Problem 3
Question
Sketch the graph of the Inequality. $$2 x+3 y \geq 2 y+1$$
Step-by-Step Solution
Verified Answer
Solid line \(2x + y = 1\) and shade above the line.
1Step 1: Simplify the Inequality
Start by simplifying the inequality \(2x + 3y \geq 2y + 1\). To do this, subtract \(2y\) from both sides to isolate terms involving \(y\) on the left side. This results in \(2x + 3y - 2y \geq 1\), which simplifies to \(2x + y \geq 1\).
2Step 2: Convert Inequality to Equation for Boundary Line
To sketch the graph of the inequality, first find the boundary line by converting the inequality to an equation. The boundary equation is \(2x + y = 1\). This line will help separate the plane into two regions.
3Step 3: Determine Intercepts of the Boundary Line
To sketch the line, determine the intercepts. Set \(x = 0\) to find the y-intercept: \(2(0) + y = 1\) gives \(y = 1\). Set \(y = 0\) to find the x-intercept: \(2x + 0 = 1\) gives \(x = \frac{1}{2}\). Thus, the intercepts are (0, 1) and \(\left(\frac{1}{2}, 0\right)\).
4Step 4: Sketch the Boundary Line
Plot the intercepts on a coordinate plane: (0, 1) and \(\left(\frac{1}{2}, 0\right)\). Draw a straight line through these points. The line represents the equation \(2x + y = 1\).
5Step 5: Determine the Region for the Inequality
Choose a test point not on the line, such as (0,0), and substitute it into the inequality \(2x + y \geq 1\). This gives \(2(0) + 0 \geq 1\), which is false. This means the region that does not include the origin satisfies the inequality. Shade the region above the line.
6Step 6: Finalize the Graph
Since the inequality is \(\geq\) (greater than or equal to), the boundary line is solid, indicating points on the line are also included in the solution. Thus, the final graph includes the solid line \(2x + y = 1\) and the shaded region above it.
Key Concepts
Linear EquationsCoordinate PlaneBoundary LineTest Points
Linear Equations
A linear equation is an equation that makes a straight line when it is graphed on a coordinate plane. In its most basic form, the equation is written as \(ax + by = c\), where variables \(x\) and \(y\) are raised to the first power. In this exercise, the boundary line we derived from the inequality is represented by the linear equation \(2x + y = 1\). This line divides the coordinate plane into two distinct regions.
- Key components: coefficients for \(x\) and \(y\), constant term
- Represents a straight line when graphed
Coordinate Plane
The coordinate plane is a two-dimensional space formed by a horizontal number line, called the x-axis, and a vertical number line, called the y-axis. These axes intersect at a point called the origin, denoted by (0,0).
To graph an inequality, we need to understand how to navigate this plane. We used it here to plot the boundary line for our inequality. Each point on the plane is defined by a pair of numbers (x, y), indicating its horizontal and vertical positions.
- X-axis: horizontal line
- Y-axis: vertical line
- Origin: point (0,0)
Boundary Line
In the context of graphing inequalities, a boundary line represents the critical line where an inequality switches from true to false (or vice versa). To understand in which region an inequality holds true, we convert the inequality to an equation to find the boundary line. For the given inequality, the boundary line is represented by \(2x + y = 1\). This line divides the plane into two regions.
- Solid line: \(\geq\) or \(\leq\), points on the line are included
- Dashed line: \(>\) or \(<\), points on the line are not included
Test Points
Using test points is a method to determine which region of the coordinate plane satisfies the inequality. After plotting the boundary line, we must identify which side of it is the solution to the inequality. A convenient test point is often (0,0), unless it lies on the boundary line itself. For the exercise, we used the test point (0,0) in the inequality \(2x + y \geq 1\). We found the inequality was not true for (0,0), meaning the solution region is on the opposite side of the boundary line from this point.
- Choose a point not on the line, like (0,0)
- Substitute into the inequality
- True: region includes the test point, False: region is opposite
Other exercises in this chapter
Problem 3
Exer. \(3-12:\) Find the inverse of the matrix if it exists. $$\left[\begin{array}{rr} 2 & -4 \\ 1 & 3 \end{array}\right]$$
View solution Problem 3
Solve the system. $$\left\\{\begin{array}{l} 2 x+5 y=16 \\ 3 x-7 y=24 \end{array}\right.$$
View solution Problem 3
Sketch the region \(R\) determined by the given constraints, and label its vertices. Find the maximum value of \(C\) on \(R\) $$\begin{array}{lll} C=3 x+y ; & x
View solution Problem 3
Use the method of substitution to solve the system. $$\left\\{\begin{aligned} y^{2} &=1-x \\ x+2 y &=1 \end{aligned}\right.$$
View solution