Problem 30
Question
A flask contains a mixture of neon (Ne), krypton (Kr), and radon (Rn) gases. Compare (a) the average kinetic energies of the three types of atoms and; (b) the root-mean-square speeds. (Hint: The periodic table in Appendix D shows the molar mass (in g/mol) of each element under the chemical symbol for that element)
Step-by-Step Solution
Verified Answer
(a) The average kinetic energies are equal for Ne, Kr, and Rn. (b) Ne has the highest rms speed, followed by Kr, and then Rn.
1Step 1: Understand Molecular Kinetic Energy
The average kinetic energy of gas particles is given by the equation \( KE = \frac{3}{2} k T \), where \( k \) is the Boltzmann constant and \( T \) is the temperature in Kelvin. This shows that average kinetic energy depends only on the temperature, not the type of gas.
2Step 2: Compare Average Kinetic Energies
Since the average kinetic energy depends only on temperature (and temperature is the same for all gases in the flask), the average kinetic energy is the same for Ne, Kr, and Rn.
3Step 3: Understand Root-Mean-Square Speed Formula
Root-mean-square speed is given by the equation \( v_{rms} = \sqrt{\frac{3kT}{m}} \), where \( m \) is the molar mass of the gas. This means it depends on both the temperature and the molar mass of the gas.
4Step 4: Calculate Root-Mean-Square Speeds
The root-mean-square speed inversely depends on the square root of the molar mass of each gas. Using the molar masses from the periodic table (Ne: 20.18 g/mol, Kr: 83.80 g/mol, Rn: 222 g/mol), calculate \( v_{rms} \) for each: Ne will have the highest \( v_{rms} \), followed by Kr, and Rn will have the lowest.
Key Concepts
Root-Mean-Square SpeedMolar MassBoltzmann Constant
Root-Mean-Square Speed
The root-mean-square speed (\( v_{rms} \)) is an important concept in understanding gas behavior. It provides us with an average measure of the speed at which gas particles move in a system. It is derived from the formula: \[ v_{rms} = \sqrt{\frac{3kT}{m}} \] where \( k \)is the Boltzmann constant, \( T \)represents the temperature in Kelvin, and \( m \)is the molar mass of the gas.
- The term \( \sqrt{3kT} \)reflects the influence of temperature. Higher temperature means faster particle speeds.
- The denominator expresses the impact of the molar mass, indicating that lighter gases have higher root-mean-square speeds.
Molar Mass
Molar mass is a key factor when dealing with gas calculations, influencing properties such as root-mean-square speed. Molar mass, characterized by the symbol \( m \), is the mass of one mole of a substance, commonly expressed in grams per mole (g/mol).
- It essentially tells us how heavy or light a particular molecule is and thus plays a significant role in kinetic computations like \( v_{rms} \).
- Heavier particles, due to their higher molar mass, tend to move slower compared to lighter ones at the same temperature.
Boltzmann Constant
The Boltzmann constant (\( k \)) is a fundamental constant utilized in statistical mechanics and thermodynamics. Its value, approximately \( 1.38 \times 10^{-23} \text{ J/K} \), connects the macroscopic and microscopic worlds, converting temperature energy into kinetic energy.
- It allows us to translate the temperature of a system into the kinetic energy of particles, a central concept in gas behavior models.
- In the formula for average kinetic energy \( KE = \frac{3}{2} k T \), it clarifies how temperature affects the movement of particles.
Other exercises in this chapter
Problem 27
How many moles are in a \(1.00-\mathrm{kg}\) bottle of water? How many nolecules? The inolar mass of water is 18.0 \(\mathrm{g} / \mathrm{mol}\).
View solution Problem 29
Consider 5.00 mol of liquid water. (a) What volume is occupied by this amount of water? The molar mass of water is 18.0 \(\mathrm{g} / \mathrm{mol}\) (b) Imagin
View solution Problem 31
(a) A process called gaseous diffusion is often used to separate isotopes of uranium-that is, atoms of the elements that have different inasses, such as \(^{235
View solution Problem 33
We have two equal-size boxes, \(A\) and \(B\) . Each box contains gas that behaves as an ideal gas. We insert a thermometer into each box and find that the gas
View solution