Problem 3
Question
Solve each system of equations by the substitution method. $$ \left\\{\begin{array}{l} x+y=6 \\ y=-3 x \end{array}\right. $$
Step-by-Step Solution
Verified Answer
The solution to the system is \( x = -3 \) and \( y = 9 \).
1Step 1: Solve One Equation for One Variable
The system of equations is: \( x+y=6 \) and \( y=-3x \) . We notice that the second equation \( y = -3x \) already gives \( y \) in terms of \( x \).
2Step 2: Substitute the Expression into the Other Equation
Substitute \( y = -3x \) from the second equation into the first equation \( x + y = 6 \). This gives us \( x + (-3x) = 6 \).
3Step 3: Simplify and Solve for One Variable
Simplify the substituted equation: \( x - 3x = 6 \), which simplifies to \( -2x = 6 \). Divide both sides by \(-2\) to solve for \( x \): \( x = -3 \).
4Step 4: Substitute Back to Find the Other Variable
Now that we have \( x = -3 \), substitute it back into \( y = -3x \) to find \( y \). This gives us \( y = -3(-3) = 9 \).
5Step 5: Verify the Solution
Check the solution \((x, y) = (-3, 9)\) by plugging \( x = -3 \) and \( y = 9 \) back into the original equations: \( -3 + 9 = 6 \) which holds true, and \( 9 = -3(-3) \) which also holds true.
Key Concepts
System of EquationsSolve EquationsAlgebraic ManipulationVerification of Solution
System of Equations
A system of equations consists of two or more equations with the same set of variables. These equations need to be solved together to find a common solution. In our original exercise, we have a system of two equations:
- Equation 1: \( x+y=6 \)
- Equation 2: \( y=-3x \)
Solve Equations
Solving equations is the process of determining the values of variables that make the equations true. For solving the system of equations using the substitution method, we follow a systematic approach:1. **Understand the equations**: First, we recognize that equation 2, \( y = -3x \), already provides us with \(y\) expressed in terms of \(x\).
2. **Substitute known values**: Next, we substitute this expression for \(y\) into equation 1, \( x+y=6 \), allowing us to solve for \(x\) independently.
3. **Solve for one variable**: After substitution, we simplify and solve the remaining equation to find the value of \(x\).
4. **Find the other variable**: Finally, we revisit the substituted equation to solve for \(y\) using the value of \(x\) obtained in the earlier steps.This structured process helps in isolating variables, simplifying the task of solving complex systems.
2. **Substitute known values**: Next, we substitute this expression for \(y\) into equation 1, \( x+y=6 \), allowing us to solve for \(x\) independently.
3. **Solve for one variable**: After substitution, we simplify and solve the remaining equation to find the value of \(x\).
4. **Find the other variable**: Finally, we revisit the substituted equation to solve for \(y\) using the value of \(x\) obtained in the earlier steps.This structured process helps in isolating variables, simplifying the task of solving complex systems.
Algebraic Manipulation
Algebraic manipulation involves performing operations to transform equations into a more tractable form. This is crucial when using methods like substitution. In our solution:
- After substituting \(y = -3x\) into \(x + y = 6\), we perform operations to simplify the equation into \(-2x = 6\).
- Dividing both sides by \(-2\) allows us to solve for \(x\), yielding \(x = -3\).
Verification of Solution
Verification of the solution is an essential step to ensure the accuracy of the values obtained. This involves substituting the values of \(x\) and \(y\) back into the original equations to check if they hold true:
- Substituting \((x, y) = (-3, 9)\) into Equation 1: \( -3 + 9 = 6 \) confirms that the left side equals the right side.
- Similarly, substituting into Equation 2: \( 9 = -3(-3) \) also verifies each side of the equation is equivalent.
Other exercises in this chapter
Problem 2
An isosceles triangle, a triangle with two sides of equal length, has a perimeter of 20 inches. Each of the equal sides is one inch longer than the third side.
View solution Problem 3
Solve each system of equations by the addition method. $$ \left\\{\begin{array}{l} x-2 y=8 \\ -x+5 y=-17 \end{array}\right. $$
View solution Problem 3
Determine whether each ordered pair is a solution of the system of linear equations. See Examples 1 and \(2 .\) \(\left\\{\begin{array}{l}3 x-y=5 \\ x+2 y=11\en
View solution Problem 3
Two computer disks and three notebooks cost \(\$ 17\). However, five computer disks and four notebooks cost \(\$ 32\). Find the price of each. a. notebook \(=\$
View solution