Problem 3
Question
What are the products of each of the following acid-base reactions? Indicate the acid and its conjugate base and the base and its conjugate acid. (a) \(\mathrm{HNO}_{3}+\mathrm{H}_{2} \mathrm{O} \rightarrow\) (b) \(\mathrm{HSO}_{4}^{-}+\mathrm{H}_{2} \mathrm{O} \rightarrow\) (c) \(\mathrm{H}_{3} \mathrm{O}^{+}+\mathrm{F}^{-} \rightarrow\)
Step-by-Step Solution
Verified Answer
(a) \( \mathrm{NO}_3^- + \mathrm{H}_3O^+ \). (b) \( \mathrm{SO}_4^{2-} + \mathrm{H}_3O^+ \). (c) \( \mathrm{H}_2O + \mathrm{HF} \).
1Step 1: Identify Reactants in (a)
In the reaction \( \mathrm{HNO}_3 + \mathrm{H}_2O \rightarrow \), \( \mathrm{HNO}_3 \) is the acid because it donates a proton (\( \mathrm{H}^+ \)), and \( \mathrm{H}_2O \) is the base since it accepts a proton.
2Step 2: Write Products for (a)
When \( \mathrm{HNO}_3 \) donates a proton to \( \mathrm{H}_2O \), it forms the conjugate base \( \mathrm{NO}_3^- \). The \( \mathrm{H}_2O \), having gained a proton, forms the conjugate acid \( \mathrm{H}_3O^+ \). Thus, the products are \( \mathrm{NO}_3^- + \mathrm{H}_3O^+ \).
3Step 3: Identify Reactants in (b)
In \( \mathrm{HSO}_4^- + \mathrm{H}_2O \rightarrow \), \( \mathrm{HSO}_4^- \) is the acid, donating a proton, while \( \mathrm{H}_2O \) acts as the base, accepting the proton.
4Step 4: Write Products for (b)
When \( \mathrm{HSO}_4^- \) donates a proton to \( \mathrm{H}_2O \), it forms \( \mathrm{SO}_4^{2-} \) (conjugate base). \( \mathrm{H}_2O \) becomes \( \mathrm{H}_3O^+ \) (conjugate acid). So, the products are \( \mathrm{SO}_4^{2-} + \mathrm{H}_3O^+ \).
5Step 5: Identify Reactants in (c)
In \( \mathrm{H}_3O^+ + \mathrm{F}^- \rightarrow \), \( \mathrm{H}_3O^+ \) acts as the acid, donating a proton. \( \mathrm{F}^- \) is the base as it accepts the proton.
6Step 6: Write Products for (c)
When \( \mathrm{H}_3O^+ \) donates a proton to \( \mathrm{F}^- \), it forms \( \mathrm{H}_2O \) (conjugate base). \( \mathrm{F}^- \), when it gains a proton, becomes \( \mathrm{HF} \) (conjugate acid). Therefore, the products are \( \mathrm{H}_2O + \mathrm{HF} \).
Key Concepts
Conjugate Acid-Base PairsProton TransferReaction Products
Conjugate Acid-Base Pairs
In acid-base reactions, reacting species are acids and bases, which transform into their respective conjugates. Here, the acid is the proton donor, and the base is the proton acceptor. Conjugate pairs are directly linked by this proton exchange. This concept is essential to understand the relationship between acids and their conjugate bases, as well as bases and their conjugate acids.
Consider the reaction of nitric acid (\( \mathrm{HNO}_3 \)) with water \( (\mathrm{H}_2O) \). \( \mathrm{HNO}_3 \) donates a proton to \( \mathrm{H}_2O \), creating \( \mathrm{NO}_3^- \) and \( \mathrm{H}_3O^+ \):
Consider the reaction of nitric acid (\( \mathrm{HNO}_3 \)) with water \( (\mathrm{H}_2O) \). \( \mathrm{HNO}_3 \) donates a proton to \( \mathrm{H}_2O \), creating \( \mathrm{NO}_3^- \) and \( \mathrm{H}_3O^+ \):
- \( \mathrm{HNO}_3 \) (acid) transforms into \( \mathrm{NO}_3^- \) (conjugate base)
- \( \mathrm{H}_2O \) (base) transforms into \( \mathrm{H}_3O^+ \) (conjugate acid)
Proton Transfer
Proton transfer is the heart of any acid-base reaction. It involves the movement of protons (\( \mathrm{H}^+ \)) from an acid to a base. This exchange alters the identity of the substances involved, creating new compounds as products.
Imagine the transfer between sulfurous acid ion \( (\mathrm{HSO}_4^-) \) and water. When \( \mathrm{HSO}_4^- \) donates its proton, it becomes \( \mathrm{SO}_4^{2-} \), while \( \mathrm{H}_2O \) acquires the proton, forming \( \mathrm{H}_3O^+ \). This kind of transfer shows how acids and bases modify each other:- Acids donate protons to become conjugate bases.- Bases accept protons to become conjugate acids.
These transfers are not confined to laboratory settings but occur in natural and industrial processes alike, influencing various chemical balances in ecosystems and human metabolism.
Imagine the transfer between sulfurous acid ion \( (\mathrm{HSO}_4^-) \) and water. When \( \mathrm{HSO}_4^- \) donates its proton, it becomes \( \mathrm{SO}_4^{2-} \), while \( \mathrm{H}_2O \) acquires the proton, forming \( \mathrm{H}_3O^+ \). This kind of transfer shows how acids and bases modify each other:- Acids donate protons to become conjugate bases.- Bases accept protons to become conjugate acids.
These transfers are not confined to laboratory settings but occur in natural and industrial processes alike, influencing various chemical balances in ecosystems and human metabolism.
Reaction Products
The culmination of proton transfers in acid-base reactions leads to the formation of distinct reaction products. These products are characterized by their conjugate acid-base nature, representing the chemical shift that occurs in the exchange.
In the reaction of hydronium ion \((\mathrm{H}_3O^+)\) with fluoride \((\mathrm{F}^-)\), the products are water \((\mathrm{H}_2O)\) and hydrogen fluoride \((\mathrm{HF})\):
Understanding reaction products helps in anticipating the impact of specific reactions, crucial for controlling chemical processes.
In the reaction of hydronium ion \((\mathrm{H}_3O^+)\) with fluoride \((\mathrm{F}^-)\), the products are water \((\mathrm{H}_2O)\) and hydrogen fluoride \((\mathrm{HF})\):
- \( \mathrm{H}_3O^+ \) gives up a proton to form \( \mathrm{H}_2O \) (conjugate base)
- \( \mathrm{F}^- \) accepts the proton to become \( \mathrm{HF} \) (conjugate acid)
Understanding reaction products helps in anticipating the impact of specific reactions, crucial for controlling chemical processes.
Other exercises in this chapter
Problem 1
Write the formula and give the name of the conjugate base of each of the following acids. (a) HCN (b) \(\mathrm{HSO}_{4}^{-}\) (c) HF
View solution Problem 2
Write the formula and give the name of the conjugate acid of each of the following bases. (a) \(\mathrm{NH}_{3}\) (b) \(\mathrm{HCO}_{3}^{-}\) (c) \(\mathrm{Br}
View solution Problem 4
What are the products of each of the following acid-base reactions? Indicate the acid and its conjugate base and the base and its conjugate acid. (a) \(\mathrm{
View solution Problem 5
Write balanced equations showing how the hydrogen oxalate ion, \(\mathrm{HC}_{2} \mathrm{O}_{4}^{-},\) can be both a Bronsted acid and a Bronsted base.
View solution