Problem 3
Question
$$ \underline{\phantom{xxx}} \text { find } D_{x} y . $$ $$ y=\sin ^{2} x+\cos ^{2} x $$
Step-by-Step Solution
Verified Answer
The derivative \(D_x y\) is 0.
1Step 1: Recognize Trigonometric Identity
The given expression is \(y = \sin^2 x + \cos^2 x\). We recognize that \(\sin^2 x + \cos^2 x = 1\) is a fundamental trigonometric identity.
2Step 2: Differentiate Using Constant Rule
The function \(y = 1\) is a constant function since \(\sin^2 x + \cos^2 x\) always equals 1. The derivative of any constant function is zero. Therefore, \(D_x y = 0\).
Key Concepts
Trigonometric IdentitiesDerivative of Constant FunctionStep-by-Step Calculus Solutions
Trigonometric Identities
Trigonometric identities are essential tools in simplifying and solving many calculus problems. These identities express relationships between the basic trigonometric functions: sine, cosine, tangent, etc. One of the most fundamental and widely used identities is \[\sin^2 x + \cos^2 x = 1\]This identity is known as the Pythagorean identity. It is derived from the Pythagorean theorem and helps in simplifying expressions involving squared sine and cosine functions.
- The Pythagorean identity is helpful because it simplifies complex trigonometric expressions.
- It verifies trigonometric equations by reducing them to simpler forms.
- This identity is crucial when dealing with derivatives or integrals in calculus.
Derivative of Constant Function
The concept of differentiation involves finding how a function changes as its input changes. However, when we deal with constant functions, things are much simpler. A constant function doesn't change, so its derivative is always zero.In the given problem, after applying the trigonometric identity, we are left with the constant function \(y = 1\).Differentiation rules tell us that the derivative of a constant value \(c\) is \(D_x c = 0\). This means the rate at which the constant value changes is zero.When you differentiate:
- Look for any parts of the expression that simplify to constants.
- Recall that the derivative of any constant, like our simplified \(1\), is always 0.
- This applies universally, no matter the input variable.
Step-by-Step Calculus Solutions
Step-by-step calculus solutions provide a clear path for solving complex problems. They break down a problem into manageable parts, allowing you to follow the logical progression of thought needed to arrive at the solution. Here's how you can use step-by-step solutions effectively:1. **Identify Recognizable Patterns:** Look for fundamental identities or simplifications, like the Pythagorean identity \(\sin^2 x + \cos^2 x = 1\).2. **Apply Relevant Rules:** Once simplified, apply calculus concepts, such as the derivative of a constant, to find the answer. Remember, \(D_x y = 0\) for constant functions.3. **Cross-Verify:** After solving, cross-verify each step to ensure validity and correctness. This not only helps in understanding the solution but also reinforces learning.By practicing these strategies, you'll enhance your problem-solving skills in calculus. Solutions derived step-by-step can lead to better comprehension and retention of mathematical concepts.
Other exercises in this chapter
Problem 3
Find \(d^{3} y / d x^{3}\). $$ y=(3 x+5)^{3} $$
View solution Problem 3
Find \(D_{x} y\). $$ y=(3-2 x)^{5} $$
View solution Problem 3
Find \(D_{x} y\) using the rules of this section. $$ y=\pi x $$
View solution Problem 3
Use the definition $$f^{\prime}(c)=\lim _{h \rightarrow 0} \frac{f(c+h)-f(c)}{h}$$ to find the indicated derivative. $$ f^{\prime}(3) \text { if } f(t)=t^{2}-t
View solution