Problem 30
Question
If \(V\) varies jointly as \(B\) and \(h\), and \(V=51\) when \(B=17\) and \(h=9\), find \(V\) when \(B=19\) and \(h=12\).
Step-by-Step Solution
Verified Answer
The new volume is 76.
1Step 1: Understand the Relationship
Since we are told that volume \(V\) varies jointly as base \(B\) and height \(h\), we can express this relationship with the equation \( V = k \, B \, h \), where \( k \) is a constant of proportionality.
2Step 2: Substitute Known Values to Find \(k\)
Given \( V = 51 \), \( B = 17 \), and \( h = 9 \), substitute these values into the equation: \( 51 = k \, (17) \, (9) \). Simplifying this, we find \( k = \frac{51}{153} = \frac{1}{3} \).
3Step 3: Substitute Values for the New Situation
Using the constant \( k = \frac{1}{3} \), find \( V \) when \( B = 19 \) and \( h = 12 \): \( V = \frac{1}{3} \, (19) \, (12) \).
4Step 4: Calculate the New Volume
Calculate \( V = \frac{1}{3} \, (19) \, (12) = \frac{1}{3} \, (228) = 76 \). Thus, the new volume is 76.
Key Concepts
Constant of ProportionalityAlgebraic EquationsDirect Variation
Constant of Proportionality
The constant of proportionality is a crucial concept in joint variation. It serves as a link between variables that vary together. In our problem, we see that the volume \( V \) varies jointly as the base \( B \) and height \( h \). This means that \( V \) can be expressed in terms of \( B \) and \( h \) using the equation \( V = k \times B \times h \). Here, \( k \) is the constant of proportionality and determines how strongly \( V \) depends on \( B \) and \( h \).
To find \( k \), we use specific values of \( V \), \( B \), and \( h \) given in the problem. By substituting \( V = 51 \), \( B = 17 \), and \( h = 9 \) into the equation, we solve for \( k \):
To find \( k \), we use specific values of \( V \), \( B \), and \( h \) given in the problem. By substituting \( V = 51 \), \( B = 17 \), and \( h = 9 \) into the equation, we solve for \( k \):
- \( 51 = k \times 17 \times 9 \)
- \( k = \frac{51}{153} = \frac{1}{3} \)
Algebraic Equations
Algebraic equations form the backbone of solving problems involving joint variation. They allow us to relate multiple variables in a precise mathematical way. In the exercise, the relationship between \( V \), \( B \), and \( h \) is captured by the equation \( V = k \times B \times h \). This equation shows that \( V \) is directly influenced by both \( B \) and \( h \) via the constant \( k \).
Because \( V \) depends on both factors, adjusting either \( B \) or \( h \) will change \( V \). This interaction is the essence of joint variation. To solve these equations, we:
Because \( V \) depends on both factors, adjusting either \( B \) or \( h \) will change \( V \). This interaction is the essence of joint variation. To solve these equations, we:
- Apply known values to find unknown constants.
- Substitute new values to calculate desired outcomes.
Direct Variation
Direct variation is a specific type of relationship where one variable changes directly with another. In joint variation, we extend this idea to multiple variables. The exercise demonstrates how volume \( V \) varies directly with both base \( B \) and height \( h \).
In direct variation, as one variable increases or decreases, the other variable does the same, assuming a constant proportionality. For example, if \( B \) or \( h \) increases, \( V \) should also increase, given that all other factors remain the same.
The joint variation formula \( V = k \times B \times h \) embodies this direct relationship for all involved variables. In problems of this nature:
In direct variation, as one variable increases or decreases, the other variable does the same, assuming a constant proportionality. For example, if \( B \) or \( h \) increases, \( V \) should also increase, given that all other factors remain the same.
The joint variation formula \( V = k \times B \times h \) embodies this direct relationship for all involved variables. In problems of this nature:
- Identify and understand how variables are linked.
- Use known values to deduce the constant of proportionality \( k \).
- Predict outcomes for different sets of values, maintaining consistency with the direct proportion concept.
Other exercises in this chapter
Problem 29
Graph each of the following linear and quadratic functions. $$f(x)=-2 x^{2}+14 x-25$$
View solution Problem 29
Specify the domain for each of the functions. $$f(s)=\sqrt{4 s-5}$$
View solution Problem 30
Find the inverse of the given function by using the "undoing process," and then verify that \(\left(f \circ f^{-1}\right)(x)=x\) and \(\left(f^{-1} \circ f\righ
View solution Problem 30
Determine the indicated functional values. (Objective 2 ) If \(f(x)=-5 x+2\) and \(g(x)=-3 x^{2}+4\), find \((f \circ g)(-2)\) and \((g \circ f)(-1)\).
View solution