Problem 30
Question
Assume that the discrete logistic equation is used with parameters \(R\) and \(K .\) Write the equation in the canonical form \(x_{t+1}=r x_{t}\left(1-x_{t}\right)\), and determine \(r\) and \(x_{t}\) in terms of \(R, K\), and \(R=2.5, K=50\)
Step-by-Step Solution
Verified Answer
In terms of \\(R = 2.5\\) and \\(K = 50\\), \\(r = 3.5\\) and \\(x_t = \frac{x_t}{50}\\). Equation: \\[x_{t+1} = 3.5 \left(\frac{x_t}{50}\right) (1 - \frac{x_t}{50})\].\\
1Step 1: Understand the Logistic Equation
The discrete logistic equation given is typically used to model population growth where resources are limited. The equation is: \[x_{t+1} = x_t + R x_t \left(1 - \frac{x_t}{K}\right)\] where \(x_t\) is the current population, \(R\) is the growth rate, and \(K\) is the carrying capacity.
2Step 2: Rearrange to Canonical Form
We need to express the logistic equation in the canonical form \(x_{t+1} = r x_t (1 - x_t)\). To do this, factor out \(x_t\): \[x_{t+1} = x_t + R x_t - \frac{R x_t^2}{K}\]. Simplifying gives \[x_{t+1} = x_t(1 + R - \frac{R x_t}{K})\].
3Step 3: Define Canonical Parameters
Compare the simplified equation \(x_{t+1} = x_t(1 + R - \frac{R x_t}{K})\) to the canonical form \(x_{t+1} = r x_t (1 - x_t)\) and identify: \[r = 1 + R\] and \[x_t = \frac{x_t}{K}\]. Thus, \(r\) is the effective growth rate and \(x_t\) is scaled by the carrying capacity \(K\).
4Step 4: Substitute Given Values
Given \(R = 2.5\) and \(K = 50\), substitute these values into the expressions for \(r\) and scaled \(x_t\): \[r = 1 + 2.5 = 3.5\] and \[x_t = \frac{x_t}{50}\].
5Step 5: State the Resulting Equation
Replace \(r\) and scaled \(x_t\) in the canonical form: \[x_{t+1} = 3.5 \left(\frac{x_t}{50}\right) (1 - \frac{x_t}{50})\]. This is the specific form of the discrete logistic equation with the given parameters.
Key Concepts
Population Growth ModelingCanonical FormGrowth RateCarrying Capacity
Population Growth Modeling
The discrete logistic equation is a fundamental tool in understanding population growth dynamics. It describes how populations evolve over discrete time steps, factoring in limitations of resources such as food and space. The equation acknowledges that while populations can grow rapidly, they will eventually reach a stage where growth slows due to resource scarcity.
Key elements considered in this model include:
Key elements considered in this model include:
- The current population size (\(x_t\)
- The growth rate (\(R\)
- The maximum population size that the environment can support, called carrying capacity (\(K\)
Canonical Form
The canonical form is a standardized version of the logistic equation that simplifies comparisons and calculations. It is expressed as:\(x_{t+1} = r x_t (1 - x_t)\), where:
This form erases specific parameters by scaling them, providing a clearer view of key dynamics without different scales interfering. In the context of the exercise, the canonical form is achieved by aligning the discrete logistic equation with \(x_{t+1} = r x_t (1 - x_t)\). While re-arranging, you compare the coefficients and adjust them so that the equation adopts a uniform structure applicable across different scenarios and models. The canonical form thus serves as a universal descriptor of logistic growth.
- \(x_{t+1}\) is the population size at the next time step
- \(x_t\) is the current population size
- \(r\) represents the adjusted growth rate
This form erases specific parameters by scaling them, providing a clearer view of key dynamics without different scales interfering. In the context of the exercise, the canonical form is achieved by aligning the discrete logistic equation with \(x_{t+1} = r x_t (1 - x_t)\). While re-arranging, you compare the coefficients and adjust them so that the equation adopts a uniform structure applicable across different scenarios and models. The canonical form thus serves as a universal descriptor of logistic growth.
Growth Rate
Growth rate (\(R\)) is a critical factor in modeling populations. It reflects how fast the population increases per time step. Higher growth rates indicate rapidly expanding populations, whereas lower rates suggest slower growth.
In the logistic equation, the effective growth rate (\(r\)) is derived from \(R\) as \(r = 1 + R\). This conversion integrates constant growth adjustments to accommodate population scaling and carrying capacity effects.
In the logistic equation, the effective growth rate (\(r\)) is derived from \(R\) as \(r = 1 + R\). This conversion integrates constant growth adjustments to accommodate population scaling and carrying capacity effects.
- Increases in \(R\) raise \(r\) proportionately, expanding growth potential.
- A stable \(r\) accounts for initial exponential growth and eventual stabilization due to limited resources.
Carrying Capacity
The notion of carrying capacity (\(K\)) is pivotal in understanding the logistics of population growth. It denotes the maximum number of individuals an environment can sustainably support.
As the population size approaches \(K\), growth rates decline due to resource limitations, leading to a stabilizing effect. In our equation, the population size is represented as a fraction of \(K\), converting the raw population figures into a dimensionless quantity:
As the population size approaches \(K\), growth rates decline due to resource limitations, leading to a stabilizing effect. In our equation, the population size is represented as a fraction of \(K\), converting the raw population figures into a dimensionless quantity:
- When \(x_t = K\), growth theoretically ceases, reflecting a balance with environmental carrying limits.
- When \(x_t < K\), growth continues, but at a reducing rate as reserves deplete.
Other exercises in this chapter
Problem 29
Find the recursion for a population that quadruples in size everv unit of time and that has 30 individuals at time 0 .
View solution Problem 29
Find an expression for \(a_{n}\) on the basis of the values of \(a_{0}, a_{1}, a_{2}, \ldots .\) $$ 1, \frac{1}{3}, \frac{1}{9}, \frac{1}{27}, \frac{1}{81}, \ld
View solution Problem 30
. Find the recursion for a population that quadruples in size every unit of time and that has 62 individuals at time \(0 .\)
View solution Problem 30
Find an expression for \(a_{n}\) on the basis of the values of \(a_{0}, a_{1}, a_{2}, \ldots .\) $$ \frac{1}{3}, \frac{2}{5}, \frac{3}{7}, \frac{4}{9}, \frac{5}
View solution