Problem 30
Question
Convert each of the given pairs of rectangular coordinates to a pair of polar coordinates ( \(r, \theta\) ) with \(r>0\) and \(0 \leq \theta<2 \pi\). $$(-2,2 \sqrt{3})$$
Step-by-Step Solution
Verified Answer
The polar coordinates corresponding to the rectangular coordinates (-2, 2\(\sqrt{3}\)) are (4, 2\(\pi / 3\)).
1Step 1: Calculating r
First, calculate the distance \( r \) from the origin to the point. This is done using Pythagorean theorem which gives us \( r = \sqrt{x^2 + y^2} \). When we input our coordinates we get \( r = \sqrt{(-2)^2 + (2\sqrt{3})^2} = \sqrt{4 + 12} = \sqrt{16} = 4 \). So, \( r = 4 \)
2Step 2: Calculating \(\theta\)
To calculate \(\theta\), we use the formula \( \tan(\theta) = \frac{y}{x} \). Then we use the arctan or tan inverse to find \(\theta\). However, we have to consider the quadrant of the point here. The point (-2, 2\( \sqrt{3} \)) is in the second quadrant, therefore \(\theta\) will lie between \(\pi / 2\) and \(\pi\). Calculating \(\theta\), we find \( \tan(\theta) = \frac{2\sqrt{3}}{-2} = -\sqrt{3} \). Now, we know that arctan(\(-\sqrt{3}\)) is \(-\pi / 3\). But since the point is in the second quadrant, we add \(\pi\) to get the actual \(\theta\). Hence, \(\theta = -\pi / 3 + \pi = 2\pi / 3 \).
3Step 3: Final Answer
The polar coordinates corresponding to the rectangular coordinates (-2, 2\(\sqrt{3}\)) are (4, 2\(\pi / 3\)).
Key Concepts
Pythagorean TheoremPolar CoordinatesTrigonometric FunctionsQuadrant Consideration
Pythagorean Theorem
The Pythagorean theorem is a fundamental principle in geometry, particularly when dealing with right-angled triangles. It states that for any right-angled triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides. This is expressed in the formula:
\[ c^2 = a^2 + b^2 \]
where \( c \) represents the length of the hypotenuse, and \( a \) and \( b \) represent the lengths of the triangle's other two sides.
In the context of converting rectangular coordinates to polar coordinates, the Pythagorean theorem helps us determine the radial distance \( r \) from the origin to the point. Here, \( r \) serves as the hypotenuse of a right triangle formed by drawing a perpendicular from the point to the X-axis. The two legs of this triangle are the X and Y coordinates of the point, and thus the theorem is used as follows:\[ r = \sqrt{x^2 + y^2} \]
This step is crucial because it provides the magnitude of the polar coordinate, which tells us how far away the point is from the origin in a direct line.
\[ c^2 = a^2 + b^2 \]
where \( c \) represents the length of the hypotenuse, and \( a \) and \( b \) represent the lengths of the triangle's other two sides.
In the context of converting rectangular coordinates to polar coordinates, the Pythagorean theorem helps us determine the radial distance \( r \) from the origin to the point. Here, \( r \) serves as the hypotenuse of a right triangle formed by drawing a perpendicular from the point to the X-axis. The two legs of this triangle are the X and Y coordinates of the point, and thus the theorem is used as follows:\[ r = \sqrt{x^2 + y^2} \]
This step is crucial because it provides the magnitude of the polar coordinate, which tells us how far away the point is from the origin in a direct line.
Polar Coordinates
Polar coordinates offer an alternative way to represent the position of a point in a plane, using a distance and an angle rather than the traditional X and Y coordinates. In polar coordinates, a point is identified by two values:
- The radial distance \( r \) from the origin (also known as the pole), which is the length of a straight line drawn from the origin to the point.
- The angle \( \theta \) (theta), which is the counterclockwise rotation required to align the positive X-axis with a line drawn from the origin to the point. This angle is measured in radians.
Trigonometric Functions
Trigonometric functions are the bridge between angular and spatial relationships in a plane, and they play a crucial role in the conversion of rectangular coordinates to polar coordinates. The three primary trigonometric functions are sine (sin), cosine (cos), and tangent (tan), which relate the angles of a right triangle to the ratios of two of its sides.
For a right triangle with angle \( \theta \), the functions are defined as:
For a right triangle with angle \( \theta \), the functions are defined as:
- \( \sin(\theta) = \frac{{\text{{opposite side}}}}{{\text{{hypotenuse}}}} \)
- \( \cos(\theta) = \frac{{\text{{adjacent side}}}}{{\text{{hypotenuse}}}} \)
- \( \tan(\theta) = \frac{{\text{{opposite side}}}}{{\text{{adjacent side}}}} \)
Quadrant Consideration
The concept of quadrants is essential when working with polar coordinates because the angle \( \theta \) can take on different values depending on the quadrant in which the point is located. The coordinate plane is divided into four quadrants by the X-axis and Y-axis, labelled counter-clockwise as I, II, III, and IV.
Knowing the quadrant helps determine the correct direction of \( \theta \):
Knowing the quadrant helps determine the correct direction of \( \theta \):
- In Quadrant I, \( 0 \leq \theta < \frac{\pi}{2} \).
- In Quadrant II, \( \frac{\pi}{2} \leq \theta < \pi \).
- In Quadrant III, \( \pi \leq \theta < \frac{3\pi}{2} \).
- In Quadrant IV, \( \frac{3\pi}{2} \leq \theta < 2\pi \).
Other exercises in this chapter
Problem 30
Use De Moivre's Theorem to find each expression. $$(2-2 i)^{4}$$
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Determine whether the given pairs of vectors are orthogonal. $$\mathbf{v}=\langle 3,5\rangle, \mathbf{w}=\left\langle\frac{5}{6}, \frac{1}{2}\right\rangle$$
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Find the magnitude and direction of each of the given vectors. Express the direction as an angle \(\theta\) in standard position, where \(0^{\circ} \leq \theta
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Use De Moivre's Theorem to find each expression. $$(\sqrt{3}+i)^{3}$$
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