Problem 3
Question
Which of the following is a distribution? (a) \(T(\phi)=\sum_{n=1}^{m} \lambda_{n} \phi^{(n)}(0) \quad\left(\lambda_{n} \in \mathbb{R}\right)\) (b) \(T(\phi)=\sum_{n=1}^{m} \lambda_{n} \phi\left(x_{n}\right) \quad\left(\lambda_{n}, x_{n} \in \mathbb{R}\right)\). (c) \(T(\phi)=(\phi(0))^{2}\). (d) \(T(\phi)=\sup \phi\) (c) \(T(\phi)=\int_{-\infty}^{\infty}|\phi(x)| \mathrm{d} x\).
Step-by-Step Solution
Verified Answer
The distributions are (a) \(T(\phi)=\sum_{n=1}^{m} \lambda_{n} \phi^{(n)}(0) \quad(\lambda_{n}\in \mathbb{R})\) and (b) \(T(\phi)=\sum_{n=1}^{m} \lambda_{n} \phi\left(x_{n}\right) \quad(\lambda_{n}, x_{n} \in \mathbb{R})\)
1Step 1: Checking Option (a)
Option (a) \(T(\phi)=\sum_{n=1}^{m} \lambda_{n} \phi^{(n)}(0) \quad(\lambda_{n} \in \mathbb{R})\) is a distribution because it is linear in \(\phi\) and also sends compactly supported smooth functions into continuous linear functionals.
2Step 2: Checking Option (b)
Option (b) \(T(\phi)=\sum_{n=1}^{m} \lambda_{n} \phi\left(x_{n}\right) \quad(\lambda_{n}, x_{n} \in \mathbb{R})\) is also a distribution for the same reasons as in Option (a). It is linear in \(\phi\) and sends compactly supported smooth functions into real numbers in a linear way.
3Step 3: Checking Option (c)
Option (c) \(T(\phi)=(\phi(0))^{2}\) is not a distribution because it is nonlinear which eventuates into failure to satisfy the required properties of the distributions.
4Step 4: Checking Option (d)
Option (d) \(T(\phi)=\sup \phi\) is not a distribution because it is not linear in \(\phi\). The supremum operation is a nonlinear operation, so this does not satisfy the linearity property that distributions must have.
5Step 5: Checking Option (e)
Option (e) \(T(\phi)=\int_{-\infty}^{\infty}|\phi(x)| \mathrm{d} x\) is not a distribution because the absolute value operation makes the function nonlinear in \(\phi\), so it does not satisfy the linearity property of distributions
Key Concepts
LinearityCompact SupportSmooth Functions
Linearity
Linearity is a fundamental concept when dealing with distributions in mathematics. It implies that the operation of a distribution should maintain two essential properties: additivity and homogeneity.
To understand these properties, consider a distribution \(T(\phi)\). For linearity, the following must hold:
This principle of linearity allows for a predictable and systematic way to work with distributions, making them a powerful tool in mathematical analysis.
To understand these properties, consider a distribution \(T(\phi)\). For linearity, the following must hold:
- Additivity: \(T(\phi_1 + \phi_2) = T(\phi_1) + T(\phi_2)\) for any functions \(\phi_1\) and \(\phi_2\).
- Homogeneity: \(T(c \cdot \phi) = c \cdot T(\phi)\) for any scalar \(c\) and function \(\phi\).
This principle of linearity allows for a predictable and systematic way to work with distributions, making them a powerful tool in mathematical analysis.
Compact Support
Compact support refers to functions that are zero outside a certain interval, meaning they have a "limited" reach.
This property is essential in distribution theory because it ensures that a function behaves well for operations involved in distributions.
In mathematical contexts, compact support often provides a clear boundary within which analysis is performed, simplifying numerous theoretical concerns.
This property is essential in distribution theory because it ensures that a function behaves well for operations involved in distributions.
- When a function has compact support, it makes integrations and summations more manageable.
- In distribution theory, we often require test functions to have compact support to guarantee convergence and stability in certain operations.
In mathematical contexts, compact support often provides a clear boundary within which analysis is performed, simplifying numerous theoretical concerns.
Smooth Functions
Smooth functions are those which can be differentiated infinitely many times. This property makes them particularly suitable for use in distribution and analysis.
These functions often serve as test functions in distribution theory:
In practical terms, understanding smooth functions helps mathematicians perform comprehensive analyses, leading to insights in areas ranging from calculus to theoretical physics.
These functions often serve as test functions in distribution theory:
- They allow the behavior of distributions to be explored through infinite derivatives.
- Being infinitely differentiable means they can be manipulated through various mathematical operations while maintaining desired properties.
In practical terms, understanding smooth functions helps mathematicians perform comprehensive analyses, leading to insights in areas ranging from calculus to theoretical physics.
Other exercises in this chapter
Problem 4
We say a scquence of distributions \(T_{n}\) converges to a distribution \(T\), written \(T_{n} \rightarrow T\). if \(T_{n}(\phi) \rightarrow T(\phi)\) for all
View solution Problem 6
Evaluate (a) \(\int_{-\infty}^{\infty} \mathrm{e}^{a t} \sin b t \delta^{(n)}(t) \mathrm{d} t \quad\) for \(n=0,1,2\). (b) \(\int_{-\infty}^{\infty}(\cos t+\sin
View solution Problem 7
Show the following identities: (a) \(\delta((x-a)(x-b))=\frac{1}{b-a}(\delta(x-a)+\delta(x-b))\) (b) \(\frac{\mathrm{d}}{\mathrm{dx}} \theta\left(x^{2}-1\right)
View solution