Problem 30
Question
Find each of the following products. $$ \sqrt{x} \sqrt{x} $$
Step-by-Step Solution
Verified Answer
Answer: The product of the expression \(\sqrt{x}\sqrt{x}\) is \(x\).
1Step 1: Identify the terms to be multiplied
We are given the expression \(\sqrt{x}\sqrt{x}\). Here, the terms to be multiplied are \(\sqrt{x}\) and \(\sqrt{x}\).
2Step 2: Multiply the square roots
To multiply the two square roots, we write it like this:
$$
\sqrt{x} \cdot \sqrt{x}
$$
3Step 3: Apply the property of square roots
We can now apply the property of square roots, which states that \(\sqrt{a} \cdot \sqrt{a} = a\). In this case, our "a" is "x", so we have:
$$
\sqrt{x} \cdot \sqrt{x} = x
$$
4Step 4: State the final answer
By multiplying the two square roots together, we have found the product to be:
$$
\sqrt{x} \cdot \sqrt{x} = x
$$
Key Concepts
Multiplication of Square RootsProperties of Square RootsBasic Algebra
Multiplication of Square Roots
When you have square roots being multiplied together, like \(\sqrt{x}\) and \(\sqrt{x}\), it's a straightforward process. Multiplying square roots involves using a property that simplifies multiplication under the radical. If you multiply \(\sqrt{a}\) by \(\sqrt{b}\), you multiply the numbers under the radicals first. This is expressed as:
Practicing these concepts can build confidence in solving more complex equations involving radicals.
- \(\sqrt{a} \cdot \sqrt{b} = \sqrt{a \cdot b}\)
- In simpler cases, such as \(\sqrt{x} \cdot \sqrt{x}\), the solution turns into \(\sqrt{x^2}\).
Practicing these concepts can build confidence in solving more complex equations involving radicals.
Properties of Square Roots
Square roots have special mathematical properties that simplify how we work with them. One of the main properties helpful in today's exercise is how multiplying square roots together often results in removing the radical. Let's break this property down:
Recognizing these properties allows you to efficiently handle and work through problems involving square roots. Comprehending them can be a game-changer when simplifying expressions.
- \((\sqrt{a})^2 = a\): This tells us that whenever you multiply a square root by itself, you get the number under the square root.
- Importantly, \(\sqrt{a} \cdot \sqrt{b} = \sqrt{a \cdot b}\) allows combining square roots during multiplication.
Recognizing these properties allows you to efficiently handle and work through problems involving square roots. Comprehending them can be a game-changer when simplifying expressions.
Basic Algebra
Basic algebra often serves as the stepping stone for understanding more complex mathematical problems, including dealing with square roots. Algebra is concerned with symbols and the rules for manipulating these symbols.
Understanding algebra basics can empower you to simplify and solve expressions smoothly. It is foundational knowledge necessary for dealing with expressions that involve radical terms.
- In algebra, terms like variables are used instead of known numbers. For example, "x" is a common variable.
- When dealing with expressions like \(\sqrt{x} \cdot \sqrt{x}\), the algebraic rules we apply come directly from understanding mathematical properties, like those of square roots.
Understanding algebra basics can empower you to simplify and solve expressions smoothly. It is foundational knowledge necessary for dealing with expressions that involve radical terms.
Other exercises in this chapter
Problem 30
Simplify each expression by performing the indicated operation. $$ 6 \sqrt{18}+5 \sqrt{32}+4 \sqrt{50} $$
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For the following problems, simplify the expressions. $$ (x+\sqrt{8})(3 x+\sqrt{8}) $$
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For the following problems, simplify each expressions. $$ \sqrt{\frac{5}{16}} $$
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For the following problems, find the two square roots of the given number. $$ 64 $$
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