Problem 30
Question
Find the midpoint of each line segment with the given endpoints. $$ (\sqrt{50},-6) \text { and }(\sqrt{2}, 6) $$
Step-by-Step Solution
Verified Answer
The midpoint of the line segment with endpoints (\sqrt{50},-6) and (\sqrt{2}, 6) is (\sqrt{13}, 0).
1Step 1: Identify the Coordinates of the Endpoints
We are given two sets of coordinates which are the endpoints in a two-dimensional plane. The endpoints are \((\sqrt{50},-6)\) and \((\sqrt{2}, 6)\). So, \(x1= \sqrt{50}\), \(y1= -6\), \(x2= \sqrt{2}\) and \(y2= 6\).
2Step 2: Apply the Midpoint Formula
The midpoint formula is given by \((\frac{{x1+x2}}{2}, \frac{{y1+y2}}{2})\). Substituting the endpoint coordinates from Step 1 into the midpoint formula gives: \(\frac{{\sqrt{50}+\sqrt{2}}}{2}, \frac{{-6+6}}{2}\).
3Step 3: Calculate the Midpoint
Evaluate the expressions to find the coordinates of the midpoint. This provides \(\frac{{\sqrt{50}+\sqrt{2}}}{2}= \sqrt{13}\) for x and \(\frac{{-6+6}}{2}= 0\) for y. Therefore, the midpoint of the line segment with the given endpoints is at \((\sqrt{13}, 0)\) .
Key Concepts
Coordinate GeometryLine SegmentsDistance in Geometry
Coordinate Geometry
Coordinate geometry, also known as analytic geometry, is a branch of mathematics that uses algebra to study geometric properties and relationships. It's a way to represent geometric figures and analyze their properties by using a coordinate system, like the Cartesian plane.
This system allows you to plot points using pairs of numbers which are called coordinates. Each point is described by a set of coordinates \(x, y\). The horizontal axis is the x-axis, and the vertical axis is the y-axis. By plotting points and drawing lines, you can visually understand the relationship between different geometric objects.
In our exercise, we used coordinate geometry to find the midpoint of a line segment with given endpoints. Understanding the position of these points on a two-dimensional plane helps you to calculate various geometric properties, such as distance, slope, and midpoint.
This system allows you to plot points using pairs of numbers which are called coordinates. Each point is described by a set of coordinates \(x, y\). The horizontal axis is the x-axis, and the vertical axis is the y-axis. By plotting points and drawing lines, you can visually understand the relationship between different geometric objects.
In our exercise, we used coordinate geometry to find the midpoint of a line segment with given endpoints. Understanding the position of these points on a two-dimensional plane helps you to calculate various geometric properties, such as distance, slope, and midpoint.
Line Segments
A line segment is a part of a line that is bounded by two distinct endpoints. Unlike a line, a line segment does not extend indefinitely. In coordinate geometry, we define these endpoints using coordinate pairs \(x_1, y_1\) and \(x_2, y_2\).
To find the midpoint of a line segment, you take the average of the x-coordinates and the y-coordinates of the endpoints. This will give you the coordinates of a point that lies exactly in the middle of the segment.
Line segments are fundamental in geometry as they form the basis of more complex shapes and constructs. In our example, identifying the endpoints \((\sqrt{50},-6)\) and \((\sqrt{2}, 6)\) helped us to use the midpoint formula effectively to find the midpoint.
To find the midpoint of a line segment, you take the average of the x-coordinates and the y-coordinates of the endpoints. This will give you the coordinates of a point that lies exactly in the middle of the segment.
Line segments are fundamental in geometry as they form the basis of more complex shapes and constructs. In our example, identifying the endpoints \((\sqrt{50},-6)\) and \((\sqrt{2}, 6)\) helped us to use the midpoint formula effectively to find the midpoint.
Distance in Geometry
Distance in geometry refers to the measure of space between two points in a coordinate plane. The Euclidean distance formula is often used, but when dealing with midpoints, knowing how to calculate evenly split line segments is equally important.
The distance between two points \(x_1, y_1\) and \(x_2, y_2\) can be calculated using the distance formula: \(\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\\).
However, when finding midpoints, we focus on splitting the line segment into two equal parts. This involves calculating the average of the x-coordinates and y-coordinates of the endpoints, as shown in our exercise. The midpoint serves as a point equidistant from both endpoints, providing a useful reference in geometric constructions and proofs.
The distance between two points \(x_1, y_1\) and \(x_2, y_2\) can be calculated using the distance formula: \(\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\\).
However, when finding midpoints, we focus on splitting the line segment into two equal parts. This involves calculating the average of the x-coordinates and y-coordinates of the endpoints, as shown in our exercise. The midpoint serves as a point equidistant from both endpoints, providing a useful reference in geometric constructions and proofs.
Other exercises in this chapter
Problem 30
In Exercises \(21-32,\) evaluate each function at the given values of the independent variable and simplify. $$f(x)=\frac{4 x^{3}+1}{x^{3}}$$ a. \(f(2)\) b. \(f
View solution Problem 30
The functions in Exercises \(11-30\) are all one-to-one. For each function: a. Find an equation for \(f^{-1}(x),\) the inverse function. b. Verify that your equ
View solution Problem 31
Begin by graphing the absolute value function, \(f(x)=|x| .\) Then use transformations of this graph to graph the given function. $$ g(x)=-|x+4|+1 $$
View solution Problem 31
Use the given conditions to write an equation for each line in point-slope form and slope-intercept form. Passing through \((-3,-2)\) and \((3,6)\)
View solution