Problem 3
Question
Offer an explanation for the following observations. a. Base-catalyzed exchange rates indicate that the hydrocarbon cubane is much more acidic than cyclobutane, and even more acidic than cyclopropane. b. Cyclopropyl phenyl ketone \((\mathrm{p} K=28.2)\) is less acidic than acetophenone ( \(\mathrm{p} K=24.7\) ) and undergoes \(\mathrm{C}-\mathrm{H}\) exchange more slowly than phenyl \(i\)-propyl ketone, despite the fact that its most acidic hydrogen is located on a cyclopropyl ring. c. The order of acidity for cyclopentadiene, indene, and fluorene in DMSO is indicated below. The gas phase acidity is in the opposite direction, as measured by the proton affinity. Why does the fusion of benzene rings decrease the solution acidity relative to cyclopentadiene? d. The rotational barrier of the allyl anion in THF, as measured by NMR, is dependent on the identity of the cation present.
Step-by-Step Solution
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Cubane vs Cyclobutane
One of the key consequences of this strain is increased acidity. The carbon-hydrogen (\(\text{C-H}\) ) bonds in cubane contain a greater percentage of \(s\)-character due to the strain and near \(\text{sp}\)-hybridization of the orbitals. This \(s\)-character makes the hydrogen atoms more acidic as they are held more tightly to the carbon nucleus.
On the other hand, cyclobutane has a less strained, square planar structure, with bond angles closer to \(109.5^{\circ}\) typical of sp\(^3\) hybridization, making the \(\text{C-H}\) bonds less acidic. In summary, the higher angle strain in cubane results in increased acidity compared to cyclobutane, and a greater acidity than cyclopropane due to a similar rationale.
Cyclopropyl Phenyl Ketone
In acetophenone, once deprotonation occurs to form the conjugate base, the negative charge can resonate through the aromatic phenyl ring. This efficient resonance greatly stabilizes the charge, hence why acetophenone is more acidic.
Conversely, the cyclopropyl phenyl ketone, although it possesses angle strain within the cyclopropyl ring, does not allow the conjugate base formed post-deprotonation to effectively resonate through the molecule. This lack of effective resonance stabilization leads to its lower acidity and slower \(\text{C-H}\) exchange compared to acetophenone.
Cyclopentadiene and Aromaticity
The fusion of benzene rings to form indene or fluorene adds additional \(\text{p}\)-orbitals that align along the macrocycle when deprotonated. This enlarged conjugated system results in less efficient electron delocalization, weakening the stability of the anion formed, thus effectively reducing acidity in solvents such as DMSO.
Therefore, while benzene fusion offers some delocalization, it does so less efficiently across the larger system, explaining why cyclopentadiene is more acidic in certain solvents, but exhibits the reverse trend in the gas phase.
Effect of Cations on Allyl Anion
This interaction either stabilizes or destabilizes the anion, subsequently affecting the rotational barrier. Cations that are good at interacting closely with the electron cloud will lower the energy barrier, allowing easier rotation.
Thus, the choice of cation dramatically alters the dynamics observed in the allyl anion, which is visible through techniques such as NMR, highlighting important intermolecular forces at play in these systems.