Problem 30
Question
Find a vector that gives the direction in which the given function decreases most rapidly at the indicated point. Find the minimum rate. $$ F(x, y, z)=\ln \frac{x y}{z} ;\left(\frac{1}{2}, \frac{1}{6}, \frac{1}{3}\right) $$
Step-by-Step Solution
Verified Answer
The vector is \((-2, -6, 3)\) and the minimum rate is \(-7\).
1Step 1: Compute the Gradient
The gradient of the function, \( F(x, y, z) = \ln \frac{xy}{z} \), is computed by taking partial derivatives. The gradient vector is given by \( abla F = \left( \frac{\partial F}{\partial x}, \frac{\partial F}{\partial y}, \frac{\partial F}{\partial z} \right) \). Compute \( \frac{\partial F}{\partial x} = \frac{1}{x} \), \( \frac{\partial F}{\partial y} = \frac{1}{y} \), and \( \frac{\partial F}{\partial z} = -\frac{1}{z} \). Thus, the gradient is \( abla F = \left( \frac{1}{x}, \frac{1}{y}, -\frac{1}{z} \right) \).
2Step 2: Evaluate the Gradient at the Point
Substitute the point \( \left( \frac{1}{2}, \frac{1}{6}, \frac{1}{3} \right) \) into the gradient vector \( abla F = \left( \frac{1}{x}, \frac{1}{y}, -\frac{1}{z} \right) \). This yields \( abla F \left( \frac{1}{2}, \frac{1}{6}, \frac{1}{3} \right) = \left( \frac{1}{\frac{1}{2}}, \frac{1}{\frac{1}{6}}, -\frac{1}{\frac{1}{3}} \right) = (2, 6, -3) \).
3Step 3: Determine the Direction of Maximum Decrease
The direction in which the function decreases most rapidly is the opposite direction of the gradient vector. Hence, the direction is \( -abla F = (-2, -6, 3) \).
4Step 4: Calculate the Minimum Rate of Decrease
The minimum rate of decrease is the negative of the magnitude of the gradient vector evaluated at the point. The magnitude of \( abla F \) is computed as \( \|abla F\| = \sqrt{2^2 + 6^2 + (-3)^2} = \sqrt{49} = 7 \). Thus, the minimum rate of decrease is \(-7\).
Key Concepts
Partial DerivativesGradient VectorFunction Optimization
Partial Derivatives
Partial derivatives are crucial in multivariable calculus and are used to find the rate of change of a function with respect to each variable individually. In essence, they measure how a function changes as one particular variable changes, while keeping others constant.
For instance, in the function given by \( F(x, y, z) = \ln \frac{xy}{z} \), we took the partial derivative with respect to \( x \), treating \( y \) and \( z \) as constants, resulting in \( \frac{1}{x} \).
For instance, in the function given by \( F(x, y, z) = \ln \frac{xy}{z} \), we took the partial derivative with respect to \( x \), treating \( y \) and \( z \) as constants, resulting in \( \frac{1}{x} \).
- Partial derivative with respect to \( y \) is \( \frac{1}{y} \).
- Partial derivative with respect to \( z \) is \( -\frac{1}{z} \).
Gradient Vector
The gradient vector is an essential tool in calculus for vector-valued functions. It combines all the partial derivatives of a function into one vector, which points in the direction of the greatest rate of increase of the function.
For our function \( F(x, y, z) = \ln \frac{xy}{z} \), the gradient is expressed as \( abla F = \left( \frac{1}{x}, \frac{1}{y}, -\frac{1}{z} \right) \).
For our function \( F(x, y, z) = \ln \frac{xy}{z} \), the gradient is expressed as \( abla F = \left( \frac{1}{x}, \frac{1}{y}, -\frac{1}{z} \right) \).
- The components \( \frac{1}{x}, \frac{1}{y}, \) and \( -\frac{1}{z} \) are derived from the partial derivatives of the function.
- It evaluates to \( (2, 6, -3) \) when you plug in the given point \( \left( \frac{1}{2}, \frac{1}{6}, \frac{1}{3} \right) \).
Function Optimization
Function optimization involves finding the input values that either maximize or minimize a function's output. Gradient descent, a popular method, leverages the gradient vector to find the minimum point of a function by iteratively moving in the direction of the greatest decrease.
The exercise revolves around pinpointing the direction and rate at which our function \( F(x, y, z) = \ln \frac{xy}{z} \) decreases most rapidly.
The exercise revolves around pinpointing the direction and rate at which our function \( F(x, y, z) = \ln \frac{xy}{z} \) decreases most rapidly.
- By evaluating the gradient vector at a specific point, we ascertain the direction of rapid decrease: the negative gradient, \( (-2, -6, 3) \).
- The rate of this decrease is given by the magnitude of the gradient vector, computed as \( 7 \), resulting in a minimum rate of decrease of \(-7\).
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Problem 30
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