Problem 30
Question
Calculate the number of moles of \(\mathrm{KOH}\) in \(5.50 \mathrm{~mL}\) of a \(0.360 \mathrm{M} \mathrm{KOH}\) solution. What is the \(\mathrm{pOH}\) of the solution at \(25^{\circ} \mathrm{C} ?\)
Step-by-Step Solution
Verified Answer
0.00198 moles of KOH; pOH is approximately 0.444.
1Step 1: Identify Given Values
First, we need to identify all the given values from the problem. We have a potassium hydroxide (KOH) solution with a concentration of \(0.360 \text{ M}\) and a volume of \(5.50 \text{ mL}\). We also know that the temperature is \(25^{\circ} \text{C}\).
2Step 2: Convert mL to L
Since molarity is expressed in moles per liter, first convert the volume from milliliters to liters. The volume in liters is \(5.50 \text{ mL} \times \frac{1 \text{ L}}{1000 \text{ mL}} = 0.00550 \text{ L}\).
3Step 3: Calculate Moles of KOH
Use the molarity formula, \(M = \frac{n}{V}\), where \(n\) is the number of moles and \(V\) is the volume in liters. Rearrange to find \(n\): \[n = M \times V = 0.360 \text{ M} \times 0.00550 \text{ L} = 0.00198 \text{ moles of KOH}\]
4Step 4: Calculate pOH of the Solution
Potassium hydroxide is a strong base, so it dissociates completely in water. Therefore, the concentration of OH\(^-\) ions is equal to the concentration of KOH, which is \(0.360 \text{ M}\). Use the formula \(\text{pOH} = -\log[\text{OH}^-]\): \[\text{pOH} = -\log(0.360) \approx 0.444\]
Key Concepts
MolarityConcentrationpOHPotassium Hydroxide
Molarity
Molarity is a common way to express the concentration of a solution. It measures the number of moles of solute (the substance dissolved) per liter of solution. In formulaic terms, it is represented as:
To calculate the number of moles in a solution given molarity, you can rearrange this formula to solve for \( n \):
- \( M = \frac{n}{V} \)
To calculate the number of moles in a solution given molarity, you can rearrange this formula to solve for \( n \):
- \( n = M \times V \)
Concentration
The term concentration describes how much of a substance is contained within a certain volume of solution. There are several ways to express concentration, but molarity is one of the most important in chemistry. This is because it directly relates the quantity of solute to the volume of the solution.
- Higher concentration means more solute particles are packed into the same volume, making reactions faster due to increased particle interactions.
- In our context, we talk about potassium hydroxide (KOH) in water.
pOH
pOH is a measure of the basicity, or alkalinity, of a solution. It is similar to pH, which measures acidity, but instead focuses on the concentration of hydroxide ions \( \text{OH}^- \) in the solution. The formula used is:
As a strong base, potassium hydroxide fully dissociates in solution, meaning the hydroxide ion concentration directly equals the molarity of the KOH solution. Calculating pOH from a known concentration helps chemists understand how alkaline a solution is, which is crucial for processes that depend on a specific pH or pOH environment.
- \( \text{pOH} = -\log[\text{OH}^-] \)
As a strong base, potassium hydroxide fully dissociates in solution, meaning the hydroxide ion concentration directly equals the molarity of the KOH solution. Calculating pOH from a known concentration helps chemists understand how alkaline a solution is, which is crucial for processes that depend on a specific pH or pOH environment.
Potassium Hydroxide
Potassium hydroxide, often abbreviated as KOH, is a common strong base used in various industrial and laboratory settings. Being a strong base means it dissociates completely in water to produce hydroxide ions:
KOH's complete dissociation is particularly significant because it directly influences the solution's properties.
- \( \text{KOH} \rightarrow \text{K}^+ + \text{OH}^- \)
KOH's complete dissociation is particularly significant because it directly influences the solution's properties.
- Increased hydroxide ion concentration leads to a decrease in pOH, effectively making the solution more basic.
Other exercises in this chapter
Problem 28
Calculate the hydronium ion concentration in \(\mathrm{mol} / \mathrm{L}\) for each of the following solutions: (a) a solution whose \(\mathrm{pH}\) is \(5.20,(
View solution Problem 29
The \(\mathrm{pOH}\) of a solution is 9.40 at \(25^{\circ} \mathrm{C}\). Calculate the hydronium ion concentration of the solution.
View solution Problem 31
How much \(\mathrm{NaOH}\) (in grams) is needed to prepare \(546 \mathrm{~mL}\) of solution with a \(\mathrm{pH}\) of 10.00 at \(25^{\circ} \mathrm{C} ?\)
View solution Problem 32
A solution is made by dissolving \(18.4 \mathrm{~g}\) of \(\mathrm{HCl}\) in enough water to make \(662 \mathrm{~mL}\) of solution. Calculate the \(\mathrm{pH}\
View solution