Problem 30
Question
Find the exact values of \(\sin 2 \theta, \cos 2 \theta, \sin \frac{\theta}{2},\) and \(\cos \frac{\theta}{2}\) for each of the following. $$ \cos \theta=\frac{1}{6} ; 0^{\circ}<\theta<90^{\circ} $$
Step-by-Step Solution
Verified Answer
\( \sin 2\theta = \frac{\sqrt{35}}{18}, \cos 2\theta = -\frac{17}{18}, \sin \frac{\theta}{2} = \frac{\sqrt{15}}{6}, \cos \frac{\theta}{2} = \frac{\sqrt{21}}{6} \).
1Step 1: Determine \( \sin \theta \)
We know \( \cos \theta = \frac{1}{6} \). Since \( 0^{\circ}<\theta<90^{\circ} \), \( \sin \theta \) can be found using the identity \( \sin^2 \theta + \cos^2 \theta = 1 \). \( \sin^2 \theta = 1 - \left( \frac{1}{6} \right)^2 = 1 - \frac{1}{36} = \frac{35}{36} \). Therefore, \( \sin \theta = \sqrt{\frac{35}{36}} = \frac{\sqrt{35}}{6} \).
2Step 2: Compute \( \sin 2\theta \)
Use the double-angle identity for sine: \( \sin 2\theta = 2 \sin \theta \cos \theta \). Substitute the values from previous steps, \( \sin 2\theta = 2 \left( \frac{\sqrt{35}}{6} \right) \left( \frac{1}{6} \right) = \frac{2\sqrt{35}}{36} = \frac{\sqrt{35}}{18} \).
3Step 3: Compute \( \cos 2\theta \)
Use the double-angle identity for cosine: \( \cos 2\theta = 2 \cos^2 \theta - 1 \). Substitute \( \cos \theta = \frac{1}{6} \): \( \cos 2\theta = 2 \left( \frac{1}{6} \right)^2 - 1 = \frac{2}{36} - 1 = \frac{1}{18} - 1 = -\frac{17}{18} \).
4Step 4: Calculate \( \sin \frac{\theta}{2} \)
For \( \sin \frac{\theta}{2} \), use the formula \( \sin \frac{\theta}{2} = \sqrt{\frac{1 - \cos \theta}{2}} \). Substitute \( \cos \theta = \frac{1}{6} \): \( \sin \frac{\theta}{2} = \sqrt{\frac{1 - \frac{1}{6}}{2}} = \sqrt{\frac{\frac{5}{6}}{2}} = \sqrt{\frac{5}{12}} = \frac{\sqrt{15}}{6} \).
5Step 5: Calculate \( \cos \frac{\theta}{2} \)
For \( \cos \frac{\theta}{2} \), use the formula \( \cos \frac{\theta}{2} = \sqrt{\frac{1 + \cos \theta}{2}} \). Substitute \( \cos \theta = \frac{1}{6} \): \( \cos \frac{\theta}{2} = \sqrt{\frac{1 + \frac{1}{6}}{2}} = \sqrt{\frac{\frac{7}{6}}{2}} = \sqrt{\frac{7}{12}} = \frac{\sqrt{21}}{6} \).
Key Concepts
Double-Angle IdentitiesHalf-Angle IdentitiesTrigonometric Identities
Double-Angle Identities
Double-angle identities are formulas used to express trigonometric functions of double angles, like \(2\theta\), in terms of single angles \(\theta\). These identities can simplify calculations and are extremely helpful in trigonometry.
One key identity to know for sine is:
This relationship is handy for solving problems where you know \(\sin\theta\) and \(\cos\theta\) and need to calculate \(\sin 2\theta\).
Another important identity is for cosine:
Such formulas help in simplifying the trigonometric expressions and are essential for solving complex trigonometric equations.
One key identity to know for sine is:
- \( \sin 2\theta = 2\sin\theta\cos\theta \)
This relationship is handy for solving problems where you know \(\sin\theta\) and \(\cos\theta\) and need to calculate \(\sin 2\theta\).
Another important identity is for cosine:
- \( \cos 2\theta = 2\cos^2\theta - 1 \)
Such formulas help in simplifying the trigonometric expressions and are essential for solving complex trigonometric equations.
Half-Angle Identities
Half-angle identities are another set of useful trigonometric formulas. They help calculate trigonometric functions for half of an angle, such as \(\frac{\theta}{2}\), using known values of the angle \(\theta\). These identities are very helpful in calculus and geometry.
Here are the half-angle identities for sine and cosine:
This can be particularly useful when \(\cos \theta\) is more easily available, or when it would simplify your solution.
Similarly, the cosine half-angle identity lets you calculate \(\cos \frac{\theta}{2}\) from \(\cos \theta\), making it a powerful tool in trigonometry.
These formulas also determine the sign of the result based on the quadrant in which the half-angle \(\frac{\theta}{2}\) lies, ensuring accurate solutions.
Here are the half-angle identities for sine and cosine:
- \( \sin \frac{\theta}{2} = \sqrt{\frac{1 - \cos \theta}{2}} \)
- \( \cos \frac{\theta}{2} = \sqrt{\frac{1 + \cos \theta}{2}} \)
This can be particularly useful when \(\cos \theta\) is more easily available, or when it would simplify your solution.
Similarly, the cosine half-angle identity lets you calculate \(\cos \frac{\theta}{2}\) from \(\cos \theta\), making it a powerful tool in trigonometry.
These formulas also determine the sign of the result based on the quadrant in which the half-angle \(\frac{\theta}{2}\) lies, ensuring accurate solutions.
Trigonometric Identities
Trigonometric identities are equations involving trigonometric functions that are true for all angle values. They are fundamental tools that enable simplification and solution of trigonometric equations and expressions. Here are some crucial identities to remember:
Using these identities properly can simplify complex trigonometric expressions and make solving equations easier, a critical skill in mathematics.
- Pythagorean Identity: \(\sin^2\theta + \cos^2\theta = 1\)
- Reciprocal Identities such as \(\csc\theta = \frac{1}{\sin\theta}\), \(\sec\theta = \frac{1}{\cos\theta}\), and \(\cot\theta = \frac{1}{\tan\theta}\).
Using these identities properly can simplify complex trigonometric expressions and make solving equations easier, a critical skill in mathematics.
Other exercises in this chapter
Problem 29
Find the amplitude, if it exists, and period of each function. Then graph each function. \(y=\frac{1}{2} \cot 2 \theta\)
View solution Problem 30
Find all solutions of each equation for the given interval. \(2 \cos ^{2} \theta=\sin \theta+1 ; 0 \leq \theta
View solution Problem 30
You can determine whether or not an equation may be a trigonometric identity by graphing the expressions on either side of the equals sign as two separate funct
View solution Problem 30
Verify that each of the following is an identity. \(\sin \left(90^{\circ}-\theta\right)=\cos \theta\)
View solution