Problem 30
Question
Find the standard form of the equation of each parabola satisfying the given conditions. Focus: \((7,-1) ;\) Directrix: \(y=-9\)
Step-by-Step Solution
Verified Answer
The standard form of the equation of the parabola is \(x = 4(y + 5)^2 + 7\)
1Step 1: Calculate the vertex
The vertex of the parabola is midway between the focus and the directrix. Since the directrix is \(y = -9\) and the y-coordinate of the focus is -1, the y-coordinate of the vertex is the average of these two values. So, \(y = (-9 + (-1))/2 = -5\). The x-coordinate of the vertex is the same as the x-coordinate of the focus, which is 7. So the vertex is \( (7, -5) \)
2Step 2: Calculate the value of p
The value of p is the distance from the vertex to the focus. In this case, since the vertex and the focus have the same x-coordinate, p is simply the difference in their y-coordinates, which is \( -1 - (-5) = 4 \)
3Step 3: Write the equation of the parabola
The general form of the equation of a parabola with a horizontal axis is \(x = py^2 + h\). We found earlier that p = 4 and h = 7, so the standard form of the equation of the parabola is \(x = 4(y + 5)^2 + 7 \)
Other exercises in this chapter
Problem 29
Find the standard form of the equation of each parabola satisfying the given conditions. Focus: \((2,4) ;\) Directrix: \(x=-4\)
View solution Problem 30
Find the standard form of the equation of each ellipse satisfying the given conditions. Foci: \((0,-2),(0,2) ; x\) -intercepts: \(-2\) and 2
View solution Problem 31
Find the standard form of the equation of each ellipse satisfying the given conditions. Major axis horizontal with length \(8 ;\) length of minor axis \(=4 ;\)
View solution Problem 32
Find the standard form of the equation of each ellipse satisfying the given conditions. Major axis horizontal with length \(12 ;\) length of minor axis \(=6 ;\)
View solution