] Solving this gives us \(y = 4\) and \(y = -4\), indicating the points (0, 4) and (0, -4) lie on the y-axis.
These intercepts are essential because they provide specific points that help shape the boundary of the diamond on the graph.
Plotting Points in Coordinate Plane
Plotting points in the coordinate plane involves placing calculated points correctly and connecting them to visualize the entire graph. Here, the equation \(\|x\| + \|y\| = 4\) becomes a diamond shape through appropriate plotting.
This task emphasizes a crucial step in visualizing and understanding absolute value graphs. The coordinate plane offers a way to not only represent numeric relationships but also see how symmetry and intercepts create geometric shapes, enhancing the comprehension of algebraic concepts.
- After finding intercept points (4, 0), (-4, 0), (0, 4), and (0, -4), these points must be accurately placed on the coordinate plane.
- These points form the vertices of the diamond.
This task emphasizes a crucial step in visualizing and understanding absolute value graphs. The coordinate plane offers a way to not only represent numeric relationships but also see how symmetry and intercepts create geometric shapes, enhancing the comprehension of algebraic concepts.
Other exercises in this chapter
Problem 29
Find the value of each of the following; if undefined, say \(\mathrm{so}\). (a) \(0 \cdot 0\) (b) \(\frac{0}{0}\) (c) \(\frac{0}{17}\) (d) \(\frac{3}{0}\) (e) \
View solution Problem 30
In Problems \(29-34\), find an equation for each line. Then write your answer in the form \(A x+B y+C=0\). Through \((3,4)\) with slope \(-1\)
View solution Problem 30
In Problems 15-30, specify whether the given function is even, odd, or neither, and then sketch its graph. \(h(x)= \begin{cases}-x^{2}+4 & \text { if } x \leq 1
View solution Problem 30
In Problems 29-32, show that each equation is an identity. \(\sin \left(\tan ^{-1} x\right)=\frac{x}{\sqrt{1+x^{2}}}\)
View solution