Problem 3
Question
Solve each equation.. \((m+9)(m-8)=0\)
Step-by-Step Solution
Verified Answer
The values of \(m\) that satisfy the equation \((m+9)(m-8) = 0\) are \(m=-9\) and \(m=8\).
1Step 1: Apply the zero-product property
Since the product of the two factors \((m+9)(m-8)\) is equal to zero, we can set each factor equal to zero.
So, we have:
\(m+9=0\)
and
\(m-8=0\)
2Step 2: Solve the first equation
Solving the equation \(m + 9 = 0\) for \(m\):
Subtract 9 from both sides of the equation:
\(m=-9\)
3Step 3: Solve the second equation
Solving the equation \(m - 8 = 0\) for \(m\):
Add 8 to both sides of the equation:
\(m=8\)
4Step 4: Combine the solutions
We found the solutions \(m=-9\) and \(m=8\). These are the two values of \(m\) that will satisfy the quadratic equation \((m+9)(m-8) = 0\).
Key Concepts
Zero-Product PropertyFactoringSolving EquationsAlgebra
Zero-Product Property
The zero-product property is a fundamental concept in algebra that helps us solve quadratic equations. When two numbers multiply to zero, at least one of them must be zero. This means if you have an equation like
For instance, in our example,
- \[(a)(b) = 0\]
For instance, in our example,
- \((m+9)(m-8)=0\):
Factoring
Factoring is the process of breaking down an expression into products of simpler expressions, which we call factors. This is a key step in solving quadratic equations. By factoring a quadratic equation, we can use the zero-product property to find the variable values that make the equation true.
For example, given a quadratic in the form of
For example, given a quadratic in the form of
- \[ax^2 + bx + c = 0\]
- \[(x + p)(x + q) = 0\]
- \((m+9)(m-8)\)
Solving Equations
Solving equations involves finding the value(s) of the unknown variable(s) that make the equation true. In our context, we are solving for \(m\) in the factored quadratic equation
For
- \((m+9)(m-8) = 0\)
For
- \(m + 9 = 0\)
- \(m = -9\)
- \(m - 8 = 0\)
- \(m = 8\)
Algebra
Algebra is a branch of mathematics dealing with symbols and the rules for manipulating those symbols. It involves solving equations and understanding how different equations represent relationships between quantities. Quadratic equations, like the one in our exercise, are a common type of algebraic equation, characterized by containing an unknown raised to the second power.
- The general form is \[ax^2 + bx + c = 0\]
Other exercises in this chapter
Problem 3
Find the greatest common factor of each group of terms. $$42 k^{5}, 54 k^{7}, 72 k^{9}$$
View solution Problem 3
Fill in the blank with a term that has a positive coefficient. a) \((\quad)^{2}=n^{4}\) b) \(\quad(\quad )^{2}=25 t^{2}\) c) \(\quad(\quad)^{2}=49 k^{2}\) d) \(
View solution Problem 3
Factor by grouping. $$2 k^{2}+10 k+9 k+45$$
View solution Problem 3
If \(x^{2}+b x+c\) factors to \((x+m)(x+n)\) and if \(c\) is positive and \(b\) is negative, what do you know about the signs of \(m\) and \(n ?\)
View solution