Problem 30
Question
Graph the curves \(y=x^{5}\) and \(x=y(y-1)^{2}\) and find their points of intersection correct to one decimal place.
Step-by-Step Solution
Verified Answer
The curves intersect at approximately (0,0).
1Step 1: Graph the Curve \(y = x^5\)
First, we need to graph the function \(y = x^5\). This is a simple power function where the exponent is an odd number, so the curve passes through the origin and is symmetric about the origin. It rises to the right for positive values and falls to the left for negative values.
2Step 2: Graph the Curve \(x = y(y-1)^2\)
Next, graph the function \(x = y(y-1)^2\). This is a cubic equation in disguise, found by treating \(x\) as a dependent variable. Identify its critical points and shape by noticing that it will have a cubic-like shape with local minima and maxima.
3Step 3: Find Intersection Points Algebraically
To find intersection points, solve the equations \(y = x^5\) and \(x = y(y-1)^2\) simultaneously. Substitute \(y = x^5\) into the second equation: \(x = x^5(x^5-1)^2\). Simplify the equation to look for solutions using numerical or graphical methods because it is complex to solve algebraically.
4Step 4: Use Numerical Approximations
Use a numerical tool or graphing calculator to find approximate solutions to the equation \(x = x^5(x^5 - 1)^2\). Identify values of \(x\) and use them to find \(y\) by substituting back into \(y = x^5\). Ensure solutions are accurate to one decimal place.
5Step 5: Verify the Intersection Points
Check the calculated intersection points by substituting them back into both original equations to ensure they satisfy both. This step ensures that the points are indeed intersections and not just approximations that fall close to the curves only in certain areas.
Key Concepts
Graphing Power FunctionsNumerical Methods in CalculusSolving Equations AlgebraicallyCubic Equations
Graphing Power Functions
Power functions, like the curve described by \( y = x^5 \), have distinctive characteristics. These types of functions typically follow the pattern \( y = x^n \), where \( n \) is any real number. Here, the exponent \( n = 5 \) indicates an odd power. Therefore, the graph will demonstrate specific traits. Such graphs appear symmetric with respect to the origin. Often, they pass through the origin because \( x = 0 \) results in \( y = 0 \).
When graphing power functions, focus on critical points like the origin and observe the trend of the curve for positive and negative \( x \) values.
- For positive \( x \) values, the graph rises steeply.
- For negative \( x \) values, the graph falls steeply.
When graphing power functions, focus on critical points like the origin and observe the trend of the curve for positive and negative \( x \) values.
Numerical Methods in Calculus
Sometimes, equations become too complex for solving through algebra alone. This especially occurs when tackling non-linear or higher-degree equations like the one in the exercise. Numerical methods in calculus provide alternative strategies to find approximate solutions. These methods include techniques like:
- Newton's Method - A popular iterative method used to find approximate roots of a real-valued function.
- Bisection Method - Utilized to find roots by repeatedly narrowing the interval in which a root exists.
Solving Equations Algebraically
Algebraic solutions to equations involve analytical manipulation of mathematical expressions to find roots or intersections. Solving simultaneous equations like \( y = x^5 \) and \( x = y(y-1)^2 \) often begins with substituting one equation into the other to eliminate one of the variables. For example, by substituting in the exercise, we establish \( x = x^5(x^5 - 1)^2 \). However, due to the nature of such high-degree equations, algebraic solutions can be cumbersome, leading to:
- Factorization challenges.
- Difficulties in locating closed solutions.
Cubic Equations
The equation \( x = y(y-1)^2 \) fits the portfolio of cubic equations, albeit with \( x \) as a dependent variable. Such equations appear in the form \( ax^3 + bx^2 + cx + d = 0 \) when simplified based on provided values. Cubic equations may present:
Understanding the graph of a cubic function helps us visualize critical points such as local maxima and minima along with points of inflection. For the exercise, graphing plays an essential role since it instantly shows where two curves might intersect, allowing for numeric confirmation later.
- One real root and two complex roots, or
- Three real roots.
Understanding the graph of a cubic function helps us visualize critical points such as local maxima and minima along with points of inflection. For the exercise, graphing plays an essential role since it instantly shows where two curves might intersect, allowing for numeric confirmation later.
Other exercises in this chapter
Problem 30
\(29-34\) Find the area of the region that lies inside both curves. $$ r=1+\cos \theta, \quad r=1-\cos \theta $$
View solution Problem 30
\(29-48\) Sketch the curve with the given polar equation. $$r^{2}-3 r+2=0$$
View solution Problem 31
Find an equation for the conic that satisfies the given conditions. Parabola, vertex \((0,0), \quad\) focus \((0,-2)\)
View solution Problem 31
Use the parametric equations of an ellipse, \(x=a \cos \theta\) \(y=b \sin \theta, 0 \leqslant \theta \leqslant 2 \pi,\) to find the area that it encloses.
View solution