Problem 3
Question
Spring constant It took 1800 \(\mathrm{J}\) of work to stretch a spring from its natural length of 2 \(\mathrm{m}\) to a length of 5 \(\mathrm{m} .\) Find the spring's force constant.
Step-by-Step Solution
Verified Answer
The spring's force constant is 400 N/m.
1Step 1: Understand Hooke's Law
Hooke's Law states that the force exerted by a spring is proportional to the displacement from its natural length, given by the equation \( F = kx \), where \( F \) is the force, \( k \) is the spring constant, and \( x \) is the displacement.
2Step 2: Calculate Displacement
The displacement \( x \) is the change in the spring's length from its natural length. Here, the spring is stretched from 2 meters to 5 meters, so \( x = 5 - 2 = 3 \) meters.
3Step 3: Use Work-Energy Principle for Springs
The work done on the spring is calculated using the work-energy principle for springs, which is given by the equation \( W = \frac{1}{2}kx^2 \). Here, \( W = 1800 \) J and \( x = 3 \) meters.
4Step 4: Solve for the Spring Constant
Plug the known values into the work-energy formula: \( 1800 = \frac{1}{2}k(3)^2 \). Simplifying gives \( 1800 = \frac{1}{2}k \times 9 \).
5Step 5: Calculate the Value of k
To find \( k \), rearrange the equation to isolate \( k \): \( 1800 = 4.5k\). Solve for \( k \) by dividing both sides by 4.5: \( k = \frac{1800}{4.5} = 400 \) N/m.
Key Concepts
Hooke's LawWork-Energy PrincipleDisplacement
Hooke's Law
Hooke's Law is a fundamental principle in physics that defines how a spring behaves when it is either compressed or stretched. This law is epitomized by the equation:\[ F = kx \]where:
- \( F \) represents the force exerted by the spring.
- \( k \) stands for the spring constant, a measure of the stiffness of the spring.
- \( x \) is the displacement, or how far the spring has been stretched or compressed from its natural length.
Work-Energy Principle
The work-energy principle in the context of springs provides a powerful way to relate the work done on a spring to its displacement. According to this principle, the work done on a spring is stored as potential energy within the spring. The formula central to this concept when dealing with springs is:\[ W = \frac{1}{2} k x^2 \]where:
- \( W \) is the work done in joules.
- \( k \) is the spring constant.
- \( x \) is the displacement.
Displacement
Displacement in the context of springs refers to how much the spring is elongated or compressed from its original, natural length. It is a critical factor in both Hooke's Law and the work-energy principle.In the example provided, the displacement \( x \) can be calculated by taking the difference between the new length of the spring and its original length:\[ x = \text{new length} - \text{natural length} \]So, if a spring originally measures 2 meters and is stretched to 5 meters, the displacement is:\[ x = 5 - 2 = 3 \text{ meters} \]Knowing the displacement is essential because it directly influences both the force exerted by the spring and the work done on the spring. It serves as a link between the physical elongation/compression of the spring and the mathematical expressions used to describe the spring's behavior.
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