Problem 30
Question
If an excited state of an atom has a lifetime of \(2.0 \times 10^{-7} \mathrm{~s},\) what is the minimum error associated with the measurement of the energy of this state?
Step-by-Step Solution
Verified Answer
The minimum error in energy measurement is \( 2.6364295 \times 10^{-28} \) J.
1Step 1: Identify Known Quantities
We are given that the lifetime of the excited state, denoted as \( \Delta t \), is \( 2.0 \times 10^{-7} \) seconds.
2Step 2: Introduce Heisenberg Uncertainty Principle
The Heisenberg Uncertainty Principle relates the uncertainty in energy \( \Delta E \) and the uncertainty in time \( \Delta t \) as follows: \[ \Delta E \cdot \Delta t \geq \frac{\hbar}{2} \] where \( \hbar \) is the reduced Planck's constant (\( \hbar = 1.0545718 \times 10^{-34} \, \text{Js} \)).
3Step 3: Rearrange Formula for Energy Uncertainty
To find the minimum error in energy, rearrange the inequality to solve for \( \Delta E \): \[ \Delta E \geq \frac{\hbar}{2 \cdot \Delta t} \]
4Step 4: Calculate Minimum Energy Uncertainty
Substitute the given values of \( \Delta t \) and \( \hbar \) into the rearranged formula: \[ \Delta E \geq \frac{1.0545718 \times 10^{-34}}{2 \times 2.0 \times 10^{-7}} \] Calculate the result to find the minimum energy uncertainty.
5Step 5: Perform Final Calculation
Compute the division: \( \Delta E \geq \frac{1.0545718 \times 10^{-34}}{4 \times 10^{-7}} \) \( \Delta E \geq 2.6364295 \times 10^{-28} \text{ J} \).
6Step 6: Minimum Error in Energy
The minimum error associated with the measurement of the energy of this state is \( 2.6364295 \times 10^{-28} \text{ J}. \)
Key Concepts
Energy UncertaintyLifetime of Excited StateReduced Planck's Constant
Energy Uncertainty
The idea of energy uncertainty is central to understanding the behavior of quantum systems. Quantum mechanics teaches us that it's impossible to precisely measure two conjugate properties, like energy and time, simultaneously. The Heisenberg Uncertainty Principle captures this idea with the equation:
\[ \Delta E \cdot \Delta t \geq \frac{\hbar}{2} \]
Here, \( \Delta E \) represents the uncertainty in energy, while \( \Delta t \) indicates the uncertainty in time. This formula essentially tells us that if the lifetime of a state is very short (\( \Delta t \) is small), then the uncertainty in energy (\( \Delta E \)) must be large. Conversely, a longer lifetime results in a lower energy uncertainty.
\[ \Delta E \cdot \Delta t \geq \frac{\hbar}{2} \]
Here, \( \Delta E \) represents the uncertainty in energy, while \( \Delta t \) indicates the uncertainty in time. This formula essentially tells us that if the lifetime of a state is very short (\( \Delta t \) is small), then the uncertainty in energy (\( \Delta E \)) must be large. Conversely, a longer lifetime results in a lower energy uncertainty.
- Uncertainty in measurement is a crucial insight of quantum mechanics.
- It reflects a fundamental limit rather than a flaw in technological precision.
Lifetime of Excited State
The lifetime of an excited state, denoted by \( \Delta t \), refers to the time span an atom remains in an excited energy state before returning to a lower energy state. This period is vital for determining the uncertainty in energy as per the Heisenberg Uncertainty Principle.
- Short lifetimes lead to greater uncertainties in energy.
- This results in spectral lines being broader, an effect seen in many optical experiments.
Reduced Planck's Constant
The reduced Planck's constant, denoted as \( \hbar \), is a fundamental constant in quantum mechanics. It is defined as \( \hbar = \frac{h}{2\pi} \), where \( h \) is the Planck's constant. The value of \( \hbar \) is approximately \( 1.0545718 \times 10^{-34} \) Js.
This constant is pivotal in the realm of quantum mechanics because it appears in various equations, including the Heisenberg Uncertainty Principle.
This constant is pivotal in the realm of quantum mechanics because it appears in various equations, including the Heisenberg Uncertainty Principle.
- It quantifies the scale at which quantum mechanical phenomena become relevant.
- \( \hbar \) is used in contexts involving wavefunction descriptions and angular momentum calculations.
Other exercises in this chapter
Problem 28
A \(1.0-\mathrm{kg}\) ball has a position uncertainty of \(0.20 \mathrm{~m}\). What is its minimum momentum uncertainty?
View solution Problem 29
An electron and a proton each have a momentum of \(3.28470 \times 10^{-30} \mathrm{~kg} \cdot \mathrm{m} / \mathrm{s} \pm 0.00025 \times 10^{-30} \mathrm{~kg} \
View solution Problem 32
What is the minimum uncertainty in the speed of an electron that is known to be somewhere between \(0.050 \mathrm{nm}\) and \(0.10 \mathrm{nm}\) from a proton?
View solution Problem 33
What is the minimum uncertainty in the position of a \(0.50-\mathrm{kg}\) ball that is known to have a speed uncertainty of \(3.0 \times 10^{-28} \mathrm{~m} /
View solution