Problem 30
Question
In Exercises \(29-44\), perform the indicated operations and write the result in standard form. $$ \sqrt{-81}-\sqrt{-144} $$
Step-by-Step Solution
Verified Answer
The result of \( \sqrt{-81}-\sqrt{-144} \) is \( -3i \).
1Step 1: Understand the Concept of a Complex Number
A complex number is made up of a real part and an imaginary part. It is important to understand that square root of -1 is represented by 'i', which is an imaginary number. Therefore, the square root of any negative number can be represented as the square root of the corresponding positive number, multiplied by 'i'.
2Step 2: Evaluate the Square Roots
Firstly, let's break down the negative square roots into their complex representations. The square root of -81 can be written as \( \sqrt{81} \times \sqrt{-1} \), which simplifies to \( 9i \). Similarly, the square root of -144 can be written as \( \sqrt{144} \times \sqrt{-1} \), which simplifies to \( 12i \).
3Step 3: Perform the Subtraction
As proposed in the initial operation, let's subtract these two numbers. That means \( 9i - 12i \). When you subtract these, you get \( -3i \).
Key Concepts
Imaginary NumbersOperations with Complex NumbersStandard Form of Complex Numbers
Imaginary Numbers
When venturing beyond the realm of real numbers, we encounter imaginary numbers, which have fascinated mathematicians for centuries. At their heart is the unit imaginary number, represented by the symbol 'i'. It's defined as the square root of -1, which doesn't have a solution within the set of real numbers. Imaginary numbers allow us to perform operations involving square roots of negative numbers.
For example, the square root of -81 is not possible in the set of real numbers, but in terms of imaginary numbers, it's written as \( \text{i} \times \text{i} \times 9 = 9i \). This concept also applies to other negative square roots, turning the impossible into the possible within the expanded universe of complex numbers.
For example, the square root of -81 is not possible in the set of real numbers, but in terms of imaginary numbers, it's written as \( \text{i} \times \text{i} \times 9 = 9i \). This concept also applies to other negative square roots, turning the impossible into the possible within the expanded universe of complex numbers.
Operations with Complex Numbers
Working with complex numbers involves operations such as addition, subtraction, multiplication, and division much like with real numbers. However, special rules apply when dealing with the imaginary part. For instance, to add or subtract complex numbers, we combine their real parts and imaginary parts separately.
When we come across a subtraction like \( 9i - 12i \), we treat 'i' as a common factor and simply subtract the coefficients, leading to \( -3i \). In multiplication, we use the distributive property and the fact that \( i^2 = -1 \) to simplify the expressions. Division typically requires a process called 'complex conjugation' to eliminate imaginary numbers from the denominator.
When we come across a subtraction like \( 9i - 12i \), we treat 'i' as a common factor and simply subtract the coefficients, leading to \( -3i \). In multiplication, we use the distributive property and the fact that \( i^2 = -1 \) to simplify the expressions. Division typically requires a process called 'complex conjugation' to eliminate imaginary numbers from the denominator.
Standard Form of Complex Numbers
The standard form is the most common way to express a complex number, and it is written as \( a + bi \), where 'a' is the real part and 'b' is the coefficient of the imaginary part. When we're given expressions involving \textbackslash sqrt{-81}-\textbackslash sqrt{-144}\textbackslash, our job is to simplify them into the standard form.
In the solution provided, we began with this step and simplified the square roots to obtain imaginary numbers. The final answer, \( -3i \), is already in standard form because there's no real part — the real part is effectively zero. Thus, \( -3i \) can be written as \( 0 - 3i \), adhering to the standard form convention.
In the solution provided, we began with this step and simplified the square roots to obtain imaginary numbers. The final answer, \( -3i \), is already in standard form because there's no real part — the real part is effectively zero. Thus, \( -3i \) can be written as \( 0 - 3i \), adhering to the standard form convention.
Other exercises in this chapter
Problem 29
Contain linear equations with constants in denominators. Solve equation. \(\frac{x+1}{3}=5-\frac{x+2}{7}\)
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A discount pass for a bridge costs \(\$ 30\) per month. The toll for the bridge is normally \(\$ 5.00,\) but it is reduced to \(\$ 3.50\) for people who have pu
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Solve each equation in Exercises \(15-34\) by the square root property. $$ (4 x-1)^{2}=16 $$
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Use interval notation to express solution sets and graph each solution set on a number line. Solve each linear inequality. $$8 x-2 \geq 14$$
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