Problem 3
Question
Suppose that the natural cubic spline \(s_{2}\) interpolates the function \(f: x \mapsto x^{3}\) on the interval \([0,1]\), the knots being equally spaced, so that \(x_{i}=i h, i=0,1, \ldots, m\), with \(h=1 / m, m \geq 2\). Write down the equations which determine the quantities \(\sigma_{i} .\) If the two additional conditions are \(\sigma_{0}=\sigma_{m}=0\), show that these equations are not satisfied by \(\sigma_{i}=f^{\prime \prime}\left(x_{i}\right), i=1, \ldots, m-1\), so that \(s_{2}\) and \(f\) are not identical. If, however, these two additional conditions are replaced by \(\sigma_{0}=f^{\prime \prime}(0), \sigma_{m}=f^{\prime \prime}(1)\), show that \(\sigma_{i}=f^{\prime \prime}\left(x_{i}\right), i=0,1, \ldots, m\), and deduce that \(s_{2}\) and \(f\) are identical.
Step-by-Step Solution
VerifiedKey Concepts
Natural Cubic Spline
In essence, a natural cubic spline aims to create the most relaxed curve possible given the constraints, resembling how a beam bends under its own weight. Its primary purpose is to preserve smoothness, lowering the chances of creating overly complex curves.
Boundary Conditions
In practice, different boundary conditions can significantly change the form of the spline. If the standard natural spline conditions (\(\sigma_0 = \sigma_m = 0\)) cause a mismatch with the function you're interpolating, it's sometimes necessary to adjust them to match the known values of the second derivatives, like setting \(\sigma_0\) and \(\sigma_m\) to known derivatives of the function at the endpoints.
Second Derivative
The second derivative condition is critical because it not only links the function's curvature but also influences the selection of boundary conditions. In the exercise you're studying, it's important to compute these derivatives accurately to ensure that the interpolated spline correctly reflects the function's properties.
Equally Spaced Knots
The idea is to create a uniform grid over the interpolation interval, making calculations more straightforward and balancing accuracy across all segments. For the function \(f(x) = x^3\) in the exercise example, the knots were placed at \(x_i = i \cdot h\) where \(h = \frac{1}{m}\), providing a systematic approach to creating the spline and ensuring that no segment is unnecessarily extended or shortened.