Problem 3
Question
Use either Gaussian elimination or Gauss-Jordan elimination to solve the given system or show that no solution exists. \(9 x_{1}+3 x_{2}=-5\) \(2 x_{1}+x_{2}=-1\)
Step-by-Step Solution
Verified Answer
The system of equations has no solution.
1Step 1: Write the System of Equations in Augmented Matrix Form
The given system of equations is \( 9x_1 + 3x_2 = -5 \) and \( 2x_1 + x_2 = -1 \). First, write this system as an augmented matrix:\[\begin{bmatrix}9 & 3 & | & -5 \2 & 1 & | & -1\end{bmatrix}\]
2Step 2: Perform Row Operations to Achieve Row Echelon Form
To eliminate the first term of the second equation, multiply the first row by \(2\) and the second row by \(9\) and subtract the second row from the first row.\( 2R_1 - 9R_2 \rightarrow R_1 \)This results in:\[\begin{bmatrix}0 & 0 & | & 1 \2 & 1 & | & -1 \end{bmatrix}\]
3Step 3: Interpret the Result
The row operation has led to a row of the form \( \begin{bmatrix} 0 & 0 & | & 1 \end{bmatrix} \) in the matrix. This indicates an inconsistency, meaning that the system of equations does not have a solution.
Key Concepts
Gauss-Jordan eliminationAugmented matrixRow echelon formSystem of equations
Gauss-Jordan elimination
Gauss-Jordan elimination is a method used to solve systems of linear equations. It involves performing row operations on an augmented matrix to transform it into reduced row echelon form (RREF). When this form is achieved, the solutions to the system are readily apparent.
Row operations include:
Row operations include:
- Swapping two rows
- Multiplying a row by a non-zero scalar
- Adding or subtracting a multiple of one row to another
Augmented matrix
An augmented matrix is a streamlined way to represent a system of linear equations. It combines the coefficients of the variables with the constants from the right side of the equations into a single matrix. This makes it easier to apply row operations and manipulate the equations systematically.
For a system:
For a system:
- 9x1 + 3x2 = -5
- 2x1 + x2 = -1
Row echelon form
Row echelon form (REF) is a key stage in solving systems of equations using matrix methods. A matrix is in row echelon form when:
- All non-zero rows are above any rows of all zeros.
- The leading coefficient (first non-zero number from the left, also called a pivot) of a non-zero row is always strictly to the right of the leading coefficient of the row above it.
- All entries in a column below a pivot are zeros.
System of equations
A system of equations refers to a set of equations with multiple variables that are solved simultaneously. The aim is to find values for the variables that satisfy all the equations at once. There are three possible outcomes:
- A unique solution, where one specific set of values satisfies all equations.
- Infinitely many solutions, where several sets of values can satisfy the equations.
- No solution, indicating the equations are inconsistent and cannot be satisfied by any set of values.
Other exercises in this chapter
Problem 3
Solve the given system of equations by Cramer's rule. $$ \begin{aligned} 0.1 x_{1}-0.4 x_{2} &=0.13 \\ x_{1}-\quad x_{2} &=0.4 \end{aligned} $$
View solution Problem 3
Suppose $$ \mathbf{A}=\left(\begin{array}{rrr} 2 & 3 & 4 \\ 1 & -1 & 2 \\ -2 & 3 & 5 \end{array}\right) $$ Evaluate the indicated minor determinant or cofactor.
View solution Problem 3
State the size of the given matrix. $$ \left(\begin{array}{rrr} 1 & 2 & -1 \\ 0 & 7 & -2 \\ 0 & 0 & 5 \end{array}\right) $$
View solution Problem 3
In Problems 1-20, fill in the blanks or answer true/false. If \(\mathbf{A}=\left(\begin{array}{l}1 \\ 2\end{array}\right)\) and \(\mathbf{B}=\left(\begin{array}
View solution