Problem 3
Question
The graph of the equation \((x-1)^{2}+(y-2)^{2}=9\) is a circle with center (_____,_____) and radius _____.
Step-by-Step Solution
Verified Answer
Center: (1, 2); Radius: 3.
1Step 1: Identify the Standard Form
The standard form of the equation of a circle is \((x-h)^2 + (y-k)^2 = r^2\), where \((h, k)\) is the center of the circle and \(r\) is the radius.
2Step 2: Extract the Center Coordinates
Compare the given equation \((x-1)^2 + (y-2)^2 = 9\) to the standard form. From this, we identify the values of \(h\) and \(k\). Here, \(h = 1\) and \(k = 2\).
3Step 3: Center of the Circle
So, the center of the circle is at \((h, k)\) = \((1, 2)\).
4Step 4: Calculate the Radius
The right side of the circle equation gives \(r^2 = 9\). Thus, we find \(r\) by taking the square root: \(r = \sqrt{9}\).
5Step 5: Determine the Radius Value
\(r = \sqrt{9} = 3\), so the radius of the circle is 3.
Key Concepts
Standard Form of a CircleCenter of a CircleRadius of a Circle
Standard Form of a Circle
The equation of a circle can be conveniently expressed in its standard form. This form is:
Recognizing this standard form lets you instantly match any circle equation to these key pieces of information.
- \((x-h)^2 + (y-k)^2 = r^2\)
- \((h, k)\) represents the coordinates of the center of the circle,
- \(r\) denotes the radius of the circle.
Recognizing this standard form lets you instantly match any circle equation to these key pieces of information.
Center of a Circle
The center of a circle is a crucial point that defines its position on the coordinate plane. In the standard form of a circle's equation
For example, when you compare \((x-1)^2 + (y-2)^2 = 9\) to the standard form, it is clear that
- \((x-h)^2 + (y-k)^2 = r^2\)
- \((h, k)\)
For example, when you compare \((x-1)^2 + (y-2)^2 = 9\) to the standard form, it is clear that
- \(h = 1\),
- \(k = 2\).
- \((1, 2)\).
Radius of a Circle
The radius of a circle is the distance from its center to any point on its circumference. It is one of the most fundamental features as it describes the size of the circle. In the equation
To determine the radius from an equation, you must first identify the value of \(r^2\). Taking the equation \((x-1)^2 + (y-2)^2 = 9\), we see that
The radius is not just a mere number; it is a measurement that dictates the spread of the circle. It helps in calculating other properties such as the area and circumference of the circle.
Knowing how to derive and apply the radius will significantly aid in solving more complex geometric problems involving circles.
- \((x-h)^2 + (y-k)^2 = r^2\),
To determine the radius from an equation, you must first identify the value of \(r^2\). Taking the equation \((x-1)^2 + (y-2)^2 = 9\), we see that
- \(r^2 = 9\).
- \(r = \sqrt{9} = 3\).
The radius is not just a mere number; it is a measurement that dictates the spread of the circle. It helps in calculating other properties such as the area and circumference of the circle.
Knowing how to derive and apply the radius will significantly aid in solving more complex geometric problems involving circles.
Other exercises in this chapter
Problem 2
If x is negative and y is positive, then the point (x, y) is in Quadrant ________.
View solution Problem 3
The point-slope form of the equation of the line with slope 3 passing through the point \((1,2)\) is _______
View solution Problem 3
The distance between the points \((a, b)\) and \((c, d)\) is ________. So the distance between \((1,2)\) and \((7,10)\) is ________.
View solution Problem 4
(a) The slope of a horizontal line is _______ The equation of the horizontal line passing through \((2,3)\) is (b) The slope of a vertical line is ________ The
View solution