Problem 3
Question
\(\sin \frac{2 \pi}{3}=\)________; \(\cos \frac{4 \pi}{3}=\) ________.
Step-by-Step Solution
Verified Answer
\(\sin \frac{2\pi}{3} = \frac{\sqrt{3}}{2}\); \(\cos \frac{4\pi}{3} = -\frac{1}{2}\).
1Step 1: Understanding the Unit Circle
The unit circle is a circle with a radius of 1 centered at the origin of the coordinate system. Angles measured in radians can help in identifying the values of sine and cosine for various standard positions on this circle.
2Step 2: Locate \(\frac{2\pi}{3}\) on the Unit Circle
\(\frac{2\pi}{3}\) radians is equivalent to \(120^\circ\). This angle is in the second quadrant, where the sine function is positive and the cosine function is negative.
3Step 3: Determine \(\frac{4\pi}{3}\) on the Unit Circle
\(\frac{4\pi}{3}\) radians is equivalent to \(240^\circ\). This angle is in the third quadrant, where both the sine and cosine functions are negative.
4Step 4: Calculate \(\frac{2\pi}{3}\)
In the second quadrant, \(\frac{2\pi}{3}\) has a reference angle of \(\pi/3\), for which the sine value is \(\sin \frac{\pi}{3} = \frac{\sqrt{3}}{2}\).
5Step 5: Calculate \(\frac{4\pi}{3}\)
In the third quadrant, \(\frac{4\pi}{3}\) has a reference angle of \(\pi/3\), for which the cosine value is \(\cos \frac{\pi}{3} = \frac{1}{2}\), but negative.
6Step 6: Apply the Sine and Cosine Rules for Quadrants
For \(\frac{2\pi}{3}\), \(\sin \frac{2\pi}{3} = \frac{\sqrt{3}}{2}\) because sine is positive in the second quadrant. For \(\frac{4\pi}{3}\), \(\cos \frac{4\pi}{3} = -\frac{1}{2}\) because cosine is negative in the third quadrant.
Key Concepts
Sine FunctionCosine FunctionReference AnglesQuadrants
Sine Function
The sine function, often written as \(\text{sin}(x)\), measures the y-coordinate of a point on the unit circle corresponding to an angle x. Imagine the unit circle with a radius of 1. As you move around the circle, the sine function varies between -1 and 1. When you locate an angle on the unit circle, drop a perpendicular line to the x-axis. The length of this line is the value of the sine function. For example, to find \(\text{sin}(\frac{2\pi}{3})\), you look at the y-coordinate of the point on the unit circle at this angle, which is \(\frac{\text{√3}}{2}\).
The sine function is:
The sine function is:
- Positive in Quadrants I and II
- Negative in Quadrants III and IV
Cosine Function
The cosine function, often represented as \( \text{cos}(x) \), measures the x-coordinate of a point on the unit circle corresponding to an angle x. Similar to the sine function, the cosine value varies between -1 and 1. When you measure an angle on the unit circle, drop a perpendicular line to the y-axis. The length of this line is the value of the cosine function. For instance, to find \( \text{cos}(\frac{4\text{π}}{3}) \), you look at the x-coordinate of the point on the unit circle at this angle, which is \(-\frac{1}{2}\).
The cosine function is:
The cosine function is:
- Positive in Quadrants I and IV
- Negative in Quadrants II and III
Reference Angles
Reference angles are the acute angles (less than 90 degrees) that a given angle makes with the x-axis. These angles help simplify calculations for sine and cosine. To find a reference angle, imagine the smallest angle between the terminal side of the angle and the x-axis. For example, the reference angle for \( \frac{2\text{π}}{3} \) is \( \frac{π}{3} \), because this angle lies in the second quadrant. To use a reference angle effectively:
- Identify the angle's quadrant
- Subtract the known angle from \( π \), \( 2π \), or \( \frac{3π}{2} \) based on its position
- Apply sine and cosine values for the reference angle
Quadrants
The unit circle is divided into four quadrants, each affecting the sign and value of the sine and cosine functions:
- Quadrant I: Angles from \( 0 \) to \( \frac{π}{2} \), both sine and cosine are positive.
- Quadrant II: Angles from \( \frac{π}{2} \) to \( π \), sine is positive and cosine is negative.
- Quadrant III: Angles from \( π \) to \( \frac{3π}{2} \), both sine and cosine are negative.
- Quadrant IV: Angles from \( \frac{3π}{2} \) to \( 2π \), sine is negative and cosine is positive.
Other exercises in this chapter
Problem 2
If \(\mathbf{v}=a_{1} \mathbf{i}+b_{1} \mathbf{j}\) and \(\mathbf{w}=a_{2} \mathbf{i}+b_{2} \mathbf{j}\) are two vectors, then the _______ ______is defined as \
View solution Problem 2
If \(\mathbf{v}\) is a vector, then \(\mathbf{v}+(-\mathbf{v})=\) _____
View solution Problem 3
A vector \(\mathbf{u}\) for which \(\|\mathbf{u}\|=1\) is called a(n) _____ vector.
View solution Problem 4
If \(\mathbf{v}=3 \mathbf{w},\) then the two vectors \(\mathbf{v}\) and \(\mathbf{w}\) are _________.
View solution