Problem 30
Question
If \(\alpha, \beta\) be the roots of \(x^{2}+p x-q=0\) and \(\gamma, \delta\) be the roots of \(x^{2}+p x+r=0, q+r \neq 0\), then \(\frac{(\alpha-\gamma)(\alpha-\delta)}{(\beta-\gamma)(\beta-\delta)}=\) (A) 1 (B) \(q\) (C) \(r\) (D) \(q+r\)
Step-by-Step Solution
Verified Answer
The answer is (A) 1.
1Step 1: Identify the Roots
The roots of the first equation are \( \alpha \) and \( \beta \), satisfying \( \alpha + \beta = -p \) and \( \alpha \beta = -q \). The roots of the second equation are \( \gamma \) and \( \delta \), satisfying \( \gamma + \delta = -p \) and \( \gamma \delta = r \).
2Step 2: Write Expressions for the Products
Consider the expression \((\alpha - \gamma)(\alpha - \delta)\) which can be rewritten using roots properties as \( \alpha^2 - \alpha(\gamma + \delta) + \gamma\delta = \alpha^2 + p\alpha + r \).
3Step 3: Transform and Simplify
Similarly, consider \((\beta - \gamma)(\beta - \delta)\) which simplifies to \( \beta^2 - \beta(\gamma + \delta) + \gamma\delta = \beta^2 + p\beta + r \).
4Step 4: Substitute and Simplify
Substitute \( \alpha \) and \( \beta \) as roots of the first equation: \( \alpha^2 = -p\alpha + q \) and \( \beta^2 = -p\beta + q \). This leads to the expressions \( \alpha^2 + p\alpha = q \) and \( \beta^2 + p\beta = q \).
5Step 5: Plug into Main Expression
Substitute these results into the fraction: \( \frac{(q + r)}{(q + r)} = 1 \).
6Step 6: Conclusion with Answer
The calculations confirm that the expression simplifies to 1. Thus, the answer is option (A) 1.
Key Concepts
Roots of EquationsPolynomial FunctionsMathematical IdentityAlgebraic Expressions
Roots of Equations
In mathematics, particularly in algebra, the roots of equations are the values that satisfy the given equation. For a quadratic equation like \( ax^2 + bx + c = 0 \), the roots are represented as \( x = \alpha \) and \( x = \beta \). These roots reflect where the quadratic polynomial intersects the x-axis on a graph.
Understanding the properties of roots is essential:
Similarly, for the second equation with roots \( \gamma \) and \( \delta \), they satisfy \( \gamma + \delta = -p \) and \( \gamma \delta = r \). Careful analysis of these properties allows us to solve complex quadratic equations efficiently and can sometimes lead to elegant solutions, as seen in our exercise above.
Understanding the properties of roots is essential:
- The sum of the roots, \( \alpha + \beta \), is given by \( -\frac{b}{a} \).
- The product of the roots, \( \alpha \beta \), is given by \( \frac{c}{a} \).
Similarly, for the second equation with roots \( \gamma \) and \( \delta \), they satisfy \( \gamma + \delta = -p \) and \( \gamma \delta = r \). Careful analysis of these properties allows us to solve complex quadratic equations efficiently and can sometimes lead to elegant solutions, as seen in our exercise above.
Polynomial Functions
Polynomial functions are expressions made up of variables and coefficients, involving terms in the form of \( ax^n \), where \( n \) is a non-negative integer. The quadratic function, which is of degree two, is a simple form of polynomial that often arises in algebraic problems.
In this exercise:
Polynomial functions are essential because they provide a fundamental means to model and solve higher-degree equations. They are utilized in various mathematical modeling scenarios, from physics to economics, where understanding their roots and behavior can reveal valuable insights into the problem at hand.
In this exercise:
- The first polynomial function is \( x^2 + px - q \).
- The second polynomial function is \( x^2 + px + r \).
Polynomial functions are essential because they provide a fundamental means to model and solve higher-degree equations. They are utilized in various mathematical modeling scenarios, from physics to economics, where understanding their roots and behavior can reveal valuable insights into the problem at hand.
Mathematical Identity
A mathematical identity is an equation that holds true for all variables within its domain. These identities are often used to simplify and transform expressions, which can be crucial when solving equations.
In the context of quadratic equations, identities enable us to express complex relationships through simpler forms:
In the context of quadratic equations, identities enable us to express complex relationships through simpler forms:
- Consider \( (\alpha - \gamma)(\alpha - \delta) \) transforming into \( \alpha^2 + p\alpha + r \).
- This transformation uses the identity derived from the sum and product of roots.
Algebraic Expressions
Algebraic expressions, consisting of numbers, variables, and operations, form the basis of many algebra problems. These expressions can represent real-world quantities and relationships, which is why understanding them is vital.
For instance, in our exercise, expressions like \( \alpha^2 + p\alpha + r \) or \( \beta^2 + p\beta + r \) represent specific rearrangements of original equation terms:
For instance, in our exercise, expressions like \( \alpha^2 + p\alpha + r \) or \( \beta^2 + p\beta + r \) represent specific rearrangements of original equation terms:
- The initial expressions \( \alpha^2 = -p\alpha + q \) and \( \beta^2 = -p\beta + q \) play integral roles.
- These expressions help express relations in simpler terms, making the solution process methodical.
Other exercises in this chapter
Problem 27
The solution set of \((x)^{2}+(x+1)^{2}=25\), where \((x)\) is the least integer greater than or equal to \(x\), is (A) \((2,4)\) (B) \((-5,4] \cup(2,3]\) (C) \
View solution Problem 29
If \(a x^{2}+b x+6=0\) does not have two distinct real roots \(a \in R, b \in R\), then the least value of \(3 a+b\) is (A) 4 (B) \(-1\) (C) 1 (D) \(-2\)
View solution Problem 31
Number of integral solutions of \(\frac{x+2}{x^{2}+1}>\frac{1}{2}\) is (A) 0 (B) 1 (C) 2 (D) 3
View solution Problem 32
If the ratio of the roots of \(\lambda x^{2}+\mu x+v=0\) is equal to the ratio of the roots of \(x^{2}+x+1=0\), then \(\lambda, \mu, v\) are in (A) A.P. (B) G.P
View solution