Problem 30
Question
\(27-32\) : A function \(f\) is given, and the indicated transformations are applied to its graph (in the given order). Write the equation for the final transformed graph. \(f(x)=\sqrt[3]{x}\) , reflect in the \(y\) -axis, shrink vertically by a factor of \(\frac{1}{2},\) and shift upward \(\frac{1}{3}\) unit
Step-by-Step Solution
Verified Answer
\(f(x) = \frac{1}{2}\sqrt[3]{-x} + \frac{1}{3}\) is the final transformed function.
1Step 1: Reflect in the y-axis
To reflect the graph of a function in the y-axis, we replace \( x\) with \(-x\). Therefore, the function \( f(x) = \sqrt[3]{x} \) becomes \( f(x) = \sqrt[3]{-x} \). This transformation reflects the graph across the y-axis.
2Step 2: Shrink Vertically by a Factor of 1/2
A vertical shrink by a factor of \( \frac{1}{2} \) is achieved by multiplying the entire function by \( \frac{1}{2} \). So, the function becomes \( f(x) = \frac{1}{2}\sqrt[3]{-x} \). This reduces the height of the graph by half its original size.
3Step 3: Shift Upward by 1/3 Unit
To shift the graph upward by \( \frac{1}{3} \) unit, we add \( \frac{1}{3} \) to the function. Therefore, the transformed function is \( f(x) = \frac{1}{2}\sqrt[3]{-x} + \frac{1}{3} \). This step results in the final position of the graph after all transformations.
Key Concepts
Reflecting FunctionsVertical ShrinkVertical Shift
Reflecting Functions
Reflecting a function across the y-axis is a type of transformation that involves flipping the graph over the y-axis. This is specifically done by transforming the independent variable in the function. If you have a function defined as \(f(x)\), reflecting it in the y-axis requires replacing \(x\) with \(-x\). For example, if we apply this to the function \(f(x) = \sqrt[3]{x}\), the transformed function becomes \(f(x) = \sqrt[3]{-x}\). By doing this, every point \((x, y)\) on the original graph is mapped to \((-x, y)\) on the transformed graph.
In simpler terms, reflecting across the y-axis can be visualized as if the graph stands in front of a mirror along the y-axis. This is a handy technique when you need to analyze how a function behaves symmetrically in reverse.
In simpler terms, reflecting across the y-axis can be visualized as if the graph stands in front of a mirror along the y-axis. This is a handy technique when you need to analyze how a function behaves symmetrically in reverse.
Vertical Shrink
A vertical shrink in function transformations refers to compressing the graph of the function towards the x-axis. This is carried out by multiplying the entire function by a number between 0 and 1—known as the "shrink factor." Suppose we have \(f(x) = \sqrt[3]{-x}\), and we intend to perform a vertical shrink by a factor of \(\frac{1}{2}\). In this case, we would multiply the function by \(\frac{1}{2}\), resulting in the new function \(f(x) = \frac{1}{2}\sqrt[3]{-x}\).
Think of it like squeezing the graph from top to bottom, making it vertically shorter. Each point \((x, y)\) on the original graph is moved to \((x, \frac{y}{2})\), effectively halving the height of the graph's output values. This transformation does not affect the x-values or the horizontal spacing between points, only the vertical stretch of the graph.
Think of it like squeezing the graph from top to bottom, making it vertically shorter. Each point \((x, y)\) on the original graph is moved to \((x, \frac{y}{2})\), effectively halving the height of the graph's output values. This transformation does not affect the x-values or the horizontal spacing between points, only the vertical stretch of the graph.
Vertical Shift
Vertical shifting is a straightforward transformation where you slide the graph of a function up or down. To achieve a vertical shift, you simply add or subtract a constant from the entire function. If we consider the function \(g(x) = \frac{1}{2}\sqrt[3]{-x}\) and we want to shift it upward by \(\frac{1}{3}\) unit, we add \(\frac{1}{3}\) to the function: resulting in \(f(x) = \frac{1}{2}\sqrt[3]{-x} + \frac{1}{3}\).
This means that every point on the graph of the function is moved directly upward by that amount. Using this shift technique, if a point on the unshifted graph was at \((x, y)\), it will now be at \((x, y+\frac{1}{3})\). Such translations are crucial for analyzing the effect of adding constant values to functions, often used to correct or shift the baseline of a graph in data representation.
This means that every point on the graph of the function is moved directly upward by that amount. Using this shift technique, if a point on the unshifted graph was at \((x, y)\), it will now be at \((x, y+\frac{1}{3})\). Such translations are crucial for analyzing the effect of adding constant values to functions, often used to correct or shift the baseline of a graph in data representation.
Other exercises in this chapter
Problem 30
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