Problem 3
Question
Two in-phase sources of waves are separated by a distance of \(4.00 \mathrm{~m}\). These sources produce identical waves that have a wave length of \(5.00 \mathrm{~m}\). On the line between them, there are two places at which the same type of interference occurs. (a) Is it constructive or destructive interference, and (b) where are the places located?
Step-by-Step Solution
Verified Answer
(a) Constructive. (b) At the midpoint and two equal parts at half of 4.0 m.
1Step 1: Understand Interference Types
In-phase sources can produce either constructive or destructive interference based on their path difference. Constructive interference occurs when the path difference is a multiple of the wavelength. Destructive interference happens when the path difference is an odd multiple of half the wavelength.
2Step 2: Determine the Type of Interference
Given the sources are in-phase and the problem states two places of the same type of interference occur, it's more likely to be constructive interference as this occurs at both integer multiples and half-integer multiples. Destructive interference would require the sources to be half a wavelength apart, which doesn't align well with the scenario provided repeatedly.
3Step 3: Calculate Potential Positions for Constructive Interference
The general condition for constructive interference is that the path difference is a multiple of the wavelength \( n\lambda \). Given that \( \lambda = 5.00 \text{ m} \), we are looking for positions \( x \) such that the path difference \( |r_1 - r_2| = n \times 5.00 \text{ m} \).
4Step 4: Use Geometric Symmetry for Source Positions
We know the two sources are \(4.00 \text{ m}\) apart. Let's place one source at \(0\) and the other at \(4.00\). This means a point \( x \) experiences a path difference of \( |x| + |4.00 - x| = 4.00 \). For constructive interference, the path difference should be \(0, 5.00, 10.00, ...\).
5Step 5: Conclude Location of Constructive Interference
For \( |x| + |4.00 - x| = 4.00\), possible values of \(x\) which result in multiples of \(5.00\) are symmetry points: the middle point and the ends of the spread where the simplest constructive interference case \(0\) difference happens due to the setup. There will be constructive interference at these points.
Key Concepts
Constructive InterferenceDestructive InterferencePath DifferenceWave SourcesWavelength
Constructive Interference
Constructive interference occurs when waves from two sources align in such a way that their amplitudes add together. This happens when the path difference between the waves is a multiple of the wavelength.
This means their peaks (crests) and troughs (valleys) sync up perfectly, creating a larger wave.
This means their peaks (crests) and troughs (valleys) sync up perfectly, creating a larger wave.
- Path difference: multiple of the wavelength \,\( n\lambda \).
- Results in a wave with increased amplitude.
Destructive Interference
Destructive interference occurs when two waves meet and effectively cancel each other out. This happens when the path difference between them is an odd multiple of half the wavelength.
In this case, the crest of one wave meets the trough of another, leading to reduced or zero amplitude.
In this case, the crest of one wave meets the trough of another, leading to reduced or zero amplitude.
- Path difference: odd multiple of half the wavelength \,\( (n+1/2)\lambda \).
- Results in a wave with decreased or nullified amplitude.
Path Difference
Path difference is a crucial concept when discussing wave interference. It refers to the difference in the distance traveled by two waves from their sources to a particular point.
The path difference determines the type of interference - whether constructive or destructive.
The path difference determines the type of interference - whether constructive or destructive.
- If the path difference is a whole number multiple of the wavelength \,\( n\lambda \), constructive interference happens.
- If it's an odd multiple of half the wavelength \,\( (n+1/2)\lambda \), destructive interference occurs.
Wave Sources
Wave sources are locations or points from which waves originate. The behavior of these waves as they travel depends significantly on the attributes of the sources, including phase and distance between them.
Let's break down some key aspects:
Let's break down some key aspects:
- Phase: Sources in phase produce waves that are synchronized. These waves have crests and troughs that line up, making interference analysis straightforward, particularly when identifying patterns such as constructive interference.
- Separation Distance: The distance affects potential path differences, determining what kind of interference occurs—constructive or destructive.
Wavelength
Wavelength is the distance between successive crests, troughs, or identical points of a wave. It is a fundamental property that influences wave behavior and interference.
Measured in meters (or other units of length), wavelength links directly to path difference and thus dictating the interference type.
Measured in meters (or other units of length), wavelength links directly to path difference and thus dictating the interference type.
- A larger wavelength means waves will overlap over greater distances before repeating, affecting the location of interference patterns.
- Given \,\( \lambda = 5.00 \, \text{m} \) in this exercise, this determines the points at which waves constructively interfere based on integer multiples.
Other exercises in this chapter
Problem 1
In a Young's double-slit experiment, the angle that locates the second-order bright fringe is \(2.0^{\circ} .\) The slit separation is \(3.8 \times 10^{-5} \mat
View solution Problem 2
In a Young's double-slit experiment, the wavelength of the light used is \(520 \mathrm{nm}\) (in vacuum), and the separation between the slits is \(1.4 \times 1
View solution Problem 4
The dark fringe for \(m=0\) in a Young's double-slit experiment is located at an angle of \(\theta=15^{\circ} .\) What is the angle that locates the dark fringe
View solution Problem 5
A flat observation screen is placed at a distance of \(4.5 \mathrm{~m}\) from a pair of slits. The separation on the screen between the central bright fringe an
View solution