Problem 30
Question
Factor completely, or state that the polynomial is prime. $$2 x^{3}-8 x$$
Step-by-Step Solution
Verified Answer
The factored form of the polynomial \(2x^{3}-8x\) is \(2x(x-2)(x+2)\).
1Step 1: Identify the GCF
The greatest common factor between the terms \(2x^{3}\) and \(-8x\) is \(2x\). This is because \(2x\) is the largest factor that divides both terms evenly.
2Step 2: Divide the Entire Polynomial by the GCF
Once the GCF has been identified, divide each term in the polynomial by this GCF. So \(2x^{3}\) divided by \(2x\) is \(x^{2}\) and \(-8x\) divided by \(2x\) is \(-4\).
3Step 3: Write Down the Factored Form
The polynomial, after factoring, becomes the GCF times the result from the previous step, i.e. \(2x(x^{2}-4)\). However, note that \(x^{2}-4\) is a difference of squares, which can be further factored into \((x-2)(x+2)\). So a more complete factorization is \(2x(x-2)(x+2)\).
Key Concepts
Greatest Common Factor (GCF)Difference of SquaresPolynomial Factorization
Greatest Common Factor (GCF)
Factoring a polynomial often begins by identifying the Greatest Common Factor (GCF) among its terms. The GCF is the largest factor that divides each term evenly. In our example, the polynomial is \(2x^3 - 8x\). To determine the GCF:
- Look at the coefficients (the numbers directly in front of the variables). For \(2x^3\) and \(-8x\), the coefficients are 2 and -8. The largest number that divides both is 2.
- Examine the variable part. The variable in both terms is \(x\). Since \(x^3\) and \(x\) both have \(x\), we take the lowest power, which is \(x\).
Difference of Squares
The concept of a difference of squares comes into play when recognizing patterns within a polynomial. This happens when you have an expression like \(a^2 - b^2\). The difference of squares can be rewritten as the product of two binomials:
- The formula is \(a^2 - b^2 = (a - b)(a + b)\).
- Here, \(a^2\) is \(x^2\) and \(b^2\) is 4, which is also \(2^2\).
Polynomial Factorization
Polynomial factorization involves breaking down a polynomial into simpler, easier-to-handle expressions, which multiply together to give the original polynomial. This process makes solving equations and simplifying expressions more manageable.
In our exercise, the polynomial \(2x^3 - 8x\) undergoes factorization as follows:
In our exercise, the polynomial \(2x^3 - 8x\) undergoes factorization as follows:
- Start by identifying the GCF, which is \(2x\).
- Divide the entire polynomial by \(2x\), leaving us with \(x^2 - 4\).
- Recognize \(x^2 - 4\) as a difference of squares and factor it into \((x - 2)(x + 2)\).
Other exercises in this chapter
Problem 30
Factor each trinomial, or state that the trinomial is prime. Check each factorization using FOIL multiplication. $$y^{2}-22 y+72$$
View solution Problem 30
Use factoring to solve each quadratic equation. Check by substitution or by using a graphing utility and identifying \(x\) -intercepts. $$x^{2}=14 x-49$$
View solution Problem 30
Now let's move on to factorizations that may require two or more techniques. Factor completely, or state that the polynomial is prime. Check factorizations usin
View solution Problem 30
Factor each polynomial using the greatest common factor. If there is no common factor other than 1 and the polynomial cannot be factored, so state. $$10 y^{4}+1
View solution