Problem 30
Question
Complete the square to determine whether the equation represents an ellipse, a parabola, a hyperbola, or a degenerate conic. If the graph is an ellipse, find the center, foci, vertices, and lengths of the major and minor axes. If it is a parabola, find the vertex, focus, and directrix. If it is a hyperbola, find the center, foci, vertices, and asymptotes. Then sketch the graph of the equation. If the equation has no graph, explain why. $$ x^{2}+4 y^{2}+20 x-40 y+300=0 $$
Step-by-Step Solution
Verified Answer
The equation represents a degenerate conic with no graph.
1Step 1: Rearrange the Terms
Start with the given equation: \[ x^{2} + 4y^{2} + 20x - 40y + 300 = 0 \]Rearrange the terms by grouping the \(x\) and \(y\) terms together:\[ (x^{2} + 20x) + (4y^{2} - 40y) + 300 = 0 \]
2Step 2: Complete the Square for x-terms
For the \(x\) terms, complete the square:Take \(x^{2} + 20x\). To complete the square:1. Take half of the coefficient of \(x\) (which is 20), divide by 2 to get 10, and square it to get 100.2. Add and subtract this square inside the equation:\[ (x^{2} + 20x + 100) - 100 \]
3Step 3: Complete the Square for y-terms
For the \(y\) terms, complete the square:Start with \(4y^{2} - 40y\). Factor out 4 first:\[ 4(y^{2} - 10y) \]Then complete the square inside the parentheses:1. Take half of the coefficient of \(y\) (which is -10 inside the parentheses), divide by 2 to get -5, and square it to get 25.2. Add and subtract this square inside the parentheses:\[ 4(y^{2} - 10y + 25 - 25) \]This simplifies to:\[ 4((y - 5)^{2} - 25) \] which is equivalent to\[ 4(y - 5)^{2} - 100 \]
4Step 4: Simplify the Equation
Insert the completed squares back into the equation:\[ (x + 10)^{2} - 100 + 4(y - 5)^{2} - 100 + 300 = 0 \]Combine the constants:\[ (x + 10)^{2} + 4(y - 5)^{2} + 100 = 0 \]Subtract 100 from both sides:\[ (x + 10)^{2} + 4(y - 5)^{2} = -100 \]
5Step 5: Analyze the Conic
Since the equation \[ (x + 10)^{2} + 4(y - 5)^{2} = -100 \]has a negative value on the right side, this represents a degenerate conic. This equation cannot have a graph in the real plane because the squared term cannot equal a negative number.
Key Concepts
Completing the SquareDegenerate ConicEllipseHyperbola
Completing the Square
Completing the square is a mathematical method used to transform a quadratic equation into a perfect square trinomial. This technique is especially helpful when dealing with conic sections, as it can simplify equations to a standard form. For any quadratic term, like \(x^2 + bx\), follow these steps to complete the square:
- Take the coefficient of the linear term, \(b\).
- Divide it by 2 to get \(b/2\), and square the result to \((b/2)^2\).
- Add and subtract \((b/2)^2\) inside the equation to maintain balance.
Degenerate Conic
A degenerate conic is a special case in the study of conic sections. It occurs when the conic does not form a typical curve, like an ellipse, parabola, or hyperbola. Instead, the equation does not result in a usual graph when plotted.
- One sign of a degenerate conic is when the equation equals a negative value after completing the square, as squared terms cannot be negative in real numbers.
- Common types of degenerate conics include a single point, a line, or two intersecting lines.
Ellipse
An ellipse is a type of conic section characterized by its elongated circle shape. It is defined by the equation \( \frac{(x - h)^2}{a^2} + \frac{(y - k)^2}{b^2} = 1 \), where \( (h, k) \) is the center.
- The lengths of the major and minor axes are determined by \(2a\) and \(2b\), respectively.
- The foci are located along the major axis at \(c = \sqrt{a^2 - b^2}\) from the center.
Hyperbola
A hyperbola is another conic section with two distinct curves, similar to two mirrored parabolas. It follows a general form of \( \frac{(x - h)^2}{a^2} - \frac{(y - k)^2}{b^2} = 1 \) or vice-versa.
- The center is \( (h, k) \), with vertices along the transverse axis at \( \pm a \) from the center.
- The foci, located further from the center, are \( \pm c \), where \(c = \sqrt{a^2 + b^2}\).
- The asymptotes, lines that the hyperbola approaches but never touches, are given by \(y = \pm \frac{b}{a}(x - h) + k\).
Other exercises in this chapter
Problem 30
Find an equation for the ellipse that satisfies the given conditions. Foci \((0, \pm 3),\) vertices \((0, \pm 5)\)
View solution Problem 30
(a) Use the discriminant to identify the conic. (b) Confirm your answer by graphing the conic using a graphing device. $$9 x^{2}-6 x y+y^{2}+6 x-2 y=0$$
View solution Problem 30
Find an equation for the hyperbola that satisfies the given conditions. Foci \(( \pm 6,0),\) vertices \(( \pm 2,0)\)
View solution Problem 30
Find an equation for the parabola that has its vertex at the origin and satisfies the given condition(s). Directrix \(y=6\)
View solution