Problem 30
Question
In \(24-32,\) find the exact value of each expression. $$ \tan \left(\arccos \left(-\frac{\sqrt{2}}{2}\right)\right) $$
Step-by-Step Solution
Verified Answer
The exact value is -1.
1Step 1: Identify the Angle Corresponding to the Inverse Cosine
Recognize that \( \arccos\left(-\frac{\sqrt{2}}{2}\right) \) gives the angle whose cosine is \(-\frac{\sqrt{2}}{2}\). This angle is in the second quadrant, where cosine is negative. The corresponding reference angle in the unit circle is \( \frac{3\pi}{4} \).
2Step 2: Use the Unit Circle to Find the Sine and Cosine
Recall that for the angle \( \frac{3\pi}{4} \), the coordinates on the unit circle are \( \left(-\frac{\sqrt{2}}{2}, \frac{\sqrt{2}}{2}\right) \). Here, the cosine is \(-\frac{\sqrt{2}}{2}\) and the sine is \(\frac{\sqrt{2}}{2}\).
3Step 3: Calculate the Tangent of the Angle
The tangent of an angle is the ratio of the sine to the cosine. Thus, \( \tan\left(\frac{3\pi}{4}\right) = \frac{\frac{\sqrt{2}}{2}}{-\frac{\sqrt{2}}{2}} = -1 \).
Key Concepts
Inverse Trigonometric FunctionsUnit CircleAngle Reference
Inverse Trigonometric Functions
Inverse trigonometric functions are crucial for finding angles when the values of trigonometric ratios are known. They act as the "reverse" of normal trigonometric functions, allowing us to work backward from a ratio to the angle itself.
To illustrate, \(\arccos(x)\) gives us an angle whose cosine is \(x\). Likewise, \(\arcsin(x)\) finds the angle with a given sine, and \(\arctan(x)\) provides the angle for a specified tangent ratio. Their main purpose is to simplify problems where determining angles is necessary.
Keep in mind that inverse trigonometric functions have particular ranges.
This correct recognition allows subsequent calculations to be precise.
To illustrate, \(\arccos(x)\) gives us an angle whose cosine is \(x\). Likewise, \(\arcsin(x)\) finds the angle with a given sine, and \(\arctan(x)\) provides the angle for a specified tangent ratio. Their main purpose is to simplify problems where determining angles is necessary.
Keep in mind that inverse trigonometric functions have particular ranges.
- For \(\arccos(x)\), the output (range) lies between \[0, \pi\]\ (inclusive).
- For \(\arcsin(x)\), the range is \[-\frac{\pi}{2}, \frac{\pi}{2}\].
- For \(\arctan(x)\), the range extends from \(-\frac{\pi}{2}\) to \(\frac{\pi}{2}\).
This correct recognition allows subsequent calculations to be precise.
Unit Circle
The unit circle is a fundamental concept in trigonometry linking angles to their respective trigonometric ratios. It is a circle with a radius of one, centered at the origin of a coordinate system.
Each angle on the unit circle corresponds to a point \( (\cos \theta, \sin \theta) \). This simplifies visualizing trigonometric identities and relationships. For example, the point on the circle at the angle \(\frac{3\pi}{4}\) has coordinates \(-\frac{\sqrt{2}}{2}, \frac{\sqrt{2}}{2}\).
These coordinates immediately tell us that:
Each angle on the unit circle corresponds to a point \( (\cos \theta, \sin \theta) \). This simplifies visualizing trigonometric identities and relationships. For example, the point on the circle at the angle \(\frac{3\pi}{4}\) has coordinates \(-\frac{\sqrt{2}}{2}, \frac{\sqrt{2}}{2}\).
These coordinates immediately tell us that:
- Cosine of the angle \(\theta\) is \(-\frac{\sqrt{2}}{2}\)
- Sine of the angle \(\theta\) is \(\frac{\sqrt{2}}{2}\)
Angle Reference
Angle reference is often used to determine the specific angle on the unit circle that corresponds to a given trigonometric value. This generally involves understanding which quadrants angles reside in based on the trigonometric function used.
In the context of inverse trigonometric functions, like \(\arccos\), knowing the reference angle helps to ascertain the correct quadrant and thus the correct sign of sine, cosine or tangent. For instance, in the given exercise, determining that the reference angle is \(\frac{3\pi}{4}\) helps map to the unit circle's coordinates.
Using angle reference:
In the context of inverse trigonometric functions, like \(\arccos\), knowing the reference angle helps to ascertain the correct quadrant and thus the correct sign of sine, cosine or tangent. For instance, in the given exercise, determining that the reference angle is \(\frac{3\pi}{4}\) helps map to the unit circle's coordinates.
Using angle reference:
- Decide in which quadrant your angle lies. For cosine and \(\arccos\), if your output is negative, the angle is usually in the second quadrant, \(\left(\pi/2, \pi\right)\).
- Compute or relate it to common angles. Here, the known values for \(45^\circ = \frac{\pi}{4}\) or its multiples, as shown, facilitate this.
Other exercises in this chapter
Problem 29
In \(28-37, \theta\) is the radian measure of a central angle that intercepts an arc of length \(s\) in a circle with a radius of length \(r .\) If \(\theta=4.5
View solution Problem 30
In \(26-33 :\) a. Rewrite each function value in terms of its cofunction. b. Find the exact value of the function value found in a. $$ \csc \frac{5 \pi}{6} $$
View solution Problem 30
In \(28-37, \theta\) is the radian measure of a central angle that intercepts an arc of length \(s\) in a circle with a radius of length \(r .\) If \(\theta=2.5
View solution Problem 31
In \(26-33 :\) a. Rewrite each function value in terms of its cofunction. b. Find the exact value of the function value found in a. $$ \cot \pi $$
View solution