Problem 3
Question
Sketch the graph of each parabola by using only the vertex and the \(y\) -intercept. Check the graph using a calculator. \(y=x^{2}-6 x+5\)
Step-by-Step Solution
Verified Answer
Vertex: (3, -4); y-intercept: (0, 5); the parabola opens upwards.
1Step 1: Identify the Coefficients
The given quadratic equation is in the standard form \(y = ax^2 + bx + c\). Identify the coefficients: \(a=1\), \(b=-6\), and \(c=5\).
2Step 2: Find the Vertex
The x-coordinate of the vertex can be found using the formula \(x = -\frac{b}{2a}\). Substitute \(b = -6\) and \(a = 1\) into this formula: \(x = -\frac{-6}{2 \times 1} = 3\). To find the y-coordinate of the vertex, substitute \(x = 3\) back into the equation: \(y = (3)^2 - 6(3) + 5 = 9 - 18 + 5 = -4\). Therefore, the vertex is \((3, -4)\).
3Step 3: Find the y-intercept
The y-intercept occurs when \(x = 0\). Substitute \(x = 0\) into the equation: \(y = (0)^2 - 6(0) + 5 = 5\). Thus, the y-intercept is \((0, 5)\).
4Step 4: Sketch the Parabola
Plot the points for the vertex \((3, -4)\) and the y-intercept \((0, 5)\). Since the parabola opens upwards (as \(a = 1 > 0\)), sketch a smooth curve through these points that is symmetric around the vertical line \(x = 3\), which is the axis of symmetry.
5Step 5: Verify the Graph
Use a graphing calculator to input the equation \(y = x^2 - 6x + 5\) and compare the plotted graph with the sketch. Ensure the vertex and y-intercept match the calculated points.
Key Concepts
Quadratic equationsVertex of a parabolaY-interceptGraphing calculator
Quadratic equations
Quadratic equations are a type of polynomial equation with one variable raised to the second power. They are generally structured in the form \(y = ax^2 + bx + c\), where \(a\), \(b\), and \(c\) are constants, and \(x\) represents an unknown variable.
They form a parabola when graphed on a coordinate plane. The coefficient \(a\) determines the direction of the opening of the parabola:
They form a parabola when graphed on a coordinate plane. The coefficient \(a\) determines the direction of the opening of the parabola:
- If \(a > 0\), the parabola opens upward, creating a U-shape.
- If \(a < 0\), it opens downward, forming an upside-down U.
Vertex of a parabola
The vertex of a parabola is its highest or lowest point, depending on whether it opens upward or downward. It provides critical information about the parabola's minimum or maximum value.
To find the vertex, use the formula for the x-coordinate: \(x = -\frac{b}{2a}\). This formula simplifies the process by giving us the axis of symmetry. Once we have the x-coordinate, the y-coordinate can be determined by substituting this x-value back into the original equation.
For example, in the equation \(y = x^2 - 6x + 5\), we find:
To find the vertex, use the formula for the x-coordinate: \(x = -\frac{b}{2a}\). This formula simplifies the process by giving us the axis of symmetry. Once we have the x-coordinate, the y-coordinate can be determined by substituting this x-value back into the original equation.
For example, in the equation \(y = x^2 - 6x + 5\), we find:
- The x-coordinate of the vertex: \(x = -\frac{-6}{2 \times 1} = 3\).
- Substitute \(x = 3\) into the equation to find the y-coordinate, yielding \(y = -4\).
Y-intercept
The y-intercept is the point where the graph of an equation crosses the y-axis, which occurs when \(x = 0\). It is a key feature of the graph and provides a starting point for sketching.To find the y-intercept of a parabola, substitute \(x = 0\) into the quadratic equation. In our example of \(y = x^2 - 6x + 5\), we perform the calculation:
- \(y = (0)^2 - 6(0) + 5 = 5\)
Graphing calculator
A graphing calculator is a valuable tool for visualizing complex mathematical equations, especially in verifying and sketching graphs of quadratic equations.
To use a graphing calculator effectively, enter the quadratic equation exactly as it appears: \(y = x^2 - 6x + 5\). After inputting the function, the calculator will plot the corresponding parabola.
Check the displayed graph against the manually calculated vertex and y-intercept to ensure accuracy:
To use a graphing calculator effectively, enter the quadratic equation exactly as it appears: \(y = x^2 - 6x + 5\). After inputting the function, the calculator will plot the corresponding parabola.
Check the displayed graph against the manually calculated vertex and y-intercept to ensure accuracy:
- Verify that the vertex \((3, -4)\) is correctly plotted.
- Ensure the y-intercept \((0, 5)\) is marked correctly.
Other exercises in this chapter
Problem 3
Determine whether or not the given equations are quadratic. If the resulting form is quadratic, identify \(a, b,\) and \(c,\) with \(a>0 .\) Otherwise, explain
View solution Problem 3
Solve the given quadratic equations by finding appropriate square roots as in Example \(I\) $$x^{2}=25$$
View solution Problem 4
Sketch the graph of each parabola by using only the vertex and the \(y\) -intercept. Check the graph using a calculator. \(y=-x^{2}-4 x-3\)
View solution