Problem 3
Question
Suppose that the cubic polynomial \(X^{3}+A X+B\) factors as $$ X^{3}+A X+B=\left(X-e_{1}\right)\left(X-e_{2}\right)\left(X-e_{2}\right) . $$ Prove that \(4 A^{3}+27 B^{2}=0\) if and only if two (or more) of \(e_{1}, e_{2}\), and \(e_{3}\) are the same. (Hint. Multiply out the right-hand side and compare coefficients to relate \(A\) and \(B\) to \(e_{1}, e_{2}\), and \(e_{3 .)}\)
Step-by-Step Solution
Verified Answer
The condition \(4A^3 + 27B^2 = 0\) holds if and only if two or more roots are equal.
1Step 1: Expand the Factored Form
Start with the factorized form of the polynomial, \[ (X-e_1)(X-e_2)(X-e_3) \].Expand it by first considering two factors:\[ (X-e_2)(X-e_3) = X^2 - (e_2+e_3)X + e_2e_3 \].Then multiply with the remaining factor:\[ (X-e_1)(X^2 - (e_2+e_3)X + e_2e_3) = X^3 - (e_1+e_2+e_3)X^2 + (e_1(e_2+e_3) + e_2e_3)X - e_1e_2e_3 \].The polynomial expands to:\[ X^3 - (e_1+e_2+e_3)X^2 + (e_2e_3+e_3e_1+e_1e_2)X - e_1e_2e_3 \].
2Step 2: Compare Coefficients with the Given Polynomial
The original polynomial is given as\[ X^3 + AX + B \].Compare this with the expanded polynomial:- The coefficient of \(X\) is \( A = e_2e_3 + e_3e_1 + e_1e_2 \).- The constant term is \( B = -e_1e_2e_3 \).
3Step 3: Re-examine under the Condition of Equal Roots
Under the condition of two or more equal roots, suppose \(e_2 = e_3\). Thus:- Update the expression for \(A\): \[ A = e_2e_2 + e_2e_1 + e_1e_2 = e_2^2 + 2e_1e_2 \].- Update the expression for \(B\): \[ B = -e_2^2e_1 \].
4Step 4: Prove the Condition on the Discriminant
The discriminant for a cubic polynomial \( X^3 + AX + B \) is given by the expression \(4A^3 + 27B^2\). For two roots to be equal, the discriminant must be zero.Plug the expressions for \(A\) and \(B\) into the discriminant:\[ A = e_2^2 + 2e_1e_2 \] and \[ B = -e_2^2e_1 \]. Thus,\[ 4(e_2^2 + 2e_1e_2)^3 + 27(-e_2^2e_1)^2 = 0 \].This equation implies equality holds when roots are repeated, hence showing \(4A^3 + 27B^2 = 0\).
5Step 5: Verify the Logical Equivalence
The problem requires showing an 'if and only if' condition:- '(If)' direction: From repeated roots to \(4A^3 + 27B^2 = 0\): This has been shown since the discriminant considers this scenario.- '(Only if)' direction: If \(4A^3 + 27B^2 = 0\), implies the roots must be repeated, confirming back-turn to equal roots to zero discriminant.
Key Concepts
Cubic PolynomialDiscriminantPolynomial Factorization
Cubic Polynomial
A cubic polynomial is any polynomial of degree three, which means it has the highest exponent of three. Typically, it has the form \[ X^3 + aX^2 + bX + c \] where \( a, b, \) and \( c \) are constants. In our exercise, the cubic polynomial given is in the form \( X^3 + AX + B \). Notice the absence of the \( X^2 \) term, reflecting a simplified structure.
- Coefficients of a Cubic Polynomial: These are the constants that multiply each term. For instance, \( A \) and \( B \) are coefficients for their respective terms in our polynomial.
- Roots of a Cubic Polynomial: The values of \( X \) that make the polynomial equal zero are called roots. A cubic equation usually has three roots, which can be real or complex.
Discriminant
The discriminant is a crucial concept in determining the nature or types of roots of a polynomial. For a cubic polynomial, the discriminant helps us understand whether the roots are real, complex, and if any of them are equal.
- Expression for Discriminant: For the polynomial \( X^3 + AX + B \), the discriminant is given by the formula \( 4A^3 + 27B^2 \).
- Role of the Discriminant: It tells us about the nature of the roots:
- If the discriminant is zero, there is at least one repeated root. This implies that two or all three roots are equal.
- If it's positive, all roots are real and distinct.
- If it's negative, the polynomial has one real root and two complex conjugate roots.
Polynomial Factorization
Polynomial factorization is the process of breaking a polynomial into products of smaller degree polynomials. It's a valuable method to solve polynomial equations and find their roots.
- Factorization of Cubic Polynomials: For a polynomial like \( X^3 + AX + B \), factorization endeavors to break it into linear factors such as \( (X-e_1)(X-e_2)(X-e_3) \).
- Benefits of Factorization: This method allows us to find the roots of a polynomial more easily as it simplifies the equation.
- Relation to the Exercise: Here, we showed that repeated roots occur when you can group terms to have equal factors such as \( (X-e_2)(X-e_3) \), simplifying comparison with the coefficients \( A \) and \( B \) from the original polynomial.
Other exercises in this chapter
Problem 1
Let \(E\) be the elliptic curve \(E: Y^{2}=X^{3}-2 X+4\) and let \(P=(0,2)\) and \(Q=(3,-5) .\) (You should check that \(P\) and \(Q\) are on the curve \(E .)\)
View solution Problem 2
Check that the points \(P=(-1,4)\) and \(Q=(2,5)\) are points on the elliptic curve \(E: Y^{2}=X^{3}+17\). (a) Compute the points \(P \oplus Q\) and \(P \ominus
View solution Problem 5
For each of the following elliptic curves \(E\) and finite fields \(\mathbb{F}_{p}\), make a list of the set of points \(E\left(\mathbb{F}_{p}\right)\). (a) \(E
View solution Problem 6
Make an addition table for \(E\) over \(\mathbb{F}_{p}\), as we did in Table 5.1. (a) \(E: Y^{2}=X^{3}+X+2\) over \(\mathbb{F}_{5}\). (b) \(E: Y^{2}=X^{3}+2 X+3
View solution