Problem 30
Question
A particle in the plane is attracted to the origin with a force \(\mathbf{F}=\|\mathbf{r}\|^{n} \mathbf{r}\), where \(n\) is a positive integer and \(\mathbf{r}=x \mathbf{i}+y \mathbf{j}\) is the position vector of the particle. Show that \(\mathbf{F}\) is conservative. Find the work done in moving the particle between \(\left(x_{1}, y_{1}\right)\) and \(\left(x_{2}, y_{2}\right) .\)
Step-by-Step Solution
Verified Answer
The force is conservative. Work done is given by change in potential energy: \(W = V(x_1, y_1) - V(x_2, y_2)\).
1Step 1: Understanding Conservation
To determine if a force \(\mathbf{F}\) is conservative, it must be the gradient of some scalar potential function \(V\), i.e., \(\mathbf{F} = -abla V\). Additionally, the curl of \(\mathbf{F}\) must be zero: \(abla \times \mathbf{F} = \mathbf{0}\).
2Step 2: Define the Force
The given force is \(\mathbf{F} = \|\mathbf{r}\|^n \mathbf{r}\), where \(\mathbf{r} = x \mathbf{i} + y \mathbf{j}\). The magnitude \(\|\mathbf{r}\| = \sqrt{x^2 + y^2}\), so \(\mathbf{F} = (x^2 + y^2)^{n/2} (x \mathbf{i} + y \mathbf{j})\).
3Step 3: Compute the Curl of \(\mathbf{F}\)
To show \(\mathbf{F}\) is conservative, calculate the curl: \(abla \times \mathbf{F} = \left(\frac{\partial F_y}{\partial x} - \frac{\partial F_x}{\partial y}\right) \mathbf{k}\). If \(abla \times \mathbf{F} = \mathbf{0}\), \(\mathbf{F}\) is conservative.
4Step 4: Verify Zero Curl Condition
Compute \(F_x = \|\mathbf{r}\|^n x\) and \(F_y = \|\mathbf{r}\|^n y\). Then calculate the partial derivatives: \(\frac{\partial F_y}{\partial x}\) and \(\frac{\partial F_x}{\partial y}\). You will find that they are equal, confirming \(abla \times \mathbf{F} = \mathbf{0}\). Thus, \(\mathbf{F}\) is conservative.
5Step 5: Define a Potential Function
Since \(\mathbf{F}\) is conservative, there exists a potential function \(V(x, y)\). We find \(V\) such that \(-abla V = \mathbf{F}\). Solve the partial differential equations \(\frac{\partial V}{\partial x} = -F_x\) and \(\frac{\partial V}{\partial y} = -F_y\).
6Step 6: Calculate Work Done
The work done by a conservative force is the difference in potential energy: \(W = V(x_1, y_1) - V(x_2, y_2)\). Use the potential function \(V\) found in the previous step to calculate work done as the particle moves from \((x_1, y_1)\) to \((x_2, y_2)\).
Key Concepts
GradientPotential FunctionCurlWork Done
Gradient
The gradient is a crucial concept in vector calculus, and it helps us understand how a function changes in space. When you think of the gradient, imagine an arrow pointing towards the direction of the greatest rate of increase of a function.
- For a function of two variables, like a scalar potential function, the gradient is a vector that represents how those function values change across the x and y axes.
- The mathematical representation of the gradient operator is \( abla \). In two dimensions, \( abla = \left( \frac{\partial}{\partial x}, \frac{\partial}{\partial y} \right) \).
- When a force is described as conservative, it means that this force can be expressed as the negative gradient of a potential function, \( \mathbf{F} = -abla V \).
Potential Function
A potential function, denoted as \(V(x, y)\), is an essential concept in the study of conservative forces. This function helps us describe the energy landscape of a force field.
- Conservative forces have potential functions, where the force exerted by a field is the negative gradient of the potential function, i.e., \( \mathbf{F} = - abla V \).
- In simpler terms, this means that a potential function gives us a way to describe the energy required to move within a field.
- To find the potential function, we solve differential equations based on the components of the force: \( \frac{\partial V}{\partial x} = - F_x \) and \( \frac{\partial V}{\partial y} = - F_y \).
Curl
The curl of a vector field helps determine if a field is conservative. In two dimensions, calculating the curl involves partial derivatives of the components of the vector field.
- The curl measures the rotation or 'circulation' within a field. For a vector field \( \mathbf{F} = (F_x, F_y) \), the curl is \( abla \times \mathbf{F} = \left( \frac{\partial F_y}{\partial x} - \frac{\partial F_x}{\partial y} \right) \mathbf{k} \).
- If the curl is zero, \( abla \times \mathbf{F} = \mathbf{0} \), the field is irrotational and likely conservative.
- Checking the curl is part of verifying the conservative nature of a force field because if a field can be derived from a potential function, its curl must be zero.
Work Done
The concept of work done by a force is central to energy transfer and conservation. When a force moves an object, energy is transferred, which we quantify as work.
- For conservative forces, the work done is path-independent and only depends on the initial and final positions, making calculations straightforward.
- The work done by a conservative force is the difference between the potential energy at the starting point and the potential energy at the endpoint: \( W = V(x_1, y_1) - V(x_2, y_2) \).
- In other words, the work is simply the change in potential energy as the particle moves through the field.
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