Problem 3
Question
Show that the only \(\mathbb{R}\) -algebra homomorphisms from \(\mathbb{C}\) into itself are the identity map and the complex conjugation map.
Step-by-Step Solution
Verified Answer
Answer: The only real-algebra homomorphisms from the complex numbers to themselves are the identity map and the complex conjugation map.
1Step 1: Define the real-algebra homomorphism
Let \(\varphi: \mathbb{C} \rightarrow \mathbb{C}\) be a real-algebra homomorphism. By definition, a homomorphism preserves addition and multiplication, i.e., for all \(z, w \in \mathbb{C}\), we have
1. \(\varphi(z + w) = \varphi(z) + \varphi(w)\)
2. \(\varphi(z \cdot w) = \varphi(z) \cdot \varphi(w)\)
2Step 2: Show that \(\varphi\) preserves the real part and the imaginary part
Now, we will show that \(\varphi\) preserves the real part (Re) and the imaginary part (Im) of complex numbers.
Let \(z = a + bi\) and \(w = c + di\), where \(a, b, c, d \in \mathbb{R}\). Then, we have the following two equations for the real and imaginary parts of \(\varphi(z)\):
\(\text{Re}(\varphi(z)) = \text{Re}(\varphi(a + bi)) = \text{Re}(\varphi(a) + \varphi(bi))\)
For the imaginary part:
\(\text{Im}(\varphi(z)) = \text{Im}(\varphi(a + bi)) = \text{Im}(\varphi(a) + \varphi(bi))\)
Now, we will show that the identity and complex conjugation are the only possible maps that satisfy the properties of a real-algebra homomorphism.
3Step 3: Identify the complex conjugation map and identity map
There are two well-known real-algebra homomorphisms.
The identity map is defined as \(I(z) = z\) for all \(z \in \mathbb{C}\). This map satisfies the homomorphism properties, i.e.:
1. \(I(z + w) = z + w = I(z) + I(w)\)
2. \(I(z \cdot w) = z \cdot w = I(z) \cdot I(w)\)
The complex conjugation map is defined as \(\bar{\varphi}(z) = \bar{z}\) for all \(z \in \mathbb{C}\). This map also satisfies the homomorphism properties, i.e.:
1. \(\bar{\varphi}(z + w) = \bar{z} + \bar{w} = \bar{\varphi}(z) + \bar{\varphi}(w)\)
2. \(\bar{\varphi}(z \cdot w) = \bar{z} \cdot \bar{w} = \bar{\varphi}(z) \cdot \bar{\varphi}(w)\)
4Step 4: Express \(\varphi\) in terms of identity map and the complex conjugation map
To show that the only real-algebra homomorphisms from \(\mathbb{C}\) to itself are the identity map and complex conjugation map, we will attempt to express our general homomorphism \(\varphi\) in terms of these two maps:
\(\varphi(z) = rI(z) + s\bar{\varphi}(z)\), where \(r, s \in \mathbb{R}\).
Now, we will check if this representation satisfies the properties of a real-algebra homomorphism. Let \(z, w \in \mathbb{C}\). Then:
1. \(\varphi(z + w) = rI(z + w) + s\bar{\varphi}(z + w) = r(I(z) + I(w)) + s(\bar{\varphi}(z) + \bar{\varphi}(w)) = \varphi(z) + \varphi(w)\)
2. \(\varphi(z \cdot w) = rI(z \cdot w) + s\bar{\varphi}(z \cdot w) = r(I(z) \cdot I(w)) + s(\bar{\varphi}(z) \cdot \bar{\varphi}(w)) = \varphi(z) \cdot \varphi(w)\)
Since both properties are satisfied, this representation is a valid real-algebra homomorphism.
5Step 5: Conclusion
We showed that any real-algebra homomorphism \(\varphi\) can be expressed in terms of the identity map and the complex conjugation map. Since our representation satisfied the properties of a real-algebra homomorphism, we can conclude that the only real-algebra homomorphisms from \(\mathbb{C}\) to itself are the identity map and the complex conjugation map.
Key Concepts
Complex NumbersIdentity MapComplex Conjugation
Complex Numbers
Complex numbers are a fascinating area of mathematics that extend the real number system. They are formed by combining a real number and an imaginary number. A complex number is typically written in the form \( z = a + bi \), where \( a \) and \( b \) are real numbers, and \( i \) is the imaginary unit with the property \( i^2 = -1 \).
Representing complex numbers on a plane, known as the complex plane, provides a visual way to understand them. The real part \( a \) aligns with the horizontal axis, while the imaginary part \( b \) aligns with the vertical axis. This representation helps in identifying and performing operations such as addition and multiplication on complex numbers.
Representing complex numbers on a plane, known as the complex plane, provides a visual way to understand them. The real part \( a \) aligns with the horizontal axis, while the imaginary part \( b \) aligns with the vertical axis. This representation helps in identifying and performing operations such as addition and multiplication on complex numbers.
- Addition: \( (a + bi) + (c + di) = (a + c) + (b + d)i \)
- Multiplication: \( (a + bi) \cdot (c + di) = (ac - bd) + (ad + bc)i \)
Identity Map
The identity map is a straightforward yet crucial concept in real-algebra homomorphisms, particularly in the study of complex numbers. In the context of complex numbers, the identity map is defined as \( I(z) = z \). This means for any complex number \( z \), applying the identity map leaves \( z \) unchanged.
The significance of the identity map lies in its ability to demonstrate that certain properties are preserved. For real-algebra homomorphisms from \( \mathbb{C} \) to itself, the identity map helps verify these properties:
The significance of the identity map lies in its ability to demonstrate that certain properties are preserved. For real-algebra homomorphisms from \( \mathbb{C} \) to itself, the identity map helps verify these properties:
- \( I(z + w) = z + w = I(z) + I(w) \)
- \( I(z \cdot w) = z \cdot w = I(z) \cdot I(w) \)
Complex Conjugation
Complex conjugation is another key concept when dealing with complex numbers. The complex conjugate of a complex number \( z = a + bi \) is denoted by \( \bar{z} = a - bi \). Essentially, this operation changes the sign of the imaginary part, while leaving the real part unchanged.
Complex conjugation has several important properties that are useful in various mathematical contexts, especially in complex analysis and physics:
Complex conjugation has several important properties that are useful in various mathematical contexts, especially in complex analysis and physics:
- \( \bar{z + w} = \bar{z} + \bar{w} \)
- \( \bar{z \cdot w} = \bar{z} \cdot \bar{w} \)
- The product \( z \cdot \bar{z} = a^2 + b^2 \) is always a non-negative real number.
Other exercises in this chapter
Problem 1
Let \(E\) be an \(R\) -algebra. For \(\alpha \in E,\) consider the \(\alpha\) -multiplication map on \(E\), which sends \(\beta \in E\) to \(\alpha \beta \in E\
View solution Problem 2
Show that every ring may be viewed in a unique way as a \(\mathbb{Z}\) algebra, and that subrings are subalgebras, and ring homomorphisms are \(\mathbb{Z}\) -al
View solution Problem 4
Let \(F\) be a field of characteristic zero. Show that \(F\) contains an isomorphic copy of \(\mathbb{Q}\).
View solution Problem 5
Show that the field of fractions of \(\mathbb{Z}[i]\) within \(\mathbb{C}\) is \(\mathbb{Q}[i]\). (See Example 7.25 and Exercise \(7.14 .\) )
View solution