Problem 3
Question
The temperature of the soil is \(30^{\circ} \mathrm{C}\) at the surface and decreases by \(0.04^{\circ} \mathrm{C}\) for each centimeter below the surface. Express temperature \(T\) as a function of depth \(d\), in centimeters, below the surface.
Step-by-Step Solution
Verified Answer
Answer: T(d) = -0.04d + 30
1Step 1: Identify the initial temperature
The initial temperature (\(T_0\)) is given at the surface, which is \(30^{\circ} \mathrm{C}\).
2Step 2: Determine the slope
The rate at which the temperature decreases for every centimeter below the surface is constant, and it is given as \(0.04^{\circ} \mathrm{C}\) per centimeter. Since temperature decreases as we go deeper, the slope will be negative, so the slope (m) is \(-0.04^{\circ} \mathrm{C}\) per centimeter.
3Step 3: Define the linear function
We can express the temperature (T) as a linear function of depth (d) using the general form of a linear equation: \(T = m \cdot d + T_0\). Here, m is the slope and \(T_0\) is the initial temperature.
4Step 4: Substitute the slope and initial temperature
By substituting the slope and initial temperature into the linear equation, we get the function that describes the temperature as a function of depth:
\(T(d) = -0.04d + 30\).
Now, we have the desired function that models the temperature (T) based on the depth (d) below the surface.
Key Concepts
Temperature GradientDepth and Temperature RelationshipLinear Equations in Real-World Contexts
Temperature Gradient
The term "temperature gradient" describes how temperature changes over a specific distance. In our soil example, the temperature gradient speaks to the change in soil temperature as we move deeper beneath the surface. Here, the gradient is expressed as \(-0.04^{\circ} \text{C per centimeter}\). This means for every centimeter you delve into the soil, the temperature decreases by \(-0.04^{\circ} \text{C}\). Remember, a negative sign in this context indicates a decrease in temperature. For students working with temperature gradients, it's useful to:
- Identify whether the gradient is increasing or decreasing.
- Consider the physical implications of these changes in temperature, be it in soil, water, or air.
- Use units like °C/cm to clearly understand the rate of change.
Depth and Temperature Relationship
The relationship between depth and temperature is linear and directly represented by our equation \(T(d) = -0.04d + 30\). As depth \(d\) increases, the temperature \(T\) systematically decreases. This relationship highlights one of the crucial aspects of linear equations: each unit change in \(d\) results in a consistent and predictable change in temperature.Visualizing this:
- The starting point or y-intercept is at the surface temperature of \(30^{\circ} \text{C}\).
- With increasing depth, the temperature drops at a steady rate indicated by the slope \(-0.04^{\circ} \text{C per centimeter}\).
- This linear pattern holds true unless other environmental conditions cause deviations.
Linear Equations in Real-World Contexts
Linear equations often find themselves at the heart of real-world problem-solving because of their simplicity and predictability. In many situations, like our soil temperature example, linear equations model natural phenomena where there is a constant rate of change.
Real-world scenarios where linear equations are applicable include:
- Weather prediction models that guess temperature changes over time or space.
- Economics, where linear relationships model supply and demand or cost predictions based on time.
- Physics, describing constant velocity motion where distance increases linearly with time.
Other exercises in this chapter
Problem 3
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