Problem 30
Question
Find the exact value of the expression. $$ \csc \left(\cos ^{-1} \frac{7}{25}\right) $$
Step-by-Step Solution
Verified Answer
The exact value is \( \frac{25}{24} \).
1Step 1: Understand the Inverse Cosine Function
We are given \[ \csc \left(\cos^{-1} \frac{7}{25}\right) \]This implies that we need to evaluate the cosecant of an angle whose cosine is \( \frac{7}{25} \). Let's denote this angle by \( \theta \). Therefore, \( \cos \theta = \frac{7}{25} \).
2Step 2: Use the Pythagorean Identity
To find the sine of \( \theta \), we use the Pythagorean identity: \[ \sin^2 \theta + \cos^2 \theta = 1 \]Substitute \( \cos \theta = \frac{7}{25} \) into the equation:\[ \sin^2 \theta + \left( \frac{7}{25} \right)^2 = 1 \]This simplifies to:\[ \sin^2 \theta + \frac{49}{625} = 1 \]\[ \sin^2 \theta = 1 - \frac{49}{625} \]
3Step 3: Calculate \( \sin \theta \)
Subtract \( \frac{49}{625} \) from 1:\[ 1 - \frac{49}{625} = \frac{625 - 49}{625} = \frac{576}{625} \]Thus, we have:\[ \sin^2 \theta = \frac{576}{625} \]Taking the square root (considering the principal value, assuming \( \theta \) is in the range of \( \cos^{-1} \)), we obtain:\[ \sin \theta = \frac{24}{25} \]
4Step 4: Find \( \csc \theta \)
The cosecant of an angle is the reciprocal of its sine. Thus:\[ \csc \theta = \frac{1}{\sin \theta} \]Substitute \( \sin \theta = \frac{24}{25} \):\[ \csc \theta = \frac{1}{\frac{24}{25}} = \frac{25}{24} \]
5Step 5: Conclusion
Therefore, the exact value of the given expression is:\[ \csc \left(\cos^{-1} \frac{7}{25}\right) = \frac{25}{24} \]
Key Concepts
Cosecant FunctionInverse Cosine FunctionPythagorean Identity
Cosecant Function
The cosecant function can be understood as one of the six primary trigonometric functions, closely related to sine. In fact, it is the reciprocal of the sine function. To find the cosecant of an angle \(\theta\), use the formula:
In the context of the given problem, the need arises to calculate \( \csc \theta \), where \( \theta \) is derived from the expression \( \csc(\cos^{-1}\frac{7}{25}) \). By first determining \( \sin \theta \) using trigonometric identities, we can easily find \( \csc \theta \) by taking the reciprocal of the sine value. This basic grasp of cosecant as a reciprocal process streamlines the problem-solving approach.
- \( \csc \theta = \frac{1}{\sin \theta} \)
In the context of the given problem, the need arises to calculate \( \csc \theta \), where \( \theta \) is derived from the expression \( \csc(\cos^{-1}\frac{7}{25}) \). By first determining \( \sin \theta \) using trigonometric identities, we can easily find \( \csc \theta \) by taking the reciprocal of the sine value. This basic grasp of cosecant as a reciprocal process streamlines the problem-solving approach.
Inverse Cosine Function
The inverse cosine function, denoted as \( \cos^{-1} x \) or sometimes \( \text{arccos} x \), gives us the angle \( \theta \) whose cosine is \( x \). In other words, if \( \cos \theta = x \), then \( \cos^{-1} x = \theta \). This function is critical in the realm of trigonometry for finding angles when their cosine is known.
One of the main characteristics of \( \cos^{-1} x \) is its range, which is between 0 and \( \pi \) radians (or 0° to 180° in degrees). This range ensures that for every valid input, a unique output (angle) is returned.
In solving the problem \( \csc(\cos^{-1}\frac{7}{25}) \), \( \cos^{-1} \frac{7}{25} \) leads us to find \( \theta \) where \( \cos \theta = \frac{7}{25} \). With \( \theta \) identified, the process of determining the corresponding sine (and consequently the cosecant) becomes feasible.
One of the main characteristics of \( \cos^{-1} x \) is its range, which is between 0 and \( \pi \) radians (or 0° to 180° in degrees). This range ensures that for every valid input, a unique output (angle) is returned.
In solving the problem \( \csc(\cos^{-1}\frac{7}{25}) \), \( \cos^{-1} \frac{7}{25} \) leads us to find \( \theta \) where \( \cos \theta = \frac{7}{25} \). With \( \theta \) identified, the process of determining the corresponding sine (and consequently the cosecant) becomes feasible.
Pythagorean Identity
The Pythagorean identity is one of the foundational relationships in trigonometry, derived from the Pythagorean theorem. It links the square of sine and cosine functions of an angle. The identity is expressed as:
In the textbook exercise \( \csc(\cos^{-1}\frac{7}{25}) \), since \( \cos \theta = \frac{7}{25} \), the Pythagorean identity helps compute \( \sin \theta \). By substituting \( \cos \theta \) into the identity, \( \sin^2 \theta \) can be calculated leading to \( \sin \theta = \frac{24}{25} \).
This powerful identity not only assists in solving such problems but also ensures that solutions are aligned with fundamental trigonometric truths, making it an essential tool in any trigonometry toolkit.
- \( \sin^2 \theta + \cos^2 \theta = 1 \)
In the textbook exercise \( \csc(\cos^{-1}\frac{7}{25}) \), since \( \cos \theta = \frac{7}{25} \), the Pythagorean identity helps compute \( \sin \theta \). By substituting \( \cos \theta \) into the identity, \( \sin^2 \theta \) can be calculated leading to \( \sin \theta = \frac{24}{25} \).
This powerful identity not only assists in solving such problems but also ensures that solutions are aligned with fundamental trigonometric truths, making it an essential tool in any trigonometry toolkit.
Other exercises in this chapter
Problem 29
Evaluate the expression without using a calculator. $$ \left(\cos 30^{\circ}\right)^{2}-\left(\sin 30^{\circ}\right)^{2} $$
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The measure of an angle in standard position is given. Find two positive angles and two negative angles that are coterminal with the given angle. $$ \frac{3 \pi
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Find the area of the triangle whose sides have the given lengths. \(a=1, \quad b=2, \quad c=2\)
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Find the exact value of the trigonometric function. $$ \csc \frac{5 \pi}{4} $$
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