Problem 3
Question
Use the Integral Test to determine if the series in Exercises \(1-10\) converge or diverge. Be sure to check that the conditions of the Integral Test are satisfied. $$ \sum_{n=1}^{\infty} \frac{1}{n^{2}+4} $$
Step-by-Step Solution
Verified Answer
The series converges by the Integral Test.
1Step 1: Identify function for Integral Test
First, identify the function corresponding to the series terms. The series \( \sum_{n=1}^{\infty} \frac{1}{n^2 + 4} \) corresponds to the function \( f(x) = \frac{1}{x^2 + 4} \).
2Step 2: Check conditions for Integral Test
Ensure that the function \( f(x) = \frac{1}{x^2 + 4} \) is positive, continuous, and decreasing for \( x \geq 1 \). We know that \( f(x) > 0 \) and it is continuous for all \( x > 0 \), particularly for \( x \geq 1 \). To check if it is decreasing, compute the derivative and ensure it is non-positive.
3Step 3: Compute the derivative to check decreasing nature
Calculate the derivative of \( f(x) = \frac{1}{x^2 + 4} \). Using the quotient rule, we find \( f'(x) = -\frac{2x}{(x^2 + 4)^2} \). Since \( -\frac{2x}{(x^2 + 4)^2} \leq 0 \) for \( x \geq 1 \), the function is decreasing.
4Step 4: Set up the integral
The Integral Test involves evaluating the improper integral \( \int_{1}^{\infty} \frac{1}{x^2 + 4} \, dx \). If this integral converges, so does the series, and vice versa.
5Step 5: Evaluate the improper integral
To solve \( \int_{1}^{\infty} \frac{1}{x^2 + 4} \, dx \), recognize it as an arctangent integral. It evaluates to \( \frac{1}{2} \left[ \arctan\left(\frac{x}{2}\right) \right]_1^{\infty} \), which simplifies to \( \frac{\pi}{4} - \frac{1}{2} \arctan\left(\frac{1}{2}\right) \). This converges since both terms are finite.
6Step 6: Conclude using the Integral Test
Since the integral \( \int_{1}^{\infty} \frac{1}{x^2 + 4} \, dx \) converges, by the Integral Test, the series \( \sum_{n=1}^{\infty} \frac{1}{n^2 + 4} \) also converges.
Key Concepts
Series ConvergenceImproper IntegralsDerivative Calculation
Series Convergence
When tackling problems related to the convergence or divergence of a series, the Integral Test is a useful tool. In the realm of series, convergence means that as you keep adding more and more terms, the sum approaches a finite value. For the series \( \sum_{n=1}^{\infty} \frac{1}{n^{2}+4} \), we use the corresponding continuous function \( f(x) = \frac{1}{x^2 + 4} \) to help analyze its behavior.
By determining if this function starts positive, stays continuous, and decreases as \( x \) increases, we satisfy the basic conditions required for the Integral Test.
By determining if this function starts positive, stays continuous, and decreases as \( x \) increases, we satisfy the basic conditions required for the Integral Test.
- The function must be positive because each term of the series is positive.
- Continuity is crucial, as a break can lead to unpredictable sums.
- Lastly, the function should symmetrically decrease, ensuring a downward sloping trend.
Improper Integrals
An improper integral extends the concept of definite integrals to cases where the interval of integration is infinite, or where the function has undefined areas within the range. For an integral like \( \int_{1}^{\infty} \frac{1}{x^2 + 4} \, dx \), the range of integration could infinitely extend to include all values starting from 1 onwards, thereby termed as an improper integral.
- In practice, such integrals assist in determining the ultimate behavior of series through the Integral Test.
- To evaluate an improper integral, break it down into simpler functions with known integral results, such as recognizing \( \frac{1}{x^2 + 4} \) as a derivation of the arctangent function.
- The solution, obtained through calculated limits, informs us if the series converges based on whether the integral result is finite or infinite.
Derivative Calculation
To determine if the expression \( \frac{1}{x^2 + 4} \) consistently decreases, calculating its derivative is essential. This step ensures the suitability of the function for the Integral Test, impacting the decision on convergence.
We'll use the quotient rule, a calculus method used when calculating the derivative of a ratio of two functions. This is vital when the function isn't a simple polynomial.
We'll use the quotient rule, a calculus method used when calculating the derivative of a ratio of two functions. This is vital when the function isn't a simple polynomial.
- The function's derivative \( f'(x) = -\frac{2x}{(x^2 + 4)^2} \) was computed through the quotient rule.
- Given \( f'(x) \leq 0 \) for \( x \geq 1 \), it demonstrates that the function decreases consistently.
- A decreasing function suggests that the elements of the series diminish, which is supportive of a converging sum.
Other exercises in this chapter
Problem 3
In Exercises \(1-36\) , (a) find the series' radius and interval of convergence. For what values of \(x\) does the series converge (b) absolutely, (c) condition
View solution Problem 3
Use the Comparison Test to determine if each series converges or diverges. \begin{equation}\sum_{n=2}^{\infty} \frac{1}{\sqrt{n}-1}\end{equation}
View solution Problem 3
In Exercises \(1-6,\) find a formula for the \(n\) th partial sum of each series and use it to find the series' sum if the series converges. $$ 1-\frac{1}{2}+\f
View solution Problem 3
Each of Exercises \(1-6\) gives a formula for the \(n\) th term \(a_{n}\) of a sequence \(\left\\{a_{n}\right\\} .\) Find the values of \(a_{1}, a_{2}, a_{3},\)
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