Problem 30
Question
Find the fifth term in the expansion of \((a b-1)^{20}\)
Step-by-Step Solution
Verified Answer
The fifth term is \(4845 (a b)^{16}\).
1Step 1: Identify the General Term of the Binomial Expansion
The general term in the expansion of \((a b - 1)^{20}\) using the binomial theorem is given by the formula: \[T_{k+1} = \binom{n}{k} (a b)^{n-k} (-1)^k\] where \(n = 20\) and \(k\) is the term index starting from 0.
2Step 2: Determine the Position of the Fifth Term
To find the fifth term, we use \(k = 4\). This is because the term position is given by \(k + 1\), so for the fifth term, \(k = 4\).
3Step 3: Plug in the Values to the Binomial Term
Substitute \(n = 20\) and \(k = 4\) into the general term formula:\[T_{5} = \binom{20}{4} (a b)^{20-4} (-1)^4\] Simplifying, we get:\[T_{5} = \binom{20}{4} (a b)^{16}\]
4Step 4: Calculate the Binomial Coefficient
Calculate \(\binom{20}{4}\):\[\binom{20}{4} = \frac{20 \times 19 \times 18 \times 17}{4 \times 3 \times 2 \times 1} = 4845\]
5Step 5: Construct the Fifth Term
Using the value from the binomial coefficient, substitute back:\[T_{5} = 4845 \times (a b)^{16}\]Therefore, the fifth term in the expansion is \(4845 (a b)^{16}\).
Key Concepts
Binomial ExpansionBinomial CoefficientCombinatoricsAlgebraic Expressions
Binomial Expansion
The binomial expansion is a way of expressing expressions raised to a power, such as \((a + b)^n\), in an expanded form. It allows you to write the original expression as a sum of terms involving coefficients, the variables in the binomial, and their exponents.
- Each term in the expansion is formed by taking the product of a binomial coefficient and the variables raised to their respective powers.
- The exponents of the variables depend on the position of the term in the expansion.
- Specifically, if we expand \((a + b)^n\), each term is of the form \(\binom{n}{k}a^{n-k}b^k\) where \(k\) ranges from 0 to \(n\).
Binomial Coefficient
The binomial coefficient is a key part of the binomial theorem and is denoted as \(\binom{n}{k}\). It is a way of selecting \(k\) items from \(n\) items without regard to the order of selection.
- The binomial coefficient is calculated using the formula \(\binom{n}{k} = \frac{n!}{k!(n-k)!}\).
- Factorials, denoted by \(!\), are used in the formula, representing the product of all positive integers up to \(n\).
- It measures how many ways you can combine different parts of the expression in each term of the binomial expansion.
Combinatorics
Combinatorics is the branch of mathematics dealing with combinations, arrangements, and counting. It provides the tools to handle selections from sets, permutations, and how items can be grouped or ordered under specific constraints.
- It is essential in understanding the binomial theorem since binomial coefficients are fundamentally combinations.
- Combinatorial methods help in determining how terms in binomial expansions are structured in terms of their order and position.
- The combination formula \(\binom{n}{k}\) arises directly from combinatorics, as it counts the number of ways \(k\) items can be chosen from \(n\).
Algebraic Expressions
Algebraic expressions involve a combination of variables, constants, and operations (addition, subtraction, multiplication, and division). These expressions form the foundation of understanding how terms are expanded in algebraic calculations like binomial expansions.
- An algebraic expression is a sum of terms, each consisting of a coefficient and a variable raised to a power.
- In the binomial expansion, each term of the expression contributes to the final polynomial result.
- Managing algebraic expressions efficiently involves sifting through variables and coefficients to identify patterns, simplifying them, or solving equations.
Other exercises in this chapter
Problem 29
23-32 me the common difference, the fifth term, the \(n\)th term, and the 100th term of the arithmetic sequence. $$25,26.5,28,29.5, \dots$$
View solution Problem 29
Find the \(n\)th term of a sequence whose first several terms are given. \(0,2,0,2,0,2, \ldots\)
View solution Problem 30
Determine the common ratio, the fifth term, and the \(n\)th term of the geometric sequence. $$ t, \frac{t^{2}}{2}, \frac{t^{3}}{4}, \frac{t^{4}}{8}, \dots $$
View solution Problem 30
23-32 me the common difference, the fifth term, the \(n\)th term, and the 100th term of the arithmetic sequence. $$15,12.3,9.6,6.9, \dots$$
View solution