Problem 30
Question
Are the statements true or false? If a statement is true, give an example illustrating it. If a statement is false, give a counterexample. If a function is not differentiable, then it is not continu- ous.
Step-by-Step Solution
Verified Answer
The statement is false; a counterexample is \( f(x) = |x| \) which is continuous but not differentiable at \( x = 0 \).
1Step 1: Understand the Problem
We need to determine whether the statement "If a function is not differentiable, then it is not continuous" is true or false. This involves evaluating the relationship between differentiability and continuity.
2Step 2: Recall Definitions
A function is differentiable at a point if it has a derivative there, meaning the slope of the tangent line is defined. A function is continuous at a point if there is no break, jump, or hole at that point.
3Step 3: Assess the Statement
According to mathematical principles, differentiability implies continuity, but the converse is not true. Therefore, a function can be continuous but not differentiable at a certain point.
4Step 4: Provide a Counterexample
Consider the function \( f(x) = |x| \). It is continuous everywhere, specifically at \( x = 0 \), but it is not differentiable at that point because the slope from the left does not equal the slope from the right (it has a corner).
5Step 5: Decide the Truth Value
Since we found a function (\( f(x) = |x| \)) that is continuous but not differentiable at a point, the statement "If a function is not differentiable, then it is not continuous" is false.
Key Concepts
Function ContinuityDifferentiable FunctionsCounterexample in Calculus
Function Continuity
Understanding function continuity is crucial for comprehending the behavior of functions in calculus. A function is said to be continuous at a point if there is no interruption in its graph at that point. Imagine drawing the graph of the function without lifting your pen; if you can, the function is continuous. In mathematical terms, a function \( f(x) \) is continuous at a point \( x = a \) if the limit of \( f(x) \) as \( x \) approaches \( a \) is equal to the function's value at \( a \). This is expressed as:
- \( \lim_{x \to a} f(x) = f(a) \)
Differentiable Functions
Differentiability is a deeper concept than continuity in calculus, focusing on how a function behaves at a more granular level. A function is differentiable at a point if it has a derivative at that point. This means the function has a well-defined tangent line at that point, and its graph is smooth there. The derivative represents the rate of change or slope of the function at that given point.
- If a function \( f(x) \) is differentiable at a point \( x = a \), it must first be continuous at \( x = a \).
- However, the opposite is not always true: a function can be continuous but not differentiable at a point.
Counterexample in Calculus
Counterexamples are powerful tools in calculus for disproving general statements. When faced with a proposition such as "If a function is not differentiable, then it is not continuous," providing a counterexample can show the claim is false. One classic counterexample is the function \( f(x) = |x| \), which is continuous everywhere but not differentiable at \( x = 0 \).
- This example shows how differentiability is stricter than continuity; continuity does not require the smoothness and well-defined tangents demanded by differentiability.
- In visual terms, a counterexample like \( f(x) = |x| \) demonstrates a point on the graph where the pants meet without a clear slope direction, undermining any concluding universal differentiability.
- Such examples are crucial in math for demonstrating exceptions and understanding the boundaries of mathematical rules fully.
Other exercises in this chapter
Problem 29
Draw a possible graph of \(y=f(x)\) given the following information about its derivative. \(\cdot f^{(x)}>0\) for \(x-1\) \(\cdot f^{\prime}(x)=0\) at \(x=-1\)
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(a) Estimate \(f^{\prime}(0)\) if \(f(x)=\sin x,\) with \(x\) in degrees. (b) In Example 3 on page \(93,\) we found that the derivative of \(\sin x\) at \(x=0\)
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Use algebra to evaluate the limit. $$\lim _{h \rightarrow 0} \frac{(2+h)^{2}-4}{h}$$
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